Download presentation
Presentation is loading. Please wait.
Published byArabella Watkins Modified over 8 years ago
1
Fri 10/23 Lesson Rev Learning Objective: To remember everything learned in Chapter 3! Hw: Chapter 3 Review WS 1
2
Mon 10/26 Lesson Rev Learning Objective: To remember everything learned in Chapter 3! Hw: Chapter 3 Review WS 2
3
Tues 10/27 Lesson Rev Learning Objective: To remember everything learned in Chapter 3! Hw: Chapter 3 Review WS 3
4
Tues 10/27 Lesson Rev Learning Objective: To remember everything learned in Chapter 3! Hw: Quiz Correction
5
Algebra II
6
To remember everything in Chapter 3!
7
1. –4 = 4y – 2x – 2y = –x + 12
8
No Solution Lines are Parallel & will NEVER cross!
9
2. –9y – 2x = 81 9y = –2x - 81
10
Infinite Solutions SAME line will ALWAYS touch
11
(1, – 7)
12
No Overlap No Solution! No Shading!!! NO SOLUTION
14
4x + y = 2 -4x y = -4x + 2 - 7x + 3(-4x +2) = -13 - 7x – 12x +6 = -13 -19x = -19 x = 1 4(1) + y = 2 4 + y = 2 y = - 2 (1, -2)
15
Same Line! 0 = 0 Infinite Solutions (-2)( ) (-2)
16
7(0) + 5y = –5 5y = – 5 y = –1 43x = 0 x = 0 (0, -1) (4)( ) (4) (-5)( ) (-5)
17
4x + 3y + 5z = 10 x + 6y – 5z = 14 5x + 9y = 24 x + 6y – 5z = 14 –6x – 2y + 5z = –25 –5x + 4y = –11
18
13y = 13 y = 1 (3, 1, -1) 5x + 9(1) = 24 5x + 9 = 24 5x = 15 x = 3 3 + 6(1) – 5z = 14 3 + 6 – 5z = 14 9 – 5z = 14 –5z = 5z = –1
19
5(-1) + 3z = -8 -5 + 3z = -8 3z = -3 z = -1 2x + (-1) + 3(-1) = 4 2x – 1 – 3 = 4 2x – 4 = 4 2x = 8x = 4 (4, -1, -1)
20
11. Find the value of two numbers if their sum is 22 and their difference is 6 x + y = 22 x – y = 6 2x = 28 x = 14 14 + y = 22 y = 8 {8, 14}
21
12. On the first day of choir ticket sales, 6 adults and 7 student ticket sold for a total of $154. Choir took in $302 on the second day be selling 13 adult tickets and 12 student tickets. Find the price of an adult and a student ticket. 6x + 7y = 154 13x + 12y = 302 (-12)( ) (-12) -72x - 84y =-1848 91x + 84y = 2114 19x = 266 x = 14 6(14) + 7y = 154 84 + 7y = 154 7y = 70 y = 10 $14 for adult tix $10 for student tix (7)( ) (7)
22
13. A stadium has 49,000 seats. Section A seats are $25, Section B seats are $20, and Section C seats are $15. The number of seats in Section A equals the total number of seats in Section B and C. Suppose the stadium takes in $1,052,000 from each sold out event, how may seats does each section hold? x + y + z = 49000 25x + 20y + 15z = 1052000 x = y + z
23
x + y + z = 49000 x – y – z = 0 2x = 49000 x = 24,500 20x – 20y – 20z = 0 25x + 20y + 15z = 1052000 45x – 5z = 1052000 (20)
24
13. 45(24500) – 5z = 1052000 1102500 – 5z = 1052000 -5z = -50500 z = 10,100 24500 + y + 10100 = 49000 34600 + y = 49000 y = 14,400 Section A: 24,500 Section B: 14,400 Section C: 10,100
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.