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Published byDwayne Hill Modified over 8 years ago
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Thermodynamics II Thermodynamics II
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THTH TCTC QHQH QCQC W HEAT ENGINE THTH TCTC QHQH QCQC W REFRIGERATOR system l system taken in closed cycle U system = 0 l therefore, net heat absorbed = work done Q H - Q C = W (engine) Q C - Q H = -W (refrigerator) energy into green blob = energy leaving green blob Engines and Refrigerators 11
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THTH TCTC QHQH QCQC W HEAT ENGINE The objective: turn heat from hot reservoir into work The cost: “waste heat” 1st Law: Q H -Q C = W efficiency e W/Q H =W/Q H = (Q H -Q C )/Q H = 1-Q C /Q H Heat Engine: Efficiency 13
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THTH TCTC QHQH QCQC W REFRIGERATOR The objective: remove heat from cold reservoir The cost: work 1st Law: Q H = W + Q C coeff of performance K r Q C /W = Q C /W = Q C /(Q H - Q C ) Refrigerator: Coefficient of Performance 22
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Carnot Cycle l Idealized Heat Engine è No Friction S = Q/T = 0 è Reversible Process »Isothermal Expansion »Adiabatic Expansion »Isothermal Compression »Adiabatic Compression 32
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THTH TCTC QHQH QCQC W HEAT ENGINE The objective: turn heat from hot reservoir into work The cost: “waste heat” 1st Law: Q H -Q C = W efficiency e W/Q H =W/Q H = 1-Q C /Q H S = Q C /T C - Q H /T H 0 S = 0 for Carnot Therefore, Q C /Q H T C / T H Q C /Q H = T C / T H for Carnot Therefore e = 1 - Q C /Q H 1 - T C / T H e = 1 - T C / T H for Carnot e = 1 is forbidden! e largest if T C << T H Engines and the 2nd Law 36
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Summary l First Law of thermodynamics: Energy Conservation Q = U + W l Heat Engines è Efficiency = = 1-Q C /Q H l Refrigerators è Coefficient of Performance = Q C /(Q H - Q C ) Entropy S = Q/T l 2 nd Law: Entropy always increases! l Carnot Cycle: Reversible, Maximum Efficiency e = 1 – T c /T h 50
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