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The wave equation LL2 Section 46. In vacuum,  = 0 and j = 0. These have non-trivial solutions. Thus, electromagnetic fields can exist without charges.

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Presentation on theme: "The wave equation LL2 Section 46. In vacuum,  = 0 and j = 0. These have non-trivial solutions. Thus, electromagnetic fields can exist without charges."— Presentation transcript:

1 The wave equation LL2 Section 46

2 In vacuum,  = 0 and j = 0. These have non-trivial solutions. Thus, electromagnetic fields can exist without charges.

3 Such electromagnetic fields must be time-varying Suppose instead Then These constant-field equations, without charge or current, have only a trivial solution

4 The potentials  and A are not unique. They are subject to auxiliary conditions. First condition  = 0.

5 A is still not unique, where f is time independent The transform does not change E or H. Second condition (Coulomb Gauge): div A = 0. Shows that div A is a function only of coordinates. Thus, we can always make div A = 0 by transform where df/dt =0. d’Alembert equation Wave equation

6 d’Alembertian operator E and H obey the same equation (Apply operators curl or d/dt to the equation for A.)

7 4D derivation

8 Ai is not unique. Impose an additional condition. Lorentz condition Lorentz gauge More general than Potentials that satisfy Coulomb gauge also satisfy Lorentz gauge, But not vice versa. 4D divergence

9 With the wave equation becomes or

10 Lorentz condition is a scalar, so has relativistic invariance. If  and A satisfy it in one inertial frame, They do in all inertial frames. Such ( , A) is still not unique. We can add


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