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Published byAmi Baldwin Modified over 8 years ago
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EXAMPLE 1 Solve a triangle for the AAS or ASA case Solve ABC with C = 107°, B = 25°, and b = 15. SOLUTION First find the angle: A = 180° – 107° – 25° = 48°. By the law of sines, you can write a sin 48° sin 107° c = 15 sin 25° = Write two equations, each with one variable. a sin 48° 15 sin 25° = sin 107° c 15 sin 25° =
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EXAMPLE 1 Solve a triangle for the AAS or ASA case Solve for each variable. a = 15 sin 48° sin 25° c = 15 sin 107° sin 25° Use a calculator. a26.4c33.9 In ABC, A = 48°, a 26.4, and c 33.9. ANSWER
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GUIDED PRACTICE for Example 1 Solve ABC. 1. B = 34°, C = 100°, b = 8 SOLUTION By the law of sines, you can write a sin 46° sin 100° c = 8 sin 34° = Write two equations, each with one variable. a sin 46° 8 sin 34° = sin 100° c 8 sin 34° = First find the angle: A = 180° – 34° – 100° = 46°.
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GUIDED PRACTICE for Example 1 Solve for each variable. Use a calculator. a10.3c14.1 In ABC, A 46°, a 10.3, and c 14.1. ANSWER c 8 sin 100° sin 34° = a 8 sin 46° sin 34° =
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GUIDED PRACTICE for Example 1 2. A = 51°, B = 44°, c = 11 Solve ABC. SOLUTION By the law of sines, you can write a sin 51° sin 85° 11 = b sin 44° = Write two equations, each with one variable. a sin 51° 11 sin 85° = sin 44° b 11 sin 85° = First find the angle: C = 180° – 51° – 44° = 85°.
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GUIDED PRACTICE for Example 1 Solve for each variable. Use a calculator. a8.6b7.7 In ABC, A 85°, a 8.6, and b 7.7. ANSWER ab 11 sin 44° sin 85° = 11 sin 51° sin 85° =
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