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1 Measures MENU Perimeter Main MENU Area of rectangle Area of rectangle questions Area of compound rectangles Area of comp rects questions Areas of borders.

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Presentation on theme: "1 Measures MENU Perimeter Main MENU Area of rectangle Area of rectangle questions Area of compound rectangles Area of comp rects questions Areas of borders."— Presentation transcript:

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2 1 Measures MENU Perimeter Main MENU Area of rectangle Area of rectangle questions Area of compound rectangles Area of comp rects questions Areas of borders Areas of borders questions Area of a triangle - Practical Area of a triangle - questions Area of compound triangles Area of comp triangles questions Volume of a Cuboid questions Surface Area of a Cuboid Surface Area of a Cuboid questions Volume of a Triangular Prism Vol of a Triangular Prism questions Surface Area of Triangular Prisms Surface Area of Prism questions Volume of Rectilinear solids Vol of Rect solids questions Area of a Circle questions Areas of circle shapes Areas of circle shapes questions Area of an Anulus questions Area of Circles 10 quickfire Area of Triangles 10 quickfire Area of Rectangles 10 quickfire Vol of Cuboid 10 quickfire Finding π Calculating circumference Circumference questions Compound Circles questions Circumference of Circles10 quickfire Teacher’s notes on quickfire Arcs & Sectors questions

3 2 Menu

4 3 12 m 7 m What do we mean by Perimeter ? It is how far you would walk in order to go around the outside ! Menu

5 4 12 m 7 m How many ways are there to work out the Perimeter ? 12 m 7 m 12 + 7 + 12 + 7 = 38 m (2 x 12) + (2 x 7) = 38 m 12 + 12 + 7 + 7 = 38 m 2 (12 + 7) = 38 m Generalise Menu

6 5 Use any method you like ! Menu

7 6 14 cm 10 cm 6 m 40 cm 70 cm 1.5 m 2.5 m 200 cm 120 cm 80 cm 50 cm 1) 2) 3) 4) 5) 6) 48 cm 24 m 640 cm 220 cm 8 m 260 cm Menu Answers

8 7 8 cm 4 cm 9 cm 5 m 8 cm 10 cm 9 cm 11 cm 12 cm 9 cm 1 1 1 1 1 1 1 1 30 cm 30 m 24 cm 51 cm 50 cm 1)2)3) 4) 5) Menu Answers

9 8 12 + 7 + 12 + 7 12 + 12 + 7 + 7 (2 x 12) + (2 x 7) 2 (12 + 7) 12 m 7 m 12 m 7 m L L W W L + W + L + W L + L + W + W ( 2 x L ) + ( 2 x W ) 2 ( L + W ) The Expressions are all the same ! Menu

10 9

11 10 What is meant by the Area of this rectangle ? √√√√√√ √√√√√√ √√√√√√ 18 squares There must be a quicker way of doing it ? 6 3 6 x 3 = 18 What about the UNITS ? The number of squares that fit inside the shape. cm cm 2 Area of a Rectangle = Length x Width Menu

12 11 Work out the Areas of the following rectangles. Remember to state the UNITS ! 8 m 3 m 7 cm 11 cm 3 km 5 km 8 mm 6 mm 12 m 10 m 24 m 2 77 cm 2 15 km 2 48 mm 2 120 m 2 1) 2) 3) 4) 5) Menu Answers

13 12 14 cm 10 cm 6 m 40 cm 70 cm 1.5 m 2.5 m 200 cm 120 cm 80 cm 50 cm 1) 2) 3) 4) 5) 6) 36 m 2 2800 cm 2 3.75 m 2 24000 cm 2 140 cm 2 4000 cm 2 Menu Answers

14 13 Menu

15 14 How can I work out the Area of this shape ? I could count the squares ! √√ √√ √√ √√ √√ √√√√ 14 m 2 4 m 2 m Menu

16 15 Oh no ! This one isn’t split into squares ! 6 m 5 m 8 m 2 m I could split it into individual rectangles ! 3 m 6 x 3 = 18 m 2 8 x 2 = 16 m 2 Total Area = 18 + 16 = 34 m 2 Menu

17 16 6 m 5 m 8 m 2 m I could have split it up differently ! 6 x 5 = 30 m 2 2 m 2 x 2 = 4 m 2 Total Area is still 30 + 4 = 34 m 2 Menu

18 17 8 cm 10 cm 4 cm 7 cm 5 cm 6 cm 2 cm 5 x 2 = 10 cm 2 4 cm 7 x 4 = 28 cm 2 4 cm 4 x 4 = 16 cm 2 Total Area 10 + 28 + 16 = 54 cm 2 Menu

19 18 Work out the following Areas ( Copy the diagrams and show all working out. ) Remember to state your UNITS ! ( Diagrams NOT drawn to scale ! ) 7 m 8 m 3 m 4 m 9 cm 4 cm 7 cm 6 cm 6 mm 10 mm 3 mm 1 mm 7 mm 8 mm 4 mm 7 m 2 m 10 m 4 m 3 m 54 cm 2 44 m 2 82 m 2 62 mm 2 1) 2) 3) 4) Menu Answers

20 19 Menu

21 20 I could just count the squares.               26 squares 9 m 26 m 2 Menu

22 21 10 m 5 m I can’t count the squares ! It is just a big rectangle with a small rectangle taken away ! 8 m 3 m Area of big rectangle = 10 x 5 = 50 m 2 Area of small rectangle (water) = 8 x 3 = 24 m 2 Area of path = 50 – 24 = 26 m 2 Menu

23 22 Work out the Areas of the following paths. (Sketch the diagrams) 7 m 4 m 9 m 11 m 20 m 8 m 5 m 1 m 2 m 3 m 6 m 3 m 1) 2) 3) 23 m 2 154 m 2 81 m 2 Menu Answers

24 23 Teacher’s Notes on Area of a Triangle (Practical) Pupils should be given a piece of paper (preferably coloured gummed paper). 1)Draw around the ‘gummed paper’ and onto a page in their books so that they have a piece of ‘gummed paper’ and its outline in their books. 2)Draw a line across the middle of the outline. 3)Mark a point anywhere along the top edge of the gummed paper and join the mark to the bottom as shown in the powerpoint. 3)Cut out the triangle. 4)Cut up the triangle and rearrange it so that it fits over half of the outlined rectangle. This demonstrates that the area of the triangle is half of the area of the square / rectangle that it came from. Menu Practical

25 24 Menu Teacher Notes

26 25 Gummed PaperIn Books The Area of the Triangle is equal to a half of the Area of the Rectangle. Menu

27 26 The Area of a Triangle = 1 x BASE x Perpendicular HEIGHT Cut-out In Books Length Width Length The Area of the Triangle = Half of the Area of the Rectangle The Area of the Triangle = 1 of Length x Width 2 BASE HEIGHT 2 Perpendicular Height Menu

28 27 10 cm 7 cm 5 cm 8 cm 7 cm 5 cm Area of Triangle = 1 of Base x Height 2 OR Area of Triangle = 1 of Height x Base 2 OR Area of Triangle = Base x Height 2 1 of 10 x 7 2 = 5 x 7 = 35 cm 2 1 of 8 x 5 2 = 4 x 5 = 20 cm 2 7 x 5 2 = 35 2 = 17.5 cm 2 Menu

29 28 Calculate the Areas of the Following Triangles. ( Show all of your working out ). ( All lengths in cm) 8 6 4 10 4 12 5 14 3 8 7 5 16 5 4 9 20 26 1)2)3) 4)5)6) 7) 8) 9) 24 cm 2 20 cm 2 24 cm 2 35 cm 2 12 cm 2 17.5 cm 2 40 cm 2 18 cm 2 260 cm 2 Menu Answers

30 29 8 cm 6 cm 10 cm 12 cm Area = ½ the BASE X HEIGHT = ½ of 8 x 6 = 24 cm 2 Menu

31 30 7 cm 3 cm 4 cm 6 cm Area = ½ the BASE X HEIGHT = 3 x 7 2 = 21 2 = 10.5 cm 2 Menu

32 31 Calculate the Areas of the Following Triangles. ( Show all of your working out ). ( All lengths in cm) 14 8 10 9 6 12 8 10 5 12 9 5 80 30 11 10 16 10 14 9 9095 40 cm 2 36 cm 2 30 cm 2 54 cm 2 22.5 cm 2 1200 cm 2 1) 2) 3) 4)5) 6) 14 Menu Answers

33 32 Menu

34 33 10 m 4 m 7 m I could split it into a triangle and a rectangle ! 10 x 4 = 40 m 2 ½ of 10 x 3 = 15 m 2 3 m Total Area = 40 + 15 = 55 m 2 Menu

35 34 6 m 4 m 3 m 6 x 4 = 24 m 2 2 m ½ of 2 x 3 = 3 m 2 Total Area = 24 + 3 = 27 m 2 Menu

36 35 8 m6 m 3 m 5 m 4 m 8 x 5 = 40 m 2 ½ of 8 x 3 = 12 m 2 ½ of 6 x 5 = 15 m 2 ½ of 8 x 4 = 16 m 2 Total Area = 40 + 12 + 15 + 16 = 83 m 2 Menu

37 36 Sketch the following shapes and work out their Areas. (Don’t forget to state your units !) 6 m 8 m 10 cm 2 cm 4 cm 8 m 7 m2 m 10 m12 mm 10 mm 7 mm 1) 2) 3)4) 42 m 2 24 cm 2 61 m 2 102 mm 2 Menu Answers

38 37 Menu

39 38 Volume is the amount of space inside the shape. 4 cm 2 cm 3 cm It is the number of 1 cm cubes that would fit into the cuboid. 1 cm 24 cm 3 Why not use the formula Volume = Length x Width x Height Length Height Width It doesn’t matter which sides are which ! 2 x 4 x 3 = 24 4 x 2 x 3 = 24 3 x 4 x 2 = 24 etc.., Simply multiply the three measurements together. What is meant by Volume ? How is it measured ? Menu

40 39 It simply doesn’t matter how you do the multiplying ! 4 4 3 × 3 12 2 × 2 = 24 cm 3 4 4 2 × 2 8 × 3 = 24 cm 3 3 3 2 3× 2 6 4 × 4 = 24 cm 3 Menu

41 40 So what are the volumes of these cuboids ? 6 cm 3 cm 2 cm 6 x 3 x 2 = 36 cm 3 3 x 2 x 6 = 36 cm 3 2 x 6 x 3 = 36 cm 3 3 m 5 m 1 m 5 x 3 x 1 = 15 m 3 1 x 5 x 3 = 15 m 3 3 x 5 x 1 = 15 m 3 Menu

42 41 Work out the Volumes of the following : ( Remember to state your UNITS ! ) 4 m 2 m 5 m 2 cm 3 cm 7 cm 5 mm 6 cm 5 cm 4 cm 20 m 6 m 2 m 1)2) 3) 4) 5) 40 m 3 42 cm 3 120 cm 3 240 m 3 125 mm 3 Menu Answers

43 42 Work out the missing lengths. 6 m 2 m x Volume = 36 m 3 4 cm x Volume = 160 cm 3 20 m x x Volume = 500 m 3 x x x Volume = 64 mm 3 1)2) 3) 4) 3 m 10 cm 5 m 4 mm Menu Answers

44 43 Menu

45 44 4 cm 2 cm 5 cm Surface Area is the total Area of all of the surfaces that you can touch. 5 x 4 = 20 cm 2 There is another one the same around the back ! x 2 = 40 cm 2 5 x 2 = 10 cm 2 There is another one on the bottom ! x 2 = 20 cm 2 4 x 2 = 8 cm 2 There is another one on this end ! x 2 = 16 cm 2 Total Surface Area 40 + 20 + 16 = 76 cm 2 Menu

46 45 Work out the Surface Areas. Don’t forget to state your UNITS ! 4 m 2 m 3 m 1 cm 7 cm 20 mm 10 mm 15 mm 4 m 1) 2) 3) 4) 52 m 2 30 cm 2 1300 mm 2 96 m 2 Menu Answers

47 46 It is a CUBE ! Its Surface Area = 150 cm 2 How tall is it ? x 5 cm Menu

48 47 Work out the missing length x x x x x 4 m 3 m x x 10 cm x x 3x S.A.= 294 cm 2 S.A. = 136 m 2 S.A. = 138 cm 2 S.A. = 504 m 2 1) 2) 3) 4) 7 cm 8 m 3 cm 6 m Menu Answers

49 48 Menu

50 49 Area of a Triangle = ½ Base x Perpendicular Height 4 cm 3 cm 7 cm Work out the Area of the end and then multiply by the length. ½ of 4 x 3 = 6 cm 2 Volume = 6 x 7 = 42 cm 3 Menu

51 50 Work out the Volumes of the following Prisms. Remember to state your UNITS ! 1) 2) 8 cm 6 cm 10 cm 7 cm 5 m 12 m 13 m 10 m 168 cm 3 300 m 3 Menu Answers

52 51 Menu

53 52 4 cm 3 cm 7 cm ½ of 4 x 3 = 6 cm 2 But there are two of these panels ! 12 5 cm 7 x 5 = 35 cm 2 What about the bottom panel ? + 35 7 x 4 = 28 cm 2 + 28 What about the rear panel ? 3 x 7 = 21 cm 2 + 21 Total Surface Area = 96 cm 2 Menu

54 53 Work out the Surface Areas of the following Prisms. Remember to state your UNITS ! 1) 2) 8 cm 6 cm 10 cm 7 cm 5 m 12 m 13 m 10 m 216 cm 2 360 m 2 Menu Answers

55 54 Menu

56 55 Think Volume think cheese ! Menu

57 56 Can you completel y cut up the cheese and have all the same size and shaped slices ? This is called the Constant Cross- sectional Area. Menu

58 57 Can you completel y cut up the cheese and have all the same size and shaped slices ? Menu

59 58 To work out the Volume you first work out the Constant Cross- sectional Area (Area of the cheese slice ) and then multiply by the length / height ( how far the knife travelled ). 8 cm 6 cm 10 cm Area of a triangle = ½ base x height 3 x 8 = 24 cm 2 Volume = 24 x 10 = 240 cm 3 8 cm 9 cm Area of a Circle = π r 2 3.14 x 4 2 = 50.24 cm 2 Volume = 50.24 x 9 = 452.16 cm 3 Menu

60 59 Work out the Volumes of the following shapes. Show all of your working out. Don’t forget to state your UNITS ! Rubber hose pipe. Volume of rubber = ? 4 m 6 m 5 m 6 cm 4 cm 30 m 10 m 5 m 4 m 20 m 2 cm 3 cm 6 m 10 m 8 m 1) 2) 3) 4) 5) c.s.a = 2 x 6 = 12 m 2 V = 12 x 5 = 60 m 3 c.s.a = 3.14 x 2 2 = 12.56 cm 2 V = 12.56 x 6 = 75.36 cm 3 c.s.a = (5 x 10) + ½ of 10 x 4 = 70 m 2 V = 70 X 30 = 2100 m 3 c.s.a = 6 + 10 2 () x 8 = 64 m 2 V = 64 x 10 10 m = 640 m 3 c.s.a = 3.14 x 1.5 2 – 3.14 x 1 2 = 3.925 cm 2 V = 3.925 x 2000 = 7850 cm 3 Menu Answers

61 60 Menu

62 61

63 62 Radius Diameter Menu

64 63 3 m Area = π r 2 A = 3.142 X 3 X 3 A = 28.278 m 2 5 m A = 3.142 X 5 2 A = 3.142 X 25 A = 78.55 m 2 Menu

65 64 Calculate the Areas of the following circles. Give answers to 2 decimal places. ( Take π = 3.142 ) 1)2) 3) 4)5)6) 4 cm 6 m 10 mm 7 cm 2 m 8 cm 50.27 cm 2 113.11 m 2 314.2 mm 2 153.96 cm 2 12.57 m 2 201.09 cm 2 Menu Answers

66 65 8 m A = π r 2 4 m A = 3.142 X 4 X 4 A = 50.27 m 2 10 m A = π r 2 5 m A = 3.142 X 5 2 A = 78.55 m 2 Menu

67 66 Calculate the Areas of the following circles. Give answers to 2 decimal places. ( Take π = 3.142 ) 1)2) 3) 4)5)6) 16 cm 34 m 50m 13 cm 42 m 15 cm 201.09 cm 2 908.04 m 2 1963.75 m 2 132.75 cm 2 1385.62 m 2 176.74 cm 2 Menu Answers

68 67 Calculate the Areas of the following circles. Give answers to 2 decimal places. ( Take π = 3.142 ) 1)2) 3) 4)5)6) 32 cm 53 m 7.5 mm 26 cm 22 m 38 cm 3217.41 cm 2 2206.47 m 2 44.18 mm 2 2123.99 cm 2 1520.73 m 2 1134.26 cm 2 Menu Answers

69 68 Menu

70 69 There is no formula for this ! 10 m I could treat it as a whole circle and then halve my answer ! 5 m A = π X 5 2 A = 78.55 Area of blue Semi-Circle = 78.55 2 = 39.28 m 2 Area of a whole circle = π r 2 Menu

71 70 Area of a whole circle = π r 2 It is ¼ of a whole circle ! 4 m A = π X 4 2 A = π X 16 A = 50.27 Area of the quarter circle = 50.27 4 = 12.57 m 2 Area of a whole circle = π r 2 Area of a whole circle = π r 2 Menu

72 71 Area of a whole circle = π r 2 3 cm This is ¾ of a whole circle ! A = π x 3 2 A = π x 9 A = 28.28 Area of green shape = 28.27 x 3 4 = 21.2 cm 2 Menu

73 72 Area of a whole circle = π r 2 It is made out of 3 circles ! 20 m Area of big semi-circle = π x 10 2 2 10 m = 157.1 m 2 5 m Area of a small semi-circle = π x 5 2 2 = 39.28 m 2 But there are 2 of them ! X 2 = 78.55 m 2 Green Area = 157.1 – 78.55 = 78.55 m 2 Menu

74 73 Try and work these Areas out. Give answers to 2 decimal places. Let π = 3.142 8 m 10 m 6 m 12 m 20 m 30 m 1) 2) 3) 4) 89.14 m 2 88.28 m 2 457.1 m 2 257.11 m 2 Menu Answers

75 74 Menu

76 75 It looks like a washer. It is a big circle with a little circle taken away 4 cm 6 cm Area of Big circle = π x 6 2 = 113.11 Area of Small circle = π x 4 2 = 50.27 Area of yellow anulus = 113.11 – 50.27 = 62.84 cm 2 Menu

77 76 What about a formula ? R r Area of yellow anulus = Area of big circle – Area of small circle = π R 2 – π r 2 = π ( R 2 – r 2 ) I can factorise it ! Menu

78 77 Work out the areas of the coloured paths. Give answers to 2 decimal places. Take π = 3.142 6 m 10 m 20 m 3 m 201.09 m 2 160.24 m 2 1) 2) Menu Answers

79 78 Menu

80 79. Area of a Circle = πr 2 Circumference of a Circle = πD Minor Sector Major Sector 120° Area of a Sector 6 cm What FRACTION of the circle is taken up by the Minor Sector ? 120 360 π r 2 = 120 × π × 6 2 360 = 37.7 cm 2 Length of an Arc Minor Arc Major Arc 120 360 π D = 120 × π × 12 360 = 12.6 cm Menu

81 80 Work out the following Areas and their Arc lengths ( Show all of your working out ) 1)2) 3) 4) 100°40° 205° 330° 8 cm 5 cm 10 cm 0.5 cm 55.9cm 2 & 14.0 cm 8.7cm 2 & 3.5 cm 178.9cm 2 & 35.8 cm 0.7cm 2 & 2.9 cm Menu Answers

82 81 Teacher’s Notes on quickfire questions Quickfire questions are designed as a straight forward starter where pupils quickly work out the answers (possibly in the backs of their books). The teacher should then review each question giving out the answers and reminding pupils of the techniques / ideas behind the topic. Menu

83 82 Menu

84 83 Question 1 6 cm 4 cm Menu

85 84 Question 2 8 cm 5 cm Menu

86 85 Question 3 4 cm 1 cm Menu

87 86 Question 4 10 cm 7 cm Menu

88 87 Question 5 9 cm 3 cm Menu

89 88 Question 6 8 cm 4 cm Menu

90 89 Question 7 11 cm 8 cm Menu

91 90 Question 8 12 cm 3 cm Menu

92 91 Question 9 6 cm 5 cm Menu

93 92 Question 10 7 cm Menu

94 93 Menu

95 94 Question 1 8 m 6 m Menu

96 95 Question 2 10 m 12 m Menu

97 96 Question 3 7 m 8 m Menu

98 97 Question 4 9 m 5 m Menu

99 98 Question 5 4 m 1 m Menu

100 99 Question 6 14 m 12 m Menu

101 100 Question 7 8 m 12 m 11 m 10 m Menu

102 101 Question 8 5 m 16 m 12 m 11 m Menu

103 102 Question 9 7 m 8 m 11 m Menu

104 103 Question 10 7 m 12 m 13 m 14 m Menu

105 104 Menu

106 105 Question 1 Let π = 3 2 cm Menu

107 106 Question 2 Let π = 3 5 cm Menu

108 107 Question 3 Let π = 3 10 cm Menu

109 108 Question 4 Let π = 3 1 cm Menu

110 109 Question 5 Let π = 3 8 cm Menu

111 110 Question 6 Let π = 3 16 cm Menu

112 111 Question 7 Let π = 3 6 cm Menu

113 112 Question 8 Let π = 3 6 cm Menu

114 113 Question 9 Let π = 3 200 cm Menu

115 114 Question 10 Let π = 3 0.5 m Menu

116 115 Menu

117 116 Question 1 5 cm 3 cm 2 cm Menu

118 117 Question 2 4 m 2 m 1 m Menu

119 118 Question 3 9 mm 1 mm Menu

120 119 Question 4 8 cm 2 cm 3 cm Menu

121 120 Question 5 11 m 3 m 2 m Menu

122 121 Question 6 7 cm 5 cm 2 cm Menu

123 122 Question 7 3 mm 20 mm Menu

124 123 Question 8 10 m 4 m 3 m Menu

125 124 Question 9 20 mm 10 mm 5 mm Menu

126 125 Question 10 30 m 20 m 10 m Menu

127 126 Teacher’s Notes on finding π: Each pupil needs a piece of string to wrap around each circle in order to be able to measure their circumferences. The target is that pupils notice that in each case the circumference is just over 3 times the diameter. Menu

128 127 Menu

129 128 Radius Diameter c i r c u m f e r e n c e We are going to try to find the connection between the diameter and the circumference. Menu

130 129 Draw 5 different sized circles. Use a ruler to measure their diameters. Wrap string around their circumferences, unravel the string and place on a ruler. Record your figures in the table below. Circle Number Circumference C Diameter D CDCD 1 2 3 4 5 1) 2) 3) 4) 5) In the fourth column divide the circumference by the diameter. How big is the circumference compared to the diameter ? Menu

131 130 In each case the circumference is just a little bit more than 3 times the diameter. In fact it is 3.142 times as big ! This is such a special number that it is even given its own symbol which is the Greek letter Pi. π = 3.142 Menu

132 131 Circumference = 3.142 × Diameter C = 3.142 × D or C = π D You will need to memorise this formula ! Menu

133 132 8 m 10 m C = π D C = 3.142 X 8 C = 25.136 m C = π D C = 3.142 X 10 C = 31.42 m Menu

134 133 Calculate the Circumferences of the following circles. Give answers to 2 decimal places. ( Take π = 3.142 ) 1)2) 3) 4)5)6) 16 cm 34 m 50m 13 cm 42 m 15 cm 106.83 m 157.10 m 40.85 cm 131.96 m 47.13 cm 50.27 cm Menu Answers

135 134 3 m 5 m C = π D C = 3.142 × 6 C = 18.852 m C = π D C = 3.142 × 10 C = 31.42 m Menu

136 135 Calculate the Circumferences of the following circles. Give answers to 2 decimal places. ( Take π = 3.142 ) 1)2) 3) 4)5)6) 4 cm 6 m 10 mm 7 cm 2 m 8 cm 25.14 cm 37.70 m 62.84 mm 43.99 cm 12.57 m 50.27 cm Menu Answers

137 136 Calculate the Circumferences of the following circles. Give answers to 2 decimal places. ( Take π = 3.142 ) 1)2) 3) 4)5)6) 32 cm 53 m 7.5 mm 26 cm 22 m 38 cm 201.09 cm 166.53 m 23.57 mm 163.38 cm 138.25 m119.40 cm Menu Answers

138 137 Menu

139 138 Work out the perimeter. 6 m C = π D C = 3.142 × 6 C = 18.852 m But the blue is only ½ a circle ! Top half arc = 9.426 m Total perimeter = 9.426 + 6 = 15.426 m Menu

140 139 Work out the perimeter. 10 m 6 m 12 m The 4 small quarters make up a complete circle ! C = π D C = 3.142 × 2 C = 6.284 m Total Perimeter = 6.284 + 10 + 6 + 10 + 6 = 38.284 m Menu

141 140 Work out the perimeter. 12 cm Circumference of big circle = 3.142 × 12 = 37.704 cm Length of top arc = 18.852 cm Circumference of small circle = 3.142 × 4 = 12.568 cm Total length of small arcs = 6.284 × 3 = 18.852 cm Total Perimeter = 18.852 + 18.852 = 37.704 cm Menu

142 141 Calculate, to 3 dec.places, the Perimeters of the following shapes. { Let π = 3.142 ) 1) 20 cm 8 cm 2) 3) 6 m4 m 4) 12 cm 62.840 cm 28.568 cm 25.710 m 42.852 cm Menu Answers

143 142 Menu

144 143 Question 1 Let π = 3 2 cm Menu

145 144 Question 2 Let π = 3 5 cm Menu

146 145 Question 3 Let π = 3 10 cm Menu

147 146 Question 4 Let π = 3 1 cm Menu

148 147 Question 5 Let π = 3 8 cm Menu

149 148 Question 6 Let π = 3 16 cm Menu

150 149 Question 7 Let π = 3 6 cm Menu

151 150 Question 8 Let π = 3 6 cm Menu

152 151 Question 9 Let π = 3 200 cm Menu

153 152 Question 10 Let π = 3 0.5 m Menu

154 153 End of Measures Presentation. Return to previous slide.


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