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Published byMelvin Jordan Modified over 8 years ago
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Dr. Nermin Hamza
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x · y = y · x x + y = y + x x · (y · z) = (x · y) · z x + (y + z) = (x + y) + z x · (y + z) = (x · y) + (x · z) x + (y · z) = (x + y) · (x + z) x · x = x x + x = x
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x · (x + y) = x x + (x · y) = x x · x ‘ = 0 x + x’ = 1 (x’) ‘ = x (x · y)’ = x’ + y’ (x + y)’ = x’.y’
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Exercise Proof that : X+ XY = X X+X’Y = X+Y X(X’+Y)= XY
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Exercise Simplify : 1- X + X’.Y 2- X. Y +X’. Z + Y. Z 3- A + ((A. B’) ‘.C
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Exercise Simplify : 1- X + X’.Y = X +Y 2- X. Y +X ‘ Z + Y. Z = X.Y + X’.Z 3- A + ((A. B’) ‘.C = B+C
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Exercise Simplify : 1- A + ((B+C)’. A 2- ((A. B’)’ +B’). B
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Exercise Simplify : 1- A + ((B+C)’. A = A 2- ((A. B’)’ +B’). B = A’.B
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Exercise Get the function as sum of product, product of sum, proof that both cases are equal: XYF 001 010 100 111
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Exercise F= ∑ m(0,1) = X’.Y’ + X.Y F= ∏ M(1,2) = (X’+Y).(X+Y’) PROOF: (X’+Y).(X+Y’) = (X’.X)+(X’.Y’)+(Y. X)+(Y.Y’) = 0+ X’Y’ + X.Y + 0= MIDTERMS
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Exercise GET sum of product and product of sum : ABCF 0000 0010 0100 0111 1001 1011 1101 1111
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Exercise Solution is : ∑ m=(3,4,5,6,7) = A’BC + AB’C’ + AB’C + ABC’ + ABC ∏ M (0,1,2) = (A+B+C).(A+B+C’). (A+ B’ + C) PROOF ??== A+BC
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Exercise GET sum of product and product of sum : ABCF 0001 0011 0101 0110 1000 1010 1100 1110
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Exercise ∑m(0,1,2)= Proof ? A’ (B’+C)
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Other Digital Logic Operation 15 Basic Combinational Logic, NAND and NOR gates
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16 Combinational logic How would your describe the output of this combinational logic circuit?
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17 NAND Gate The NAND gate is the combination of an NOT gate with an AND gate. The Bubble in front of the gate is an inverter.
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18 Combinational logic How would your describe the output of this combinational logic circuit?
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19 NOR gate The NOR gate is the combination of the NOT gate with the OR gate. The Bubble in front of the gate is an inverter.
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20 NAND and NOR gates The NAND and NOR gates are very popular as they can be connected in more ways that the simple AND and OR gates. NAND : F= (XY)’ NOR : F= (X+Y)’
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21 Truth Table Complete the Truth Table for the NAND and NOR Gates InputOutput 001 011 101 110 InputOutput 001 010 100 110 NAND NOR
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XOR F= X’Y +X Y’ = (X XOR Y)
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XNOR F= XY +X’Y’ = (X XOR Y) ‘
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Exercise
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Map Method m0m1 m2m3
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Map Method
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27 Map Representation A two-variable function has four possible minterms. We can re- arrange these minterms into a Karnaugh map (K-map). Now we can easily see which minterms contain common literals. Minterms on the left and right sides contain y’ and y respectively. Minterms in the top and bottom rows contain x’ and x respectively.
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Map Method F(a,b) = Σm(0,3) F(a,b) =A’B’ + AB
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Let f= m1 +m2 + m3 … present in map
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Exercise
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