Download presentation
Presentation is loading. Please wait.
Published byDwight Boone Modified over 8 years ago
1
e 10 cm 1cm e -e
2
Calculate E y here.
3
Cathode Ray Tube Conducting Paper +10 Volts 0 Volts A + B + C +
4
ExEx EyEy + -
5
+ V OUT V IN -
6
V OUT V IN
7
V=6 volts V=8 volts V=4 volts V=2 volts V=0 volts V=-2 volts = 1cm E=?
8
6 V 5 V 4 V abc def ghi
9
3 V A.B. C.
10
3 C 4 C 3 cm -5 C
11
3 C 4 C 3 cm -5 C q
12
3 C 4 C 3 cm -5 C q
13
3 V 6 V 1,000
14
Baseball Diamond Heuristic of Electrostatics Equations
15
(Usually find with Gauss’s Law.) (Remember: V, the electric potential, has units of energy per unit charge.) (scalar) (vector) (The change of electric potential a particle experiences moving from one position to another can be used to find the change in its kinetic energy via the “work- energy theorem”: K = W.) (The potential energy stored in having 2 charges at a distance r from each other.) (The force between 2 charges at a distance r from each other.) Note: F, U, E, and V are all functions of position. RELATING IMPORTANT CONCEPTS
17
3 V B. C.
18
3 V 1 2 3
19
3 V 1 2 3
20
V R1R1 R2R2
21
V R DMM V DMM V R1R1 R DMM V DMM
22
3 V 1 2 3 1
23
100 200 100 10
24
100 200 100 10 V
25
V R1R1 R2R2
26
3 V 1 2 3 1 2
27
3 V 1 2 3 1 2 1
28
9 V R 1 = 1 R 2 = 2 R 3 = 3 R 4 =4 I 4 =? V 4 =? I 1 =? V 1 =?I 2 =? V 2 =? I 3 =? V 3 =? I Battery =? R effective =?
29
SCOPESCOPE tV
30
t V motor t V resistor =|V source |-V motor T t1t1 t2t2 V motor,on V resistor,on on off on off
31
OSCOPEOSCOPE Voltage (0.5 volts per div) Time (1 second per div)
32
OSCOPEOSCOPE Y-axis: Voltage (0.5 volts per division) X-axis: Time (1 second per division) 0 1.5
34
R C + - red1 bottom ground red2
35
R V source (t) = V MAX sin( t) where V MAX = 5 Volts /(2 ) = 1,000 Hz V R (t) = -V source (t) = -V MAX sin( t)
36
V source (t) = V MAX sin( t) where V MAX = 5 Volts /(2 ) = 1,000 Hz
37
V amp =3 V 330 CH1CH2 red1 red2 bottom ground x-y mode
38
200 100 red 1 red 2 (channel inverted) black (middle ground) + - 200 100 red 1 black (bottom ground) red 2 + -
39
R C V source (t)
40
SCOPESCOPE
41
Y-axis: Voltage (5 volts per division) X-axis: Time (3 millisecond per division)
43
I I I Magnet B B Close is strong B Far is ~ zero Magnet B I L
44
I I I I I I Beginning Position180 o Rotated Position current direction reversed (so is force on wire)
45
I I
46
I I I current direction always the same (so is force on wire) DC Power Supply + - these wires fixed brushes allow good contact as loop rotates
47
I A. N I B. S I C. N S S NS N N SS N
48
4 V 0.5 A B 1.5 2.5 4 4 V20 V
49
12 V 1 2 3 1 2 1 2 BATTERY A B
50
6 1 2 S 2 F 6 V
51
+/-Q? NS V velocity
52
NS Direction of I ?
53
NS V velocity
54
NS Direction of I ?
55
V receiver, amplitude f f maximum transmission
56
I resistor,amplitude f drive f resonance
57
R = 2,000 C = 15 F V source amplitude = 15 V L = 75 mH f drive = 750 Hz
58
R [Ohm] C [Farad] V source L [Henry]
59
10 L
60
C L
61
I resistor,amplitude f drive f resonance Same L and C with lower R
62
L R red 1 red 2 ground C R red 1 ground red 2
63
C R red 1 ground red 2 + - C R V source (t)=V source amp sin( D t) + -
64
Pulses let through by the diode move speaker with frequency of desired audio wave. Quantum mechanical turn-on voltage of diode. Modulate Wave Transmitted by Diode to Speaker
65
Function Generator RF Modulator INOUT Variable Capacitor Speaker Diode
66
Speaker Diode Solenoid ASolenoid B
67
Speaker Diode 3,600
68
RF Modulator INGROUND Variable Capacitor Speaker Diode (This is just to provide a ground.) external antenna
69
I2I2 I1I1 P d1d1 d2d2 I W H D
70
2.0 Amp 1.0 Amp P 1.0 meter 2.0 meter
71
Current carrying region 2. Current carrying region 1. Non-conducting material a b c
72
6 1 2 S 2 6 V
73
I I r a
74
A. N B. S C. N S S NS N N SS N
76
D1D1 D2D2
77
(use more frames if necessary) Cartoon Frames
78
30 V Ground 1000 V 2000 V 3000 V to ground constant voltage charge separation + + + + +- - - - - - -
79
x V a (x) -200 100 -100 200 xixi xfxf
80
+ - - + {upward} {outward} “{upward}” and “{outward}” describe which way the electron is deflected. - + {accelerated}
81
+ - - + EaEa E d,v E d,h - +
82
V d Volts 0 Volts d w v f,z x y coordinates z
83
x y V d Volts 0 Volts d w v f,z v f,y yy
84
V d,y Volts 0 Volts d w z y coordinates v f,z v f,y yy - - + + VaVa L y’ DyDy acceleration in z-direction acceleration in y-direction while crossing deflection plates constant motion while crossing remaining distance to screen
85
S (magnet) B S B OR N (magnet) B N B OR Assessment #1Assessment #2
86
I V
87
I V
88
I LED V applied (many various applied V’s) (a non-Ohmic graph) V TURN ON ÷ R
89
VRVR V applied (many various applied V’s)
90
I through R
91
Energy (eV) Momentum Generic Plot of Energy Bands for Semiconductor conduction band (empty) valence band (filled with electrons) E is called Band Gap Energy
92
C R V source Q Cap (0)=0 Q Cap (∞)= Q Max C Q Cap (0)=Q o R Q Cap (∞)= 0
93
C R V source Q Cap (0)=0 Q Cap (∞)= Q Max C Q Cap (0)=Q o =2 [coul] R
94
t V Cap (t) Delineate vertical scale:
95
Algebraic EquationDifferential Equation y+3 = 2 (involves a function y(t) and it’s parameter t) (involves coordinate y) y = -1 (solution is a point/number) (solution is a function of t) (-1)+3 = 2…True! (check solution by plugging point into original algebraic equation) (check solution by plugging function into original differential equation) …True!
96
R V source motor red 1 red 2 black
97
C R red 1 ground red 2 + - C R V source (t)=V source amp sin( D t) + -
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.