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Chapter 10 Notes
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10-1 Area: Parallelograms Area of a figure is the number of square units it encloses. The stuff inside of a figure. Area of a Parallelogram: product of any base length b and the corresponding height h( always makes a right angle). A = bh
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10-1 Area: Parallelograms 6 in 2.5 in A = bh = (2.5)(6) = 15 in 2 4 ft 1 yd A = bh = (4)(3) - change 1 yd to 3 feet = 12 ft 2 or 4 yd 2
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10-2 Area: Triangles and Trapezoids Area of a Triangle: A = (bh)/2 or (1/2)bh h b 5 m 2 m 5.4 m 4 ft5 ft 8.2 ft 1.8 ft Find area of triangles below:
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10-2 Area: Triangles and Trapezoids-answers Area of a Triangle: A = (bh)/2 or (1/2)bh h b 5 m 2 m 5.4 m 4 ft5 ft 8.2 ft 1.8 ft Find area of triangles below: A= 5 m 2 A= 7.38 ft 2
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10-2 Area: Triangles and Trapezoids Area of a Trapezoid: (1/2)h(b 1 + b 2 ) or h(b1 + b2)/2 h b2b2 b1b1 Find the area of the following trapezoids: 7 in 3 in 5 in 4 cm 7 cm 9 cm
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10-2 Area: Triangles and Trapezoids-answers Area of a Trapezoid: (1/2)h(b 1 + b 2 ) or h(b 1 + b 2 )/2 h b2b2 b1b1 Find the area of the following trapezoids: 7 in 3 in 5 in 4 cm 7 cm 9 cm A = 15 in 2 A = 22 cm 2
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10-2 Area: Triangles and Trapezoids Find the area of the following figures: 10 in 10 ft 5 ft 20 ft 12 in 18 ft 6 in 4in
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10-2 Area: Triangles and Trapezoids-answers Find the area of the following figures: 10 in 10 ft 6 ft 20 ft 12 in 18 ft 6 in 4in A = 234 ft 2 A = 108 in 2
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10-3 Area: Circles Area of Circle: A = πr 2 r Find Area: 16 m 10 ft 12 mm 6 mm
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10-3 Area: Circles - answers Area of Circle: A = πr 2 r Find Area: 16 m 10 ft 12 mm 6 mm A = 201 m 2 A = 21.5 ft 2 A = 339 mm 2
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10-4 Space Figures Space Figures: 3-D figures Prism - two parallel bases that are congruent polygons Pyramid - has a base that is a polygon. Lateral faces are triangles. Cylinder - has two parallel bases that are congruent circles Cone - one circular base and one vertex Sphere - a 3-d ball
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10-4 Space Figures Net - an unfolded space figure
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10-4 Space Figures-answers Net - an unfolded space figure Square prism Hexagonal pyramid Pentagonal prism
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10-4 Space Figures
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10-4 Space Figures-answers Base = rectangle Rectangular prism Base = pentagon Pentagonal pyramid Base = circle cone Base = hexagons Hexagonal prism
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10-4 Space Figures
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10-4 Space Figures-answers Base = triangles Triangular prism Base = rectangle Rectangular pyramid
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10-5 Surface Area: Prisms Lateral area: sum of the area of the faces OR L.A. = ph Surface area: sum of all the faces and bases OR S.A. = ph + 2B p = perimeter of the base B = area of the base h = height
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Surface area of a net
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Surface area of a net-answers 3300 ft 2 356 m 2 1092 in 2
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SA of Prisms
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SA of Prisms-answers 500 in 2 480 mm 2
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10-5 Surface Area of Cylinders Lateral area: product of the circumference of the base and the height OR L.A. = 2πrh Surface area: sum of the lateral area and the areas of the 2 bases OR S.A. = 2πrh + 2πr 2 or 2πr(h +r)
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SA of Cylinders
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SA of Cylinders-answers 9470.2 cm 2 About 330 cm 2
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10-6 Surface Area: Pyramids, Cones, and Spheres Surface Area of a Pyramid: o Lateral Area - area of each triangle added together or the formula: LA = (1/2)Pl or Pl / 2 o Total Surface Area -sum of the area of each triangle and area of the base or the formula: Total SA = (1/2)Pl + B P represents Perimeter of the base of a 3-D figure B represents Area of the base 3-D figure l represents slant height
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10-6 Surface Area: Pyramids, Cones, and Spheres Find lateral area and total surface area. Lateral Area: Total Surface Area:
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10-6 Surface Area: Pyramids, Cones, and Spheres-answers Find lateral area and total surface area. Lateral Area: Total Surface Area: 80 m 2 80 + 25 = 105 cm 2
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10-6 Surface Area: Pyramids, Cones, and Spheres Find lateral area and total surface area. Lateral Area: Total Surface Area:
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10-6 Surface Area: Pyramids, Cones, and Spheres-answers Find lateral area and total surface area. Lateral Area: Total Surface Area: 108 cm 2 108 + 36 = 144 cm 2
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10-6 Surface Area: Pyramids, Cones, and Spheres Surface Area of a Cone: o Lateral Area - area of the sides LA = πrl o Total Surface Area -sum of the lateral area and area of the base: Total SA = πrl + B or πrl + πr 2
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10-6 Surface Area: Pyramids, Cones, and Spheres Lateral Area: Total Surface Area:
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10-6 Surface Area: Pyramids, Cones, and Spheres Lateral Area: Total Surface Area: (3.14)(3)(7)= 65.94 m 2 65.94 + (3.14)(3 2 ) = 94.2 m 2
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10-6 Surface Area: Pyramids, Cones, and Spheres Lateral Area: Total Surface Area:
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10-6 Surface Area: Pyramids, Cones, and Spheres-answers Lateral Area: Total Surface Area: (3.14)(7)(15)= 329.7 ft 2 329.7 + (3.14)(7 2 ) = 483.56 ft 2
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10-6 Surface Area: Pyramids, Cones, and Spheres Surface Area of a Sphere: Total Surface Area = 4πr 2 SA =
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10-6 Surface Area: Pyramids, Cones, and Spheres Surface Area of a Sphere: Total Surface Area = 4πr 2 SA = 200.96 units squared
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10-6 Surface Area: Pyramids, Cones, and Spheres Find surface area of each figure:
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10-6 Surface Area: Pyramids, Cones, and Spheres-answers Find surface area of each figure: 216 m 2 122 m 2
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10-7 Volume of Prisms and Cylinders Volume of a prism: product of the area of the base (B) and the height (h) V = Bh OR V = lwh (rectangular prism) V = (bh)H/2 (trianglular prism) H = height of prism Volume of Cylinders: the base area (B) times the height (h) V = Bh OR V = πr 2 h
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Answers 628 m 3 1408 cm 3 147,706 in 3 726 in 3 480 ft 3 25,434 cm 3
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Answers 8139 m 3 192 ft 3
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10-9 Volume: Pyramids, Cones, and Spheres Volume of Cone: V = (1/3) Bh or Bh/3 B = area of the base
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10-9 Volume: Pyramids, Cones, and Spheres-answers Volume of Cone: V = (1/3) Bh or Bh/3 B = area of the base 1272 in 3 33 mm 3
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10-9 Volume: Pyramids, Cones, and Spheres Volume of a Pyramid: V = (1/3) Bh or Bh/3 B = area of the base
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10-9 Volume: Pyramids, Cones, and Spheres-answers Volume of a Pyramid: V = (1/3) Bh or Bh/3 B = area of the base 33 m 3 1728 in 3
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10-9 Volume: Pyramids, Cones, and Spheres Volume of a Sphere: V = (4/3) πr 3 or (4πr 3 )/3 B = area of the base
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10-9 Volume: Pyramids, Cones, and Spheres-answers Volume of a Sphere: V = (4/3) πr 3 or (4πr 3 )/3 B = area of the base 3052 ft 3 5572 cm 3
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10-9b Scaling and Volume Similar solids have the same shape and all their corresponding dimensions are proportional. The ratio of corresponding edge lengths of 2 similar solids is the similarity ratio. Similarity ratio: length of front edge of smaller length of front edge of larger
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Each pair of prisms is similar. Find the similarity ratio and ratio of the volumes of each.
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Each pair of prisms is similar. Find the similarity ratio and ratio of the volumes of each.-answers Similarity ratio = 1:2 Ratios of volume = 1:8 Similarity ratio = 2:3 Ratios of volume = 8:27
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Each pair of prisms is similar. Find the volume of the larger prism.
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answers 216 ft 3 11.4 yd 3
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