1. Light, Mirrors, and Lenses

2. Light is a part of the electromagnetic spectrum.

3. Light can travel through empty space as well as air and water.

4. Light is a transverse wave.

5. Light comes in discreet packages called photons.

6. Light has properties of a particle and wave, known as the dual nature of light.

7. The Sun is a Luminous Source, which means it gives off light!

8. Luminous Flux (P) is the amount of light emitted by a source.

9. Luminous Flux (P) is measured in lumens (lm).

10. Illuminance (E) is how much light is striking a surface

11. Illuminance (E) depends on the intensity of the source (P) and how far away from the source!

12. Point Source Illuminance E = P 4πr24πr2 P = luminous source intensity in lumens (lm) E = Illumination is measured in lm/m 2 or lux (lx) r = is distance between luminous source and the illuminated object.

13. Similarities of Light to Sound Source determines the frequency. Speed depends on what it is traveling through. Light travels fastest in a vacuum, slowest through water. v = f λ still applies. The speed of light in a vacuum is constant and represented by c. c = f λc = 3.00 ˣ 10 8 m/s

14. The primary colors of light are red, green, and blue.

15. The secondary colors of light are yellow, cyan, and magenta.

16. All of the colors combined make white light.

17. The mixing of all of these colors makes every color we see.

18. Doppler Shift

19. Observed λ is different from emitted λ if objects are moving.

20. If objects are moving away it shifts to the red (longer λ)

21. If objects are moving closer it shifts to the blue (shorter λ)

22. This is used in Astronomy!

23. This is based on the speed of the object (v) compared to light speed (c)

24. Doppler Shift λ obs – λ = ± v c λ λ obs is wavelength observed. v speed of the source and observer. c is speed of light 3.00 × 10 8 m/s λ is wavelength emitted from source.

25. Doppler Shift λ obs – λ = ± v c λ Quantity is positive if moving away from each other (red shift). Quantity is negative if moving closer to each other (blue shift).

26. Polarization of Light

27. Incident light is unpolarized and is at all angles.

28. The first filter removes the horizontal light.

29. The second filter removes the vertical light.

30. No light gets past the second filter!

31. This is how sunglasses work!

32. Glare is horizontal light reflected off of the ground.

33. Vertical Polarizers eliminates the horizontal light leaving only vertical.

34. More on Reflection and Refraction.

35. The Law of Reflection always applies.

36. A Smooth surface gives a regular reflection where light comes back in parallel beams.

37. A rough surface gives a diffuse reflection because light is scattered.

38. Keep in mind we see nothing unless it reflects light!!

39. Mirrors and Lenses

40. First we will look at curved mirrors, which are just a section of a circle.

41. The focal point of a concave mirror is the point halfway between the center of the circle and the surface of the mirror.

42. Following three rules we can find the location of any image. FC

43. #1 Draw a line from the top of the object reflected through the focal point. FC

44. #2 Draw a ray through the focal point and reflected parallel. FC

45. #3 draw a line through the center and straight back to the object. FC

46. We now know the location of the image. Any two of our lines will tell us. FC

47. It is an inverted image because it is upside down. FC

48. It is a real image because the beams of light actually pass through. FC

49. It is a diminished image because it is smaller than the object! FC

50. We can locate this image with the same rules. FC

51. What do we do? FC

52. Extend the reflected rays behind the mirror!!! F C

53. Is this image real? F C

54. No, the light does not actually travel there! F C

55. This image is said to be virtual ! F C

56. Is the image inverted or erect? F C

57. Erect, because it is upright! F C

58. The image is magnified because it is larger than the object! F C

59. Convex mirrors produce small images. The focal point is behind the mirror.

60. The images are never real.

61. These mirrors are valued for their wide angle views!!

62. We apply the rules we learned before. FC

63. We treat the reflected ray as if it were coming from the focus. FC

64. The second line is to the focus and straight outward. FC

65. The image is diminished giving us our “wide angle view” FC

66. Now on to Lenses!!

67. Locating an image with a lens FF

68. #1 Draw a line from the top of the object and then through a focal point. FF

69. #2 Draw a line to the top of the object straight through the center. FF

70. The image is inverted, real, and magnified. FF

71. If the object is in front of the focal point…. FF

72. What do we do???? FF

73. Extend the rays backwards…… FF

74. The image is erect, virtual, and magnified…… FF

75. Convex Lens Image Zones FF2F Zone 1: Image is on the same side, erect, magnified, and virtual.

76. Convex Lens Image Zones FF2F Zone 2: Image is on the opposite side, inverted, magnified, and real.

77. Convex Lens Image Zones FF2F Zone 3: Image is on the opposite side, inverted, diminished, and real.

78. Zone I

79. At F image at infinity and does not exist.

80. Zone II

81. At 2F image at 2F

82. Zone III

83. A convex lens focuses light on a point…..

84. A concave lens spreads light out….

85. A concave lens is used to help people with myopia.

86. Optics The Math of Mirrors and Lenses I See You!!

87. The Mirror Equation 111 += soso sisi f s o is the object’s distance from the mirror. s i is the image’s distance from the mirror. f is the focal length of the mirror.

88. The Mirror Equation 111 += soso sisi f If the answer is positive the image is real !! If the answer is negative the image is virtual !!

89. The Magnification Equation = ˗ soso sisi If the answer is positive the image is upright !! If the answer is negative the image is inverted !! m m in this equation means magnification!!

90. More on Magnification ×hoho hihi ∣m ∣ Use the absolute value for magnification!! = h o is the height of the object!! h i is the height of the image!!

91. 20 cm focal point soso 30 cm Where is the image? 1 30 + 1 sisi = 1 20 0.033+ 1 sisi =0.05 sisi =59 cm The positive result means a real image.

92. 20 cm focal point soso 30 cm What is the size of the image?? sisi = 59 soso = 30 -m 59 cm -m sisi m=-1.97 The negative result means an inverted image.

93. 20 cm focal point hoho 30 cm What is the size of the image?? 59 cm hihi 1.97 ∣m ∣× × hoho 5 = = hihi hihi hihi =9.85 cm

94. Refraction and Snell’s Law

95. Refraction goes along with reflection!!

96. Notice the refracted ray is smaller than the incident ray.

97. This is because light is slower in water than in air!

98. Facts about Refraction When light goes from a faster to slower medium, it will bend towards the normal. The Angle of Refraction is always dependent on the Angle of Incidence!!! The higher the Index of Refraction the slower light travels through the medium!!

99. The Light travels towards water at 60° Normal

102. Since light travels through glass even slower it will bend more towards the normal!! Normal

103. When light travels from a faster to slower medium it bends towards the normal!!

104. Normal

105. Since light moves slower through glass than water it bends more as it crosses the boundary!!

106. Normal

107. Using this information we can calculate the Index of Refraction (n).

108. Finding the Index of Refraction for water…

109. The Index of Refraction can also be done in terms of the speed of light!

110. Use the speed of light in a vacuum over the speed of light in water.

111. Finding the Index of Refraction for glass…

112. Remember Index of Refraction can never be less than 1 (vacuum) !!

113. Using Snell’s Law we can predict how light will bend if we know the indexes of refraction!!

120. When light went from air to water it bent towards the normal, but water to air it bends away from the normal!!

121. Why???

122. Because light travels faster in air than water!!!

123. When light travels from a slower to faster medium it bends away from the normal

124. Common Indexes of Refraction Vacuum Air Water Ethanol Crown Glass Quartz Flint Glass Diamond 1.00 1.0003 1.33 1.36 1.52 1.54 1.61 2.42

125. Light can be used to send digital signals through Total Internal Reflection…

126. This is used in fiber optic cables…

127. Total Internal Reflection This occurs because an incident beam enters a medium with a lower index of refraction, such as from water to air. (Light is refracted away from the normal) The critical angle (θ c ) is reached when the light is refracted at 90° and travels along the surface. At angles greater than the critical angle (θ c ) total internal reflection occurs.

128. Critical Angle ( θ c )

129. Notice Total Internal Reflection only occurs when the angle of the Incident beam is greater than the critical angle. θ i ˃ θ c

130. Summary of Requirements for Total Internal Reflection Index of Refraction must be lower for medium incident beam in entering. n r ˂ n i or n 2 ˂ n 1 The angle of incidence must be greater than the critical angle! θ i ˃ θ c or θ 1 ˃ θ c

131. From Water to Air n1n1 n2n2 sin θ c == 1.00 1.33 sin θ c = 0.7518 sin -1 θc θc =(0.7518) θc θc = 48.8°

132. The End