2. Course: Applied Geo. Aim: Surface Area Aim: How do we find the surface area of three dimensional figures? Do Now: Find area of shaded region.

3. Course: Applied Geo. Aim: Surface Area Cube all edges are same measure x x x all faces are squares 12 6 (A)(B) (C)(D) Which fold to make a cube? A, B, & D

4. Course: Applied Geo. Aim: Surface Area For each of these unfolded cubes, determine the color that will be opposite the red face when folded. (A) (B) (C) (D) Blue Green Brown Purple

5. Course: Applied Geo. Aim: Surface Area 600 sq. units 10 Find the surface area of cube with edge = 10 10 100 10 The surface area is the sum of the areas of the faces of the polyhedron.

6. Course: Applied Geo. Aim: Surface Area Rectangular Prism 10 20 10 200 100 1000 sq. units Faces? Shapes? 6 4 rectangles 2 squares The surface area is the sum of the areas of the faces of the polyhedron. A of Square = s 2 A of Rectangle = lw

7. Course: Applied Geo. Aim: Surface Area The surface area is the sum of the areas of the faces of the polyhedron. A of Triangle = 1/2 bh Right Pyramid with square base 10 15 10 15 10 15 75 100 Faces? Shapes?5 1 square base 4 triangles A of Square = s 2 A of each triangle = 1/2 (10)(15) = 75 400 sq. units

8. Course: Applied Geo. Aim: Surface Area Cylinder Faces? Shapes?3 2 circles 1 rectangle r h 1D1D 2D2D 3D3D 3.14 D= length of rectangle and the circumference of the circle h A of Circle =  r 2 r r C =  D D = 2r Find the surface area if r = 5 and h = 10 A of rectangle = lw 3.14 D S.A. of cylinder = 2  r 2 + 2  rh

9. Course: Applied Geo. Aim: Surface Area r h10 A of Circle =  r 2 5 5 C =  D D = 2r Find the surface area of a cylinder if r = 5 and h = 10 A of rectangle = lw 3.14 (10) A of each circle = 3.14(5) 2 = 78.5  157 sq. units (2) A of rectangle = (10)(3.14)(10) = 314 sq. units Surface area of cylinder = 471 sq units 78.5 (10)(3.14)(10) = 314 S.A. of cylinder = 2  r 2 + 2  rh

10. Course: Applied Geo. Aim: Surface Area A cylindrical cement pipe has length 500 ft and diameter 3 ft. If you are to paint the exterior of the pipe, how many square feet will you paint? Leave your answer in terms of . 500 ft 3 ft Equivalent to circumference of circle with diameter of 3 ft. C =  D  width of unfolded pipe w =  3 Exterior area of pipe = lw = (3  )500 = 1500  33 500 ft