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AP PHYSICS 1 Sound Loudness Intensity and Doppler

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1 AP PHYSICS 1 Sound Loudness Intensity and Doppler

2 Sound Waves Sound is longitudinal pressure (compression) waves
Range of hearing: 20 Hz to 20,000 Hz FREQUENCY DEMO

3 Intensity of Sound Waves
Power Area SI units are W/m2 Intensity is proportional to square of amplitude (pressure modulation)

4 Power, Energy, and Intensity
The intensity of sound (brightness or loudness) depends on the power of the source and the area that receives the power: The SI units are W/m2. A wave focused on a small area has higher intensity than if it were spread out. © 2015 Pearson Education, Inc.

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6 Spherical Waves Energy propagates equally in all directions Þ

7 Intensity Range for Human Hearing
Threshold of Hearing 10-12 W/m2 DP ~ atm ! Threshold of Pain 1.0 W/m2

8 Decibel Scale Sensation is logarithmic
I0 is threshold of hearing (0 dB) Threshold of Pain is therefore 120 dB

9 Intensity vs. Intensity Level
INTENSITY is P/A, W/m2 INTENSITY LEVEL is in decibels (dimensionless)

10 The Decibel Scale The threshold of hearing is the lowest intensity sound that can be heard. It is where we place the 0 for our loudness scale. For the average human, it is I0 = 1.0  1012 W/m2 The sound intensity level is expressed in decibels (dB) as

11 The Decibel Scale As a reminder, logarithms work like this:

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13 The Decibel Scale Right at the threshold of hearing, where I = I0, the sound intensity level is The threshold of hearing corresponds to 0 dB. © 2015 Pearson Education, Inc.

14 Sound Level Demo Sound dB Demo

15 Example 14.2 A noisy machine in a factory produces a sound with a level of 80 dB. How many machines can the factory house without exceeding the 100-dB limit? a) 12.5 machines b) 20 machines c) 100 machines

16 The Decibel Scale We can find the intensity from the sound intensity level by taking the inverse of the log10 function Recall, from the definition of the base-10 logarithm, that 10log(x) = x. Applying this to Equation 15.14, we find I = (I0)10(β/10 dB)

17 The Decibel Scale

18 Example 14.3 (skip) A train sounds its horn as it approaches an intersection. The horn can just be heard at a level of 50 dB by an observer 10 km away. Treating the horn as a point source and neglect any absorption of sound by the air or ground, a) What is the average power generated by the horn? b) What intensity level of the horn’s sound is observed by someone waiting at an intersection 50 m from the train? a) 126 W b) 96 dB

19 Example 14.4 Bozo Bob buys a 20-W train whistle and figures out that he won’t have any trouble standing 2 meters from the whistle since his stereo speakers are rated at 100 W and he has little trouble with the speakers turned all the way up. What is the intensity level of the whistle? 116 dB

20 Finding the loudness of a shout
A person shouting at the top of his lungs emits about 1.0 W of energy as sound waves. What is the sound intensity level 1.0 m from such a person? prepare We will assume that the shouting person emits a spherical sound wave.

21 Example 15.11 Finding the loudness of a shout
solve At a distance of 1.0 m, the sound intensity is Thus the sound intensity level is assess This is quite loud as you might expect.

22 Example Problem You are working in a shop where the noise level is a constant 90 dB. Your eardrum has a diameter of approximately 8.4 mm. How much power is being received by one of your eardrums? This level of noise is damaging over a long time, so you use earplugs that are rated to reduce the sound intensity level by 26 dB, a typical rating. What is the power received by one eardrum now? Answer: part A: the power = intensity*area (eq ). The intensity is 1e-12*10^9 for 90 dB noise level (eq ) or 1E-3 w/M^2, so the power is 1E-3*pi*(8.4e-3)^2 = 2.2E-7W part B: The power is now reduced by a factor of 10^(2.6), so the new power is 5.6E-10 W. Answer: part A: the power = intensity*area (eq ). The intensity is 1e-12*10^9 for 90 dB noise level (eq ) or 1E-3 w/M^2, so the power is 1E-3*pi*(8.4e-3)^2 = 2.2E-7W part B: The power is now reduced by a factor of 10^(2.6), so the new power is 5.6E-10 W.

23 The Decibel Scale

24 Doppler Effect A change in the frequency experienced by an observer due to motion of either the observer or the source. DOPPLER DEMO

25 The Doppler Effect and Shock Waves
The Doppler effect is a change in frequency due to the motion of the source. This effect is heard as the pitch of an ambulance siren changes from its approach to after it has passed you by. A shock wave is produced when an object moves faster than the speed of sound. When you hear the crack of the whip, the tip of a whip is moving at supersonic speeds.

26 Doppler Effect, Moving Observer
When not moving, When moving,

27 If observer moves away:

28 Example 1 Mary is riding a roller coaster. Her mother who is standing on the ground behind her yells out to her at a frequency of 1000 Hz, but it sounds like 920 Hz. (v=343 m/s) What is Mary’s speed? 27.4 m/s

29 Doppler Effect Source in Motion
applet

30 Doppler Effect Source in Motion

31 Doppler Effect, Source in Motion
Approaching source: Source leaving:

32 Doppler Effect: Both Observer and Source Moving
Switch appropriate signs if observer or source moves away Note: Observer is moving toward the source Vo is “+” Observer is moving away from the source Vo is “-” Source is moving toward the observer Vs is “-” Source is moving away from the observer Vs is “+”

33 Example 2 An train has a brass band playing a song on a flatcar. As the train approaches the station at 21.4 m/s, a person on the platform hears a trumpet play a note at 3520 Hz. DATA: vsound = 343 m/s a) What is the true frequency of the trumpet? b) What is the wavelength of the sound? c) If the trumpet plays the same note after passing the platform, what frequency would the person on the platform hear? a) Hz b) 9.74 cm c) 3106 Hz

34 Application: speed radar

35 Application: weather radar
Both humidity (reflected intensity) and speed of clouds (doppler effect) are measured.

36 Example 3 At rest, a car’s horn sounds the note A (440 Hz). The horn is sounded while the car moves down the street. A bicyclist moving in the same direction at 10 m/s hears a frequency of 415 Hz. DATA: vsound = 343 m/s. What is the speed of the car? (Assume the cyclist is behind the car) 31.3 m/s

37 Example 4 A train has a whistle with a frequency of a 1000 Hz, as measured when both the train and observer are stationary. For a train moving in the positive x direction, which observer hears the highest frequency when the train is at position x=0? Observer A has velocity VA>0 and has position XA>0. Observer B has velocity VB>0 and has position XB<0. Observer C has velocity VC<0 and has position XC>0. Observer D has velocity VD<0 and has position XD<0.

38 Example 5 A train has a whistle with a frequency of a 1000 Hz, as measured when both the train and observer are stationary. A train is moving in the positive x direction. When the train is at position x=0, An observer with V>0 and position X>0 hears a frequency: > 1000 Hz < 1000 Hz Can not be determined

39 Example 6 A train has a whistle with a frequency of a 1000 Hz, as measured when both the train and observer are stationary. A train is moving in the positive x direction. When the train is at position x=0, An observer with V>0 and position X<0 hears a frequency: > 1000 Hz < 1000 Hz Can not be determined

40 Example 7 A train has a whistle with a frequency of a 1000 Hz, as measured when both the train and observer are stationary. A train is moving in the positive x direction. When the train is at position x=0, An observer with V<0 and position X<0 hears a frequency: > 1000 Hz < 1000 Hz Can not be determined

41 Example 8: How fast are the police driving?
A police siren has a frequency of 550 Hz as the police car approaches you, 450 Hz after it has passed you and is moving away. How fast are the police traveling?

42 Example 15.13 How fast are the police driving? (cont.)
solve Because our goal is to find vs, we rewrite Equations as Subtracting the second equation from the first, we get

43 Example 15.13 How fast are the police driving? (cont.)
Now we can solve for the speed vs: assess This is pretty fast (about 75 mph) but reasonable for a police car speeding with the siren on.

44 Summary: Applications
d d Both Observer and Source moving. d d d d © 2015 Pearson Education, Inc.

45 Doppler Video Plane Video

46 Shock Waves A source is supersonic if it travels faster than the speed of sound. A shock wave travels with the source. If a supersonic source passes an observer, the shock wave produces a sonic boom. Less extreme examples of shock waves include the wake of a boat and the crack of a whip. © 2015 Pearson Education, Inc.

47 Shock Waves (Sonic Booms)
When the source velocity approaches the speed of sound, Video

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49 Section 16.7 Beats © 2015 Pearson Education, Inc.

50 Beats Beat Video

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52 15.3 Consonance, dissonance, and beats
Harmony is the study of how sounds work together to create effects desired by the composer. When we hear more than one frequency of sound and the combination sounds good, we call it consonance. When the combination sounds bad or unsettling, we call it dissonance.

53 15.3 Consonance, dissonance, and beats
Consonance and dissonance are related to beats. When frequencies are far enough apart that there are no beats, we get consonance. When frequencies are too close together, we hear beats that are the cause of dissonance. Beats occur when two frequencies are close, but not exactly the same.

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55 Beats The superposition of two waves with slightly different frequencies can create a wave whose amplitude shows a periodic variation. © 2015 Pearson Education, Inc.

56 Beats The ear hears a single tone that is modulated. The distinctive sound pattern is called beats. © 2015 Pearson Education, Inc.

57 Beats The air oscillates against your eardrum at frequency
The beat frequency is the difference between two frequencies that differ slightly: fosc determines the pitch, fbeat determines the frequency of the modulations. © 2015 Pearson Education, Inc.

58 QuickCheck 16.18 You hear 2 beats per second when two sound sources, both at rest, play simultaneously. The beats disappear if source 2 moves toward you while source 1 remains at rest. The frequency of source 1 is 500 Hz. The frequency of source 2 is 496 Hz 498 Hz 500 Hz 502 Hz 504 Hz Answer: B © 2015 Pearson Education, Inc. 58

59 QuickCheck 16.18 You hear 2 beats per second when two sound sources, both at rest, play simultaneously. The beats disappear if source 2 moves toward you while source 1 remains at rest. The frequency of source 1 is 500 Hz. The frequency of source 2 is 496 Hz 498 Hz 500 Hz 502 Hz 504 Hz © 2015 Pearson Education, Inc. 59


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