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Graphing Quadratics
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Finding the Vertex We know the line of symmetry always goes through the vertex. Thus, the line of symmetry gives us the x – coordinate of the vertex. To find the y – coordinate of the vertex, we need to plug the x – value into the original equation. STEP 1: Find the line of symmetry STEP 2: Plug the x – value into the original equation to find the y value. y = –2x 2 + 8x –3 y = –2(2) 2 + 8(2) –3 y = –2(4)+ 8(2) –3 y = –8+ 16 –3 y = 5 Therefore, the vertex is (2, 5)
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A Quadratic Function in Standard Form The standard form of a quadratic function is given by y = ax 2 + bx + c There are 3 steps to graphing a parabola in standard form. STEP 1: Find the line of symmetry STEP 2: Find the vertex STEP 3: Find two other points and reflect them across the line of symmetry. Then connect the five points with a smooth curve. Plug in the line of symmetry (x – value) to obtain the y – value of the vertex. MAKE A TABLE using x – values close to the line of symmetry. USE the equation
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STEP 1: Find the line of symmetry Let's Graph ONE! Try … y = 2x 2 – 4x – 1 A Quadratic Function in Standard Form Thus the line of symmetry is x = 1
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Let's Graph ONE! Try … y = 2x 2 – 4x – 1 STEP 2: Find the vertex A Quadratic Function in Standard Form Thus the vertex is (1,–3). Since the x – value of the vertex is given by the line of symmetry, we need to plug in x = 1 to find the y – value of the vertex.
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5 –1 Let's Graph ONE! Try … y = 2x 2 – 4x – 1 STEP 3: Find two other points and reflect them across the line of symmetry. Then connect the five points with a smooth curve. A Quadratic Function in Standard Form 3 2 yx
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1) Graphing Parabolas Example 2: Graph y = x 2 – 2x – 3.
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1) Graphing Parabolas Example 2: Graph y = x 2 – 2x – 3. Step 1: Find the axis of symmetry. Axis of symmetry: Equation for the axis of symmetry: x = 1
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1) Graphing Parabolas Example 2: Graph y = x 2 – 2x – 3. Step 2: Find the vertex. Sub x = 1 into the equation, solve for y. y = (1) 2 – 2(1) – 3 y = -4 The vertex is at (1, -4).
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1) Graphing Parabolas Example 2: Graph y = x 2 – 2x – 3. Step 3: Plot points and sketch the graph. xy 1-4 2 3 4
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1) Graphing Parabolas Example 2: Graph y = x 2 – 2x – 3. Step 3: Plot points and sketch the graph. xy 1-4 2(2) 2 – 2(2) – 3 = -3 3(3) 2 – 2(3) – 3 = 0 4(4) 2 – 2(4) – 3 = 5
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1) Graphing Parabolas Example 2: Graph y = x 2 – 2x – 3.
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EXAMPLE Graph y = 2x 2 -8x +6 Solution: The coefficients for this function are a = 2, b = -8, c = 6. Since a>0, the parabola opens up. The x-coordinate is: x = -b/2a, x = -(-8)/2(2) x = 2 The y-coordinate is: y = 2(2) 2 -8(2)+6 y = -2 Hence, the vertex is (2,-2).
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EXAMPLE(contd.) Draw the vertex (2,-2) on graph. Draw the axis of symmetry x=-b/2a. Draw two points on one side of the axis of symmetry such as (1,0) and (0,6). Use symmetry to plot two more points such as (3,0), (4,6). Draw parabola through the plotted points. (2,-2) (1,0) (0,6) (3,0) (4,6) Axis of symmetry x y
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VERTEX FORM OF QUADRATIC EQUATION y = a(x - h) 2 + k The vertex is (h,k). The axis of symmetry is x = h.
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GRAPHING A QUADRATIC FUNCTION IN VERTEX FORM (-3,4) (-7,-4) (-1,2) (-5,2) (1,-4) Axis of symmetry x y Example y = -1/2(x + 3) 2 + 4 where a = -1/2, h = -3, k = 4. Since a<0 the parabola opens down. To graph a function, first plot the vertex (h,k) = (-3,4). Draw the axis of symmetry x = -3 Plot two points on one side of it, such as (- 1,2) and (1,-4). Use the symmetry to complete the graph.
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Your Turn! Analyze and Graph: y = (x + 4) 2 - 3. (-4,-3)
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18 Example: Basketball Example: A basketball is thrown from the free throw line from a height of six feet. What is the maximum height of the ball if the path of the ball is: The path is a parabola opening downward. The maximum height occurs at the vertex. At the vertex, So, the vertex is (9, 15). The maximum height of the ball is 15 feet.
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