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STAT 497 LECTURE NOTES 3 STATIONARY TIME SERIES PROCESSES

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1 STAT 497 LECTURE NOTES 3 STATIONARY TIME SERIES PROCESSES
(ARMA PROCESSES OR BOX-JENKINS PROCESSES)

2 AUTOREGRESSIVE PROCESSES
AR(p) PROCESS: or where

3 AR(p) PROCESS Because the process is always invertible.
To be stationary, the roots of p(B)=0 must lie outside the unit circle. The AR process is useful in describing situations in which the present value of a time series depends on its preceding values plus a random shock.

4 AR(1) PROCESS where atWN(0, ) Always invertible.
To be stationary, the roots of (B)=1B=0 must lie outside the unit circle.

5 ||<1 STATIONARITY CONDITION
AR(1) PROCESS OR using the characteristic equation, the roots of m=0 must lie inside the unit circle. B=1  |B|<|1| ||<1 STATIONARITY CONDITION

6 AR(1) PROCESS This process sometimes called as the Markov process because the distribution of Yt given Yt1,Yt2,… is exactly the same as the distribution of Yt given Yt1.

7 AR(1) PROCESS PROCESS MEAN: 

8 AR(1) PROCESS AUTOCOVARIANCE FUNCTION: k Keep this part as it is

9 AR(1) PROCESS

10 AR(1) PROCESS When ||<1, the process is stationary and the ACF decays exponentially.

11 AR(1) PROCESS 0 <  < 1  All autocorrelations are positive.
1 <  < 0  The sign of the autocorrelation shows an alternating pattern beginning a negative value.

12 AR(1) PROCESS RSF: Using the geometric series

13 AR(1) PROCESS RSF: By operator method _ We know that

14 AR(1) PROCESS RSF: By recursion

15 THE SECOND ORDER AUTOREGRESSIVE PROCESS
AR(2) PROCESS: Consider the series satisfying where atWN(0, ).

16 AR(2) PROCESS Always invertible. Already in the Inverted Form.
To be stationary, the roots of must lie outside the unit circle. OR the roots of the characteristic equation must lie inside the unit circle.

17 AR(2) PROCESS

18 AR(2) PROCESS Considering both real and complex roots, we have the following stationary conditions for AR(2) process (see page 84 for the proof)

19 AR(2) PROCESS THE AUTOCOVARIANCE FUNCTION: Assuming stationarity and that at is independent of Ytk, we have

20 AR(2) PROCESS

21 AR(2) PROCESS

22 AR(2) PROCESS

23 AR(2) PROCESS

24 AR(2) PROCESS ACF: It is known as Yule-Walker Equations
ACF shows an exponential decay or sinusoidal behavior.

25 AR(2) PROCESS PACF: PACF cuts off after lag 2.

26 AR(2) PROCESS RANDOM SHOCK FORM: Using the Operator Method

27 The p-th ORDER AUTOREGRESSIVE PROCESS: AR(p) PROCESS
Consider the process satisfying where atWN(0, ). provided that roots of all lie outside the unit circle

28 AR(p) PROCESS ACF: Yule-Walker Equations
ACF: tails of as a mixture of exponential decay or damped sine wave (if some roots are complex). PACF: cuts off after lag p.

29 MOVING AVERAGE PROCESSES
Suppose you win 1 TL if a fair coin shows a head and lose 1 TL if it shows tail. Denote the outcome on toss t by at. The average winning on the last 4 tosses=average pay-off on the last tosses: MOVING AVERAGE PROCESS

30 MOVING AVERAGE PROCESS
Errors are the average of this period’s random error and last period’s random error. No memory of past levels. The impact of shock to the series takes exactly 1-period to vanish for MA(1) process. In MA(2) process, the shock takes 2-periods and then fade away. In MA(1) process, the correlation would last only one period.

31 MOVING AVERAGE PROCESSES
Consider the process satisfying

32 MOVING AVERAGE PROCESSES
Because , MA processes are always stationary. Invertible if the roots of q(B)=0 all lie outside the unit circle. It is a useful process to describe events producing an immediate effects that lasts for short period of time.

33 THE FIRST ORDER MOVING AVERAGE PROCESS_MA(1) PROCESS
Consider the process satisfying

34 MA(1) PROCESS From autocovariance generating function

35 MA(1) PROCESS ACF ACF cuts off after lag 1.
General property of MA(1) processes: 2|k|<1

36 MA(1) PROCESS PACF:

37 MA(1) PROCESS Basic characteristic of MA(1) Process:
ACF cuts off after lag 1. PACF tails of exponentially depending on the sign of . Always stationary. Invertible if the root of 1B=0 lie outside the unit circle or the root of the characteristic equation m=0 lie inside the unit circle.  INVERTIBILITY CONDITION: ||<1.

38 MA(1) PROCESS It is already in RSF. IF: 1= 2=2

39 MA(1) PROCESS IF: By operator method

40 THE SECOND ORDER MOVING AVERAGE PROCESS_MA(2) PROCESS
Consider the moving average process of order 2:

41 MA(2) PROCESS From autocovariance generating function

42 MA(2) PROCESS ACF ACF cuts off after lag 2.
PACF tails of exponentially or a damped sine waves depending on a sign and magnitude of parameters.

43 MA(2) PROCESS Always stationary. Invertible if the roots of
all lie outside the unit circle. OR if the roots of all lie inside the unit circle.

44 MA(2) PROCESS Invertibility condition for MA(2) process

45 MA(2) PROCESS It is already in RSF form.
IF: Using the operator method:

46 The q-th ORDER MOVING PROCESS_ MA( q) PROCESS
Consider the MA(q) process:

47 MA(q) PROCESS The autocovariance function: ACF:

48 THE AUTOREGRESSIVE MOVING AVERAGE PROCESSES_ARMA(p, q) PROCESSES
If we assume that the series is partly autoregressive and partly moving average, we obtain a mixed ARMA process.

49 ARMA(p, q) PROCESSES For the process to be invertible, the roots of
lie outside the unit circle. For the process to be stationary, the roots of Assuming that and share no common roots, Pure AR Representation: Pure MA Representation:

50 ARMA(p, q) PROCESSES Autocovariance function ACF
Like AR(p) process, it tails of after lag q. PACF: Like MA(q), it tails of after lag p.

51 ARMA(1, 1) PROCESSES The ARMA(1, 1) process can be written as
Stationary if ||<1. Invertible if ||<1.

52 ARMA(1, 1) PROCESSES Autocovariance function:

53 ARMA(1,1) PROCESS The process variance

54 ARMA(1,1) PROCESS

55 ARMA(1,1) PROCESS Both ACF and PACF tails of after lag 1.

56 ARMA(1,1) PROCESS IF:

57 ARMA(1,1) PROCESS RSF:

58 AR(1) PROCESS

59 AR(2) PROCESS

60 MA(1) PROCESS

61 MA(2) PROCESS

62 ARMA(1,1) PROCESS

63 ARMA(1,1) PROCESS (contd.)


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