1. Chapter 1 – Expressions, Equations, and Functions Algebra I A - Meeting 1 Evaluate Algebraic Expressions 721/3Division21 divided by d21/d 155(3)Multiplication5 times c5(c) 6+3x3(2+x)Distributionf times the quantity (2 plus x)f(2+x) 9(3) 2 or (3)(3) Powerse raised to the power 2(e) 2 58 – 3Subtraction8 minus b8 - b 93 + 6Additiona plus 6a + 6 Answer Substitute 3 for the variable OperationMeaningAlgebraic Expressions Section 1.1 - Evaluate Expressions Variable – is a letter used to represent a number

2. Chapter 1 – Expressions, Equations, and Functions Algebra I A - Meeting 1 The point total, T is given by n + a, where a is the number of assists. Section 1.1 - Evaluate Expressions WORD PROBLEM Jen was the leading scorer on her soccer team. She scored 120 goals and had 20 assists in her high school career. The number n of points awarded for goals is given by 2g, where g is the number of goals scored. a) How many points did Jen earn for goals? n = 2 g n = 2 (120) n = 240 points a) How many total points did Jen for the season? T = n + a T = 240 + 20 T = 260 points

3. Chapter 1 – Expressions, Equations, and Functions Algebra I A - Meeting 1 Section 1.2 – Apply Order of Operations 35 – 2 * 3 2 Class Example # 1: Evaluate the expression 35 - X X = 2 * 3 2 X = 2 * 9 X = 18 35 - 18 17 Substitution X for 2 * 3 2 Evaluate for X Evaluate the exponent Multiply the constant Subtract the known X Answer Allowing for Subtraction Substitute back in for X 35 – 2 * 3 2 = 17

4. Chapter 1 – Expressions, Equations, and Functions Algebra I A - Meeting 1 Section 1.2 – Apply Order of Operations 3(8 – 2 2 ) + 17 Class Example # 2: Evaluate the expression Y + 17 Y = 3(8 – 2 2 ) Z = 8 – 2 2 Z = 8 – 4 Z = 4 Y = 3(4) Substitute Y for 3(8 – 2 2 ) Evaluate for Y Substitute Z for (8 – 2 2 ) Evaluate the exponent Substitute back in for Z Distribute (Multiply) Subtract 3(8 – 2 2 ) + 17 = 29 Evaluate for Z Y = 3(Z) Evaluate for Y Y = 12 Substitute back in for Y Evaluate12 + 17 = 29

5. Chapter 1 – Expressions, Equations, and Functions Algebra I A - Meeting 1 Section 1.2 – Apply Order of Operations Substitute X for 2 [ 54 / (4 2 + 2) ] Class Example # 3: Evaluate the expression X = 2[Y] Y = [54 / Z] Evaluate for Z Z = R + 2 8 – X Evaluate for X Evaluate for R Substitute R for 4 2 8 – 2 [ 54 / (4 2 + 2) ] = 2 Evaluate for Y 8 – 2 [ 54 / (4 2 + 2) ] Substitute Y for [54 / (4 2 + 2) ] X = 2 [ 54 / (4 2 + 2) ] Y = [ 54 / (4 2 + 2) ] Substitute Z for (4 2 + 2) Z = 4 2 + 2 R = 4 2 R = 16 Z = 16 + 2 Z = 18 Y = [54 / 18] Y = 3 X = 2[3] X = 6 Substitute the variable(s) back into the previous expression(s)

6. Chapter 1 – Expressions, Equations, and Functions Algebra I A - Meeting 1 Lean body mass is measured in units called BMI (Body Mass Index) units Section 1.2 – Apply Order of Operations Graphing Calculator Exercise Lean body mass is the mass of the skeleton, muscle and organs. Physicians use lean body mass to determine dosages of medicine. Scientists have developed separate formulas for the lean body masses of men and women based on their mass m (in kilograms) and height (in meters). Men : a) Find the lean body mass (in BMI units) of a Matt, who is 1.8 meters tall and has a mass of 80 kilograms? BMI of Matt = 62.7 BMI units Women : b) Find the lean body mass (in BMI units) of a Kristen, who is 1.5 meters tall and has a mass of 70 kilograms? BMI of Kristen = 42.7 BMI units c) Find the following Celebrities BMI ?

7. Chapter 1 – Expressions, Equations, and Functions Algebra I A - Meeting 1 Celebrity Body Mass Index 4 53.990.71.68Oprah Winfrey 3 61.674.81.86Barack Obama 6 38.247.21.64Miley Cyrus 2 71.5 90.71.93Michael Phelps 1 102.5147.42.16Shaquille O’Neal 5 46.660.51.73Paris Hilton Ranking Body Mass IndexWeight (kilograms) Height (meters) Celebrity Section 1.2 – Apply Order of Operations

8. Chapter 1 – Expressions, Equations, and Functions Algebra I A - Meeting 1 Homework # 1 pg 5 # 3-51 multiples of 3 (Hint: 3,6,9,12,15,18,…,48,51) pg 10 # 4-36 multiples of 4 (Hint: 4,8,12,16,20,24,28,32,36) Section 1.1 & 1.2