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Speech and Language Processing Lecture 4 Chapter 4 of SLP
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03/26/10 Speech and Language Processing - Jurafsky and Martin 2 Today Word prediction task Language modeling (N-grams) N-gram intro The chain rule Model evaluation Smoothing
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03/26/10 Speech and Language Processing - Jurafsky and Martin 3 Word Prediction Guess the next word... ... I notice three guys standing on the ??? There are many sources of knowledge that can be used to inform this task, including arbitrary world knowledge. But it turns out that you can do pretty well by simply looking at the preceding words and keeping track of some fairly simple counts.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 4 Word Prediction We can formalize this task using what are called N-gram models. N-grams are token sequences of length N. Our earlier example contains the following 2-grams (aka bigrams) (I notice), (notice three), (three guys), (guys standing), (standing on), (on the) Given knowledge of counts of N-grams such as these, we can guess likely next words in a sequence.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 5 N-Gram Models More formally, we can use knowledge of the counts of N-grams to assess the conditional probability of candidate words as the next word in a sequence. Or, we can use them to assess the probability of an entire sequence of words. Pretty much the same thing as we’ll see...
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03/26/10 Speech and Language Processing - Jurafsky and Martin 6 Applications It turns out that being able to predict the next word (or any linguistic unit) in a sequence is an extremely useful thing to be able to do. As we’ll see, it lies at the core of the following applications Automatic speech recognition Handwriting and character recognition Spelling correction Machine translation And many more.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 7 Counting Simple counting lies at the core of any probabilistic approach. So let’s first take a look at what we’re counting. He stepped out into the hall, was delighted to encounter a water brother. 13 tokens, 15 if we include “,” and “.” as separate tokens. Assuming we include the comma and period, how many bigrams are there?
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03/26/10 Speech and Language Processing - Jurafsky and Martin 8 Counting Not always that simple I do uh main- mainly business data processing Spoken language poses various challenges. Should we count “uh” and other fillers as tokens? What about the repetition of “mainly”? Should such do- overs count twice or just once? The answers depend on the application. If we’re focusing on something like ASR to support indexing for search, then “uh” isn’t helpful (it’s not likely to occur as a query). But filled pauses are very useful in dialog management, so we might want them there.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 9 Counting: Types and Tokens How about They picnicked by the pool, then lay back on the grass and looked at the stars. 18 tokens (again counting punctuation) But we might also note that “the” is used 3 times, so there are only 16 unique types (as opposed to tokens). In going forward, we’ll have occasion to focus on counting both types and tokens of both words and N-grams.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 10 Counting: Wordforms Should “cats” and “cat” count as the same when we’re counting? How about “geese” and “goose”? Some terminology: Lemma: a set of lexical forms having the same stem, major part of speech, and rough word sense Wordform: fully inflected surface form Again, we’ll have occasion to count both lemmas and wordforms
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03/26/10 Speech and Language Processing - Jurafsky and Martin 11 Counting: Corpora So what happens when we look at large bodies of text instead of single utterances? Brown et al (1992) large corpus of English text 583 million wordform tokens 293,181 wordform types Google Crawl of 1,024,908,267,229 English tokens 13,588,391 wordform types That seems like a lot of types... After all, even large dictionaries of English have only around 500k types. Why so many here? Numbers Misspellings Names Acronyms etc
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03/26/10 Speech and Language Processing - Jurafsky and Martin 12 Language Modeling Back to word prediction We can model the word prediction task as the ability to assess the conditional probability of a word given the previous words in the sequence P(w n |w 1,w 2 …w n-1 ) We’ll call a statistical model that can assess this a Language Model
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03/26/10 Speech and Language Processing - Jurafsky and Martin 13 Language Modeling How might we go about calculating such a conditional probability? One way is to use the definition of conditional probabilities and look for counts. So to get P(the | its water is so transparent that) By definition that’s P(its water is so transparent that the) P(its water is so transparent that) We can get each of those from counts in a large corpus.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 14 Very Easy Estimate How to estimate? P(the | its water is so transparent that) P(the | its water is so transparent that) = Count(its water is so transparent that the) Count(its water is so transparent that)
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03/26/10 Speech and Language Processing - Jurafsky and Martin 15 Very Easy Estimate According to Google those counts are 5/9. Unfortunately... 2 of those were to these slides... So maybe it’s really 3/7 In any case, that’s not terribly convincing due to the small numbers involved.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 16 Language Modeling Unfortunately, for most sequences and for most text collections we won’t get good estimates from this method. What we’re likely to get is 0. Or worse 0/0. Clearly, we’ll have to be a little more clever. Let’s use the chain rule of probability And a particularly useful independence assumption.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 17 The Chain Rule Recall the definition of conditional probabilities Rewriting: For sequences... P(A,B,C,D) = P(A)P(B|A)P(C|A,B)P(D|A,B,C) In general P(x 1,x 2,x 3,…x n ) = P(x 1 )P(x 2 |x 1 )P(x 3 |x 1,x 2 )…P(x n |x 1 …x n-1 )
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03/26/10 Speech and Language Processing - Jurafsky and Martin 18 The Chain Rule P(its water was so transparent)= P(its)* P(water|its)* P(was|its water)* P(so|its water was)* P(transparent|its water was so)
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03/26/10 Speech and Language Processing - Jurafsky and Martin 19 Unfortunately There are still a lot of possible sentences In general, we’ll never be able to get enough data to compute the statistics for those longer prefixes Same problem we had for the strings themselves
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03/26/10 Speech and Language Processing - Jurafsky and Martin 20 Independence Assumption Make the simplifying assumption P(lizard|the,other,day,I,was,walking,along,an d,saw,a) = P(lizard|a) Or maybe P(lizard|the,other,day,I,was,walking,along,an d,saw,a) = P(lizard|saw,a) That is, the probability in question is independent of its earlier history.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 21 Independence Assumption This particular kind of independence assumption is called a Markov assumption after the Russian mathematician Andrei Markov.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 22 So for each component in the product replace with the approximation (assuming a prefix of N) Bigram version Markov Assumption
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03/26/10 Speech and Language Processing - Jurafsky and Martin 23 Estimating Bigram Probabilities The Maximum Likelihood Estimate (MLE)
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03/26/10 Speech and Language Processing - Jurafsky and Martin 24 An Example I am Sam Sam I am I do not like green eggs and ham
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03/26/10 Speech and Language Processing - Jurafsky and Martin 25 Maximum Likelihood Estimates The maximum likelihood estimate of some parameter of a model M from a training set T Is the estimate that maximizes the likelihood of the training set T given the model M Suppose the word Chinese occurs 400 times in a corpus of a million words (Brown corpus) What is the probability that a random word from some other text from the same distribution will be “Chinese” MLE estimate is 400/1000000 =.004 This may be a bad estimate for some other corpus But it is the estimate that makes it most likely that “Chinese” will occur 400 times in a million word corpus.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 26 Berkeley Restaurant Project Sentences can you tell me about any good cantonese restaurants close by mid priced thai food is what i’m looking for tell me about chez panisse can you give me a listing of the kinds of food that are available i’m looking for a good place to eat breakfast when is caffe venezia open during the day
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03/26/10 Speech and Language Processing - Jurafsky and Martin 27 Bigram Counts Out of 9222 sentences Eg. “I want” occurred 827 times
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03/26/10 Speech and Language Processing - Jurafsky and Martin 28 Bigram Probabilities Divide bigram counts by prefix unigram counts to get probabilities.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 29 Bigram Estimates of Sentence Probabilities P( I want english food ) = P(i| )* P(want|I)* P(english|want)* P(food|english)* P( |food)* =.000031
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03/26/10 Speech and Language Processing - Jurafsky and Martin 30 Kinds of Knowledge P(english|want) =.0011 P(chinese|want) =.0065 P(to|want) =.66 P(eat | to) =.28 P(food | to) = 0 P(want | spend) = 0 P (i | ) =.25 As crude as they are, N-gram probabilities capture a range of interesting facts about language. World knowledge Syntax Discourse
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03/26/10 Speech and Language Processing - Jurafsky and Martin 31 Shannon’s Method Assigning probabilities to sentences is all well and good, but it’s not terribly illuminating. A more interesting task is to turn the model around and use it to generate random sentences that are like the sentences from which the model was derived. Generally attributed to Claude Shannon.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 32 Shannon’s Method Sample a random bigram (, w) according to its probability Now sample a random bigram (w, x) according to its probability Where the prefix w matches the suffix of the first. And so on until we randomly choose a (y, ) Then string the words together I I want want to to eat eat Chinese Chinese food food
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03/26/10 Speech and Language Processing - Jurafsky and Martin 33 Shakespeare
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03/26/10 Speech and Language Processing - Jurafsky and Martin 34 Shakespeare as a Corpus N=884,647 tokens, V=29,066 Shakespeare produced 300,000 bigram types out of V 2 = 844 million possible bigrams... So, 99.96% of the possible bigrams were never seen (have zero entries in the table) This is the biggest problem in language modeling; we’ll come back to it. Quadrigrams are worse: What's coming out looks like Shakespeare because it is Shakespeare
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03/26/10 Speech and Language Processing - Jurafsky and Martin 35 The Wall Street Journal is Not Shakespeare
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03/26/10 Speech and Language Processing - Jurafsky and Martin 36 Evaluation How do we know if our models are any good? And in particular, how do we know if one model is better than another. Well Shannon’s game gives us an intuition. The generated texts from the higher order models sure look better. That is, they sound more like the text the model was obtained from. But what does that mean? Can we make that notion operational?
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03/26/10 Speech and Language Processing - Jurafsky and Martin 37 Evaluation Standard method Train parameters of our model on a training set. Look at the models performance on some new data This is exactly what happens in the real world; we want to know how our model performs on data we haven’t seen So use a test set. A dataset which is different than our training set, but is drawn from the same source Then we need an evaluation metric to tell us how well our model is doing on the test set. One such metric is perplexity (to be introduced below)
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03/26/10 Speech and Language Processing - Jurafsky and Martin 38 Unknown Words But once we start looking at test data, we’ll run into words that we haven’t seen before (pretty much regardless of how much training data you have. With an Open Vocabulary task Create an unknown word token Training of probabilities Create a fixed lexicon L, of size V From a dictionary or A subset of terms from the training set At text normalization phase, any training word not in L changed to Now we count that like a normal word At test time Use UNK counts for any word not in training
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03/26/10 Speech and Language Processing - Jurafsky and Martin 39 Perplexity Perplexity is the probability of the test set (assigned by the language model), normalized by the number of words: Chain rule: For bigrams: Minimizing perplexity is the same as maximizing probability The best language model is one that best predicts an unseen test set
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03/26/10 Speech and Language Processing - Jurafsky and Martin 40 Lower perplexity means a better model Training 38 million words, test 1.5 million words, WSJ
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03/26/10 Speech and Language Processing - Jurafsky and Martin 41 Evaluating N-Gram Models Best evaluation for a language model Put model A into an application For example, a speech recognizer Evaluate the performance of the application with model A Put model B into the application and evaluate Compare performance of the application with the two models Extrinsic evaluation
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03/26/10 Speech and Language Processing - Jurafsky and Martin 42 Difficulty of extrinsic (in-vivo) evaluation of N-gram models Extrinsic evaluation This is really time-consuming Can take days to run an experiment So As a temporary solution, in order to run experiments To evaluate N-grams we often use an intrinsic evaluation, an approximation called perplexity But perplexity is a poor approximation unless the test data looks just like the training data So is generally only useful in pilot experiments (generally is not sufficient to publish) But is helpful to think about.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 43 Zero Counts Back to Shakespeare Recall that Shakespeare produced 300,000 bigram types out of V 2 = 844 million possible bigrams... So, 99.96% of the possible bigrams were never seen (have zero entries in the table) Does that mean that any sentence that contains one of those bigrams should have a probability of 0?
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03/26/10 Speech and Language Processing - Jurafsky and Martin 44 Zero Counts Some of those zeros are really zeros... Things that really can’t or shouldn’t happen. On the other hand, some of them are just rare events. If the training corpus had been a little bigger they would have had a count (probably a count of 1!). Zipf’s Law (long tail phenomenon): A small number of events occur with high frequency A large number of events occur with low frequency You can quickly collect statistics on the high frequency events You might have to wait an arbitrarily long time to get valid statistics on low frequency events Result: Our estimates are sparse! We have no counts at all for the vast bulk of things we want to estimate! Answer: Estimate the likelihood of unseen (zero count) N-grams!
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03/26/10 Speech and Language Processing - Jurafsky and Martin 45 Laplace Smoothing Also called add-one smoothing Just add one to all the counts! Very simple MLE estimate: Laplace estimate: Reconstructed counts:
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03/26/10 Speech and Language Processing - Jurafsky and Martin 46 Laplace-Smoothed Bigram Counts
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03/26/10 Speech and Language Processing - Jurafsky and Martin 47 Laplace-Smoothed Bigram Probabilities
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03/26/10 Speech and Language Processing - Jurafsky and Martin 48 Reconstituted Counts
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03/26/10 Speech and Language Processing - Jurafsky and Martin 49 Big Change to the Counts! C(count to) went from 608 to 238! P(to|want) from.66 to.26! Discount d= c*/c d for “chinese food” =.10!!! A 10x reduction So in general, Laplace is a blunt instrument Could use more fine-grained method (add-k) But Laplace smoothing not used for N-grams, as we have much better methods Despite its flaws Laplace (add-k) is however still used to smooth other probabilistic models in NLP, especially For pilot studies in domains where the number of zeros isn’t so huge.
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03/26/10 Speech and Language Processing - Jurafsky and Martin 50 Better Smoothing Intuition used by many smoothing algorithms Good-Turing Kneser-Ney Witten-Bell Is to use the count of things we’ve seen once to help estimate the count of things we’ve never seen
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03/26/10 Speech and Language Processing - Jurafsky and Martin 51 Good-Turing Josh Goodman Intuition Imagine you are fishing There are 8 species: carp, perch, whitefish, trout, salmon, eel, catfish, bass You have caught 10 carp, 3 perch, 2 whitefish, 1 trout, 1 salmon, 1 eel = 18 fish How likely is it that the next fish caught is from a new species (one not seen in our previous catch)? 3/18 Assuming so, how likely is it that next species is trout? Must be less than 1/18 Slide adapted from Josh Goodman
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03/26/10 Speech and Language Processing - Jurafsky and Martin 52 Good-Turing Notation: N x is the frequency-of-frequency-x So N 10 =1 Number of fish species seen 10 times is 1 (carp) N 1 =3 Number of fish species seen 1 is 3 (trout, salmon, eel) To estimate total number of unseen species Use number of species (words) we’ve seen once c 0 * =c 1 p 0 = N 1 /N All other estimates are adjusted (down) to give probabilities for unseen Slide from Josh Goodman
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03/26/10 Speech and Language Processing - Jurafsky and Martin 53 Good-Turing Intuition Notation: N x is the frequency-of-frequency-x So N 10 =1, N 1 =3, etc To estimate total number of unseen species Use number of species (words) we’ve seen once c 0 * =c 1 p 0 = N 1 /Np 0 =N 1 /N=3/18 All other estimates are adjusted (down) to give probabilities for unseen P(eel) = c*(1) = (1+1) 1/ 3 = 2/3 Slide from Josh Goodman
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03/26/10 Speech and Language Processing - Jurafsky and Martin 54 GT Fish Example
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03/26/10 Speech and Language Processing - Jurafsky and Martin 55 Bigram Frequencies of Frequencies and GT Re-estimates
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03/26/10 Speech and Language Processing - Jurafsky and Martin 56 Complications In practice, assume large counts (c>k for some k) are reliable: That complicates c*, making it: Also: we assume singleton counts c=1 are unreliable, so treat N- grams with count of 1 as if they were count=0 Also, need the Nk to be non-zero, so we need to smooth (interpolate) the Nk counts before computing c* from them
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03/26/10 Speech and Language Processing - Jurafsky and Martin 57 Backoff and Interpolation Another really useful source of knowledge If we are estimating: trigram p(z|x,y) but count(xyz) is zero Use info from: Bigram p(z|y) Or even: Unigram p(z) How to combine this trigram, bigram, unigram info in a valid fashion?
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03/26/10 Speech and Language Processing - Jurafsky and Martin 58 Backoff Vs. Interpolation Backoff: use trigram if you have it, otherwise bigram, otherwise unigram Interpolation: mix all three
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03/26/10 Speech and Language Processing - Jurafsky and Martin 59 Interpolation Simple interpolation Lambdas conditional on context:
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03/26/10 Speech and Language Processing - Jurafsky and Martin 60 How to Set the Lambdas? Use a held-out, or development, corpus Choose lambdas which maximize the probability of some held-out data I.e. fix the N-gram probabilities Then search for lambda values That when plugged into previous equation Give largest probability for held-out set Can use EM to do this search
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03/26/10 Speech and Language Processing - Jurafsky and Martin 61 Katz Backoff
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03/26/10 Speech and Language Processing - Jurafsky and Martin 62 Why discounts P* and alpha? MLE probabilities sum to 1 So if we used MLE probabilities but backed off to lower order model when MLE prob is zero We would be adding extra probability mass And total probability would be greater than 1
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03/26/10 Speech and Language Processing - Jurafsky and Martin 63 GT Smoothed Bigram Probabilities
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03/26/10 Speech and Language Processing - Jurafsky and Martin 64 Intuition of Backoff+Discounting How much probability to assign to all the zero trigrams? Use GT or other discounting algorithm to tell us How to divide that probability mass among different contexts? Use the N-1 gram estimates to tell us What do we do for the unigram words not seen in training? Out Of Vocabulary = OOV words
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03/26/10 Speech and Language Processing - Jurafsky and Martin 65 OOV words: word Out Of Vocabulary = OOV words We don’t use GT smoothing for these Because GT assumes we know the number of unseen events Instead: create an unknown word token Training of probabilities Create a fixed lexicon L of size V At text normalization phase, any training word not in L changed to Now we train its probabilities like a normal word At decoding time If text input: Use UNK probabilities for any word not in training
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03/26/10 Speech and Language Processing - Jurafsky and Martin 66 Practical Issues We do everything in log space Avoid underflow (also adding is faster than multiplying)
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03/26/10 Speech and Language Processing - Jurafsky and Martin 67 Google N-Gram Release
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03/26/10 Speech and Language Processing - Jurafsky and Martin 68 Google N-Gram Release serve as the incoming 92 serve as the incubator 99 serve as the independent 794 serve as the index 223 serve as the indication 72 serve as the indicator 120 serve as the indicators 45 serve as the indispensable 111 serve as the indispensible 40 serve as the individual 234
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03/26/10 Speech and Language Processing - Jurafsky and Martin 69 Google Caveat Remember the lesson about test sets and training sets... Test sets should be similar to the training set (drawn from the same distribution) for the probabilities to be meaningful. So... The Google corpus is fine if your application deals with arbitrary English text on the Web. If not then a smaller domain specific corpus is likely to yield better results.
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