1. Prof. David R. Jackson Dept. of ECE Notes 7 ECE 5317-6351 Microwave Engineering Fall 2015 Waveguides Part 4: Rectangular and Circular Waveguide 1

2.  One of the earliest waveguides.  Still common for high power and low- loss microwave / millimeter-wave applications. Rectangular Waveguide  It is essentially an electromagnetic pipe with a rectangular cross-section. Single conductor  No TEM mode For convenience  a  b.  The long dimension lies along x. 2 y z a b x  PEC

3. Recall: where Subject to B.C.’s: TE z Modes 3 From previous table: y z a b x  PEC

4. Using separation of variables, let Must be a constant where Separation equation TE z Modes (cont.) (eigenvalue problem) 4

5. Hence, Boundary Conditions: B A A B TE z Modes (cont.) 5

6. Therefore, From the previous field-representation equations, we can obtain the following: But m = n = 0 is not allowed! (non-physical solution) Note: m = 0,1,2,… n = 0,1,2,… 6 TE z Modes (cont.)

7.  TE mn mode is at cutoff when Lossless case Lowest cutoff frequency is for TE 10 mo d e ( a > b ) Dominant TE mode (lowest f c ) We will revisit this mode later. 7 TE z Modes (cont.)

8. At the cutoff frequency of the TE 10 mode (lossless waveguide): For a given frequency (with f > f c ), the dimension a must be at least d / 2 in order for the TE 10 mode to propagate. Example: Air-filled waveguide, f = 10 GHz. We have that a > 3.0 cm/2 = 1.5 cm. 8 TE z Modes (cont.) so

9. Recall: where Subject to B.C.’s: Thus, following same procedure as before, we have the following result: TM z Modes (eigenvalue problem) 9 y z a b x  PEC

10. Boundary Conditions: B A A B TM z Modes (cont.) 10

11. Therefore m =1,2,3,… n =1,2,3,… From the previous field-representation equations, we can obtain the following: Note: If either m or n is zero, the field becomes a trivial one in the TM z case. 11 TM z Modes (cont.)

12. The lowest cutoff frequency is obtained for the TM 11 mode (same as for TE modes) Lossless case Dominant TM mode (lowest f c ) 12 TM z Modes (cont.)

13. The maximum band for single mode operation is f c 10 [Hz] (67% bandwidth). b < a / 2 b > a / 2 f f Single mode operation a > b Mode Chart Two cases are considered: 13 Lossless case y z a b x  PEC

14. Dominant Mode: TE 10 Mode For this mode we have Hence we have 14 y z a b x  PEC

15. Phase velocity: Group velocity: Dispersion Diagram for TE 10 Mode Lossless case (“Light line”) Velocities are slopes on the dispersion plot. 15

16. Top view End view Side view Field Plots for TE 10 Mode 16 y z a b x  PEC

17. Top view End view Side view Field Plots for TE 10 Mode (cont.) 17 y z a b x  PEC

18. Time-average power flow in the z direction for +z mode: In terms of amplitude of the field amplitude, we have For a given maximum electric field level (e.g., the breakdown field), the power is increased by increasing the cross-sectional area ( ab ). Power Flow for TE 10 Mode Note: 18

19. Recall (calculated on previous slide) on conductor Side walls Attenuation for TE 10 Mode 19 y z a b x PEC C

20. Top and bottom walls (since fields of this mode are independent of y ) Attenuation for TE 10 Mode (cont.) 20 y z a b x PEC C

21. Attenuation for TE 10 Mode (cont.) Simplify, using Final result: Assume f > f c (The wavenumber is taken as that of a guide with perfect walls.) 21 y z a b x  PEC

22. Attenuation in dB/m dB/m = 8.686  c [np/m] Hence Let z = distance down the guide in meters. 22 y z a b x  PEC

23. Attenuation for TE 10 Mode (cont.) Brass X-band air-filled waveguide (See the table on the next slide.) 23 a = 2.0 cm (from the Pozar book)

24. Attenuation for TE 10 Mode (cont.) Microwave Frequency Bands Letter DesignationFrequency range L band 1 to 2 GHz S band 2 to 4 GHz C band 4 to 8 GHz X band 8 to 12 GHz Ku band 12 to 18 GHz K band 18 to 26.5 GHz Ka band 26.5 to 40 GHz Q band 33 to 50 GHz U band 40 to 60 GHz V band 50 to 75 GHz E band 60 to 90 GHz W band 75 to 110 GHz F band 90 to 140 GHz D band 110 to 170 GHz (from Wikipedia) 24

25. Mode f c [GHz] 50 mil (0.05”) thickness Modes in an X-Band Waveguide “Standard X-band waveguide” (WR90) 25

26. Determine , , and g (as appropriate) at 10 GHz and 6 GHz for the TE 10 mode in an air-filled waveguide. Example: X-Band Waveguide 26

27. Evanescent mode:  = 0 ; g is not defined! Example: X-Band Waveguide (cont.) 27

28. Circular Waveguide TM z mode: The solution in cylindrical coordinates is: Note: The value n must be an integer to have unique fields. 28 a z  PEC

29. Plot of Bessel Functions x J n (x) n = 0 n = 1 n = 2 29

30. Plot of Bessel Functions (cont.) x Y n (x) n = 0 n = 1 n = 2 30

31. Circular Waveguide (cont.) Choose (somewhat arbitrarily) The field should be finite on the z axis is not allowed 31 Hence, we have

32. B.C.’s: Circular Waveguide (cont.) xn1xn1 xn2xn2 xn3xn3 x Jn(x)Jn(x) Hence Note: The value x n0 = 0 is not included since this would yield a trivial solution: Sketch for a typical value of n (n  0). Note: Pozar uses the notation p mn. 32 This is true unless n = 0, in which case we cannot have p = 0.

33. TM np mode: Circular Waveguide (cont.) 33

34. Cutoff Frequency: TM z At f = f c : 34

35. Cutoff Frequency: TM z (cont.) TM 01, TM 1 1, TM 21, TM 02, …….. p \ n012345 12.4053.8325.1366.3807.5888.771 25.5207.0168.4179.76111.06512.339 38.65410.17311.62013.01514.372 411.79213.32414.796 x np values 35

36. TE z Modes Proceeding as before, we now have that Set (From Ampere’s law) Hence 36 The prime denotes derivative with respect to the argument.

37. x' n1 x' n2 x' n3 x J n ' (x) TE z Modes (cont.) Sketch for a typical value of n (n  1). We don’t need to consider p = 0 ; this is explained on the next slide. 37

38. TE z Modes (cont.) Note: If p = 0 (trivial solution) (nonphysical solution) We then have, for p = 0 : (The TE 00 mode is not physical.) 38

39. Cutoff Frequency: TE z Hence 39

40. TE 11, TE 21, TE 01, TE 31, …….. p \ n012 345 13.8321.8413.0544.2015.3175.416 27.0165.3316.7068.0159.28210.520 310.1738.5369.96911.34612.68213.987 413.32411.70613.170 x´ np values Cutoff Frequency: TE z 40

41. TE 11 Mode TE 10 mode of rectangular waveguide TE 11 mode of circular waveguide The dominant mode of circular waveguide is the TE 11 mode. The mode can be thought of as an evolution of the TE 10 mode of rectangular waveguide as the boundary changes shape. Electric field Magnetic field (From Wikipedia) 41

42. TE 11 Mode The attenuation due to conductor loss for the TE 11 mode is: 42 The derivation is in the Pozar book (see Eq. 3.133).

43. TE 01 Mode The TE 01 mode has the unusual property that the conductor attenuation decreases with frequency. (With most waveguide modes, the conductor attenuation increases with frequency.) The TE 01 mode was studied extensively as a candidate for long- range communications – but eventually fiber-optic cables became available with even lower loss. It is still useful for some high-power applications. 43 Note: This mode is not the dominant mode!

44. f c, TE 11 f cc f c, TM 01 f c, TE 21 f c, TE 01 TE 01 TE 21 TE 11 TM 11 TM 01 TE 01 Mode (cont.) 44 P 0 = 0 at cutoff

45. TE 01 Mode (cont.) Practical Note: The TE 01 mode has only an azimuthal (  - directed) surface current on the wall of the waveguide. Therefore, it can be supported by a set of conducting rings, while the lower modes (TE 11,TM 01, TE 21, TM 11 ) will not propagate on such a structure. (A helical spring will also work fine.) 45

46. 46 Products include: 4-Port Diplexers, CP or Linear; 3-Port Diplexers, 2xRx & 1xTx; 2-Port Diplexers, RxTx, X-Pol or Co-Pol, CP or Linear; TE21 Monopulse Tracking Couplers; TE01 Mode Components; Transitions; Filters; Flex Waveguides; Waveguide Bends; Twists; Runs; etc. Many of the items are "off the shelf products". Products can be custom tailored to a customer's application. Many of the products can be supplied with standard feed horns for prime or offset antennas. VertexRSI's Torrance Facility is a leading supplier of antenna feed components for the various commercial and military bands. A patented circular polarized 4-port diplexer meeting all Intelsat specifications leads a full array of products. TE 01 Mode (cont.)

47. From the beginning, the most obvious application of waveguides had been as a communications medium. It had been determined by both Schelkunoff and Mead, independently, in July 1933, that an axially symmetric electric wave (TE 01 ) in circular waveguide would have an attenuation factor that decreased with increasing frequency [44]. This unique characteristic was believed to offer a great potential for wide-band, multichannel systems, and for many years to come the development of such a system was a major focus of work within the waveguide group at BTL. It is important to note, however, that the use of waveguide as a long transmission line never did prove to be practical, and Southworth eventually began to realize that the role of waveguide would be somewhat different than originally expected. In a memorandum dated October 23, 1939, he concluded that microwave radio with highly directive antennas was to be preferred to long transmission lines. "Thus," he wrote, “we come to the conclusion that the hollow, cylindrical conductor is to be valued primarily as a new circuit element, but not yet as a new type of toll cable” [45]. It was as a circuit element in military radar that waveguide technology was to find its first major application and to receive an enormous stimulus to both practical and theoretical advance. K. S. Packard, “The origins of waveguide: A case of multiple rediscovery,” IEEE Trans. Microwave Theory and Techniques, pp. 961-969, Sept. 1984. TE 01 Mode (cont.) 47

48. Comparison of Waveguide with Wireless System (Two Antennas) 48 Waveguide: Antenna:  For small distances, the waveguide delivers more power (no spreading).  For large distances, the antenna (wireless) system will deliver more power. (spreading spherical wave) (attenuating wave)

49. Wireless System (Two Antennas) 49 Two antennas (transmit and receive): (from antenna theory) Matched receive antenna: Here we examine a wireless system in more detail. Hence, we have: P t = power transmitted P r = power received A er = effective area of receive antenna Friis transmission formula

50. Wireless System (Two Antennas) (cont.) 50 Hence, we have: dB of attenuation: Friis transmission formula

51. dB Attenuation: Comparison of Waveguiding system with Wireless System 51 Waveguiding system: Wireless system: D = diameter

52. dB Attenuation: Comparison of Waveguiding System with Wireless System 52 DistanceCoaxFiberWireless 1 m0.40.000328.2NA 10 m40.00348.2NA 100 m400.0368.2NA 1 km4000.388.239.3 10 km-3108.259.3 100 km-30128.279.3 1000 km-300148.299.3 10,000 km--168.2119.3 100,000 km--188.2139.3 1,000,000 km--208.2159.3 10,000,000 km--228.2179.3 100,000,000 km--248.2199.3 RG59 1 GHz Single Mode Two Dipoles 34m Dish+Dipole