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Calculate the number of atoms of silicon in moles of silicon.

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Presentation on theme: "Calculate the number of atoms of silicon in moles of silicon."— Presentation transcript:

1 Calculate the number of atoms of silicon in 0.367 moles of silicon.
6.10 x atoms Si 2.21 x atoms Si 2.21 atoms Si 1.64 x atoms Si What do you need ? Avogadro’s Number 1 mole = 6.02 x atoms 0.367 mol x x atoms / 1 mol = 2.21 x atoms Si

2 Calculate the molar mass of potassium phosphate.
134 g/mol 86.07 g/mol g/mol g/mol What do you need ? 1) Formula of potassium phosphate: K3PO4 2) Atomic Weights (molar mass) K = 39.10, P = 30.97, O = 16.00 3(39.10) (16.00) = g/mol

3 Calculate the mass in grams of 4.00 moles of sulfur.
What do you need ? Atomic Weight sulfur (S) = 32.07 (molar mass) = g/mol 4 mol sulfur x g/mol sulfur = 128.3 g

4 How many moles is 146.3 grams of nickel?
What do you need ? Atomic Weight (Ni) = 58.69 (molar mass Ni) = g/1 mol 146.3 g Ni x 1 mol Ni / g Ni = 2.493 mol

5 Calculate the molar mass of methane gas if 1
Calculate the molar mass of methane gas if 1.00 g of methane occupies a volume of 1.39 L at STP. 22.4 g/mol 16.1 g/mol 1.39 g/mol 0.719 g/mol What do you need ? 1 mole of a STP = 22.4 L 1 mol / 22.4 L = x mol / 1.39 L x mol = 1.39 L . mol / 22.4 L x mol = mol 1.00 g / mol = 16.1 g/mol

6 Calculate the percentage composition for all the elements in nicotine, C10H14N2.
What do you need ? Molar mass C10H14N2 C = 12.01, H = 1.01, N = 14.01 10(12.01) + 14(1.01) + 2(14.01) = g/mol 120.1g/mol g/mol g/mol 120.1/ / / x 100 = x 100 = x 100 = 74.02% % %

7 Freon was used commonly as a refrigerant until CFCs were found to deplete the ozone layer. An analysis of freon gave the following data: 9.93% carbon, 58.64% chlorine, and 31.43% fluorine. What is the empirical formula of freon, CxClyFz? What do you need ? Atomic masses: C = 12.01, Cl = 35.45, F = 19.00 Calculate respective moles: 9.93g/12.01 g/mol * g/ g/mol * g /19.00 g/mol 0.827mol mol mol CxClyFz = C0.827Cl1.654 F1.654 C1Cl2F2 CCl2F2

8 In an experiment, 5. 00 g of tungsten reacts with air to give 6
In an experiment, 5.00 g of tungsten reacts with air to give 6.31 g of tungsten oxide. What is the empirical formula of tungsten oxide? W3O W5O WO WO What do you need ? Equation for Reaction: x W(s) + y/2 O 2 (g) WxOy (s) Mass of O2 6.31 g g = 1.31g Atomic masses: W = , O = 16.00 Calculate respective moles: 5.00/ g/mol * g /16.00 g/mol 0.0272mol mol WxOy = W O W1 O 3.01 W O 3

9 A student calculated the relative number of moles for several different compounds as follows. What are the correct empirical formulas? Al1 O 1.511 Al2 O 3 aluminum oxide K3.012P1O3.973 K3PO4 potassium phosphate N1 O 2.501 N2 O5 dinitrogen pentoxide C1.002H1.331O1.006 C3H4O3 pyruvic acid C1.012H2.001O1.009 CH2O formaldehyde

10 A student calculated an empirical formula of CH2O for an unknown white solid. The solid could possibly be several different compounds: formaldehyde, lactic acid, erythrose, ribose or glucose. Mass spectrometry results indicated a molar mass of g/mol. What is the correct molecular formula of the solid? CH2O formaldehyde C3H6O3 lactic acid C4H8O4 erythrose C5H10O5 ribose C6H12O6 glucose What do you need ? Molar mass CH2O = g/mol C = 12.01, H = 1.01, O = 16.00 Compare molar masses: g/mol / g/mol = 3 3 x (C1H2O1) = C3H6O3 lactic acid

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