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Review Unit 7 (Chp 5,8,19): Thermodynamics (∆H, ∆S, ∆G, K) John D. Bookstaver St. Charles Community College St. Peters, MO 2006, Prentice Hall, Inc. Chemistry, The Central Science, 10th edition Theodore L. Brown; H. Eugene LeMay, Jr.; and Bruce E. Bursten
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Big Idea #5: Thermodynamics Chemical and physical processes are driven by: a decrease in enthalpy (–∆H), or an increase in entropy (+∆S), or both. Bonds break and form to lower free energy (∆G).
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ΔS = ΔH T ΔH = q (heat) (disorder) (microstates) (dispersal of matter & energy at T) ΔE = q + w PΔV = –w (at constant P) += Enthalpy (H) (kJ) Entropy (S) (J/K) Free Energy (G) (kJ) Energy (E) (energy of ΔH and ΔS at a T) (max work done by favorable rxn) ΔG = ΔH – TΔS (–∆G sys means +∆S univ & K>1) ΔH = ΔE + PΔV internal work by energy system (KE + PE) (–w)
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Enthalpy (∆H) Calculated 4 Ways 1)Bond Energies H rxn = (BE reactants ) (BE products ) 2)Hess’s Law H overall = H rxn1 + H rxn2 + H rxn3 … 3)Standard Heats of Formation (H f ) H = n H f(products) – n H f(reactants) 4)Calorimetry (lab) q = mc∆T (surroundings or thermometer) –q = ∆H ∆H/mol = kJ/mol (molar enthalpy) (+ broken)(– formed) (NOT) (given) (NOT) (given)
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S : dispersal of matter & energy at T (s) + ( l) (aq) solid gas VV more microstates H 2 O (g) TT S( s ) < S( l ) < S( aq ) < S( g ) Entropy (S) (Molecular Scale) Temperature Volume Particle mixing Particle number Particle size S o = n S o (products) – m S o (reactants) +∆S (dispersal) (given)
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Thermodynamically Favorable: (defined as) increasing entropy of the universe (∆S univ > 0) Thermodynamically Favorable ∆S univ > 0 (+Entropy of the Universe) S univ = S system + S surroundings > 0 (+)(+)(+)(+) Chemical and physical processes are driven by: decrease in enthalpy (–∆H sys ) increase in entropy (+∆S sys ) causes (+∆S surr )
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S universe = S system + (∆S univ ) & (∆G sys ) S universe = S system + S surroundings > 0 For all thermodynamically favorable reactions: multiplying each term by T: H system T –T S universe = –T S system + H system rearrange terms: –T S universe = H system – T S system (Boltzmann) (Clausius) G system = H system – T S system (Gibbs free energy equation)
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– G is thermodynamically favorable. Gibbs defined T S univ as the change in free energy of a system ( G sys ) or G. Free Energy ( G) is more useful than S univ b/c all terms focus on the system. If – G sys, then + S universe. Therefore… (∆S univ ) & (∆G sys ) –T S univ = H sys – T S sys G sys = H sys – T S sys (Gibbs free energy equation) “Bonds break & form to lower free energy (∆G).”
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Standard Free Energy (∆G o ) and Temperature (T) The temperature dependence of free energy comes from the entropy term (–T S ). G = H – T S (on equation sheet) enthalpy term (kJ/mol) entropy term (J/mol∙K) free energy (kJ/mol) energy transferred as heat energy dispersed as disorder max energy used for work (consists of 2 terms) units must match!!! (kJ)
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∆G o =(∆Ho)(∆Ho)∆So∆So ( ) – T ( ) G = H T S (high T) – (low T) + + – (high T) + (low T) – + – – + + + – – (unfav. at ALL T) (fav. at ALL T) (fav. at high T) (unfav. at low T) (unfav. at high T) (fav. at low T) – T( ) = = = = + + – – Standard Free Energy (∆G o ) and Temperature (T) Thermodynamic Favorability
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Calculating ∆G o (4 ways) 1)Standard free energies of formation, G f : 2)Gibbs Free Energy equation: 3)From K value (next few slides) 4)From voltage, E o (next Unit) G = nG (products) – mG (reactants) ff (given equation) G = H – T S (given equation) (may need to calc. ∆H o & ∆S o first) (given equation)
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Free Energy (∆G) & Equilibrium (K) G = –RT ln K K = e^ –∆G o RT (on equation sheet) (NOT on equation sheet) R = 8.314 J∙mol –1 ∙K –1 = 0.008314 kJ∙mol –1 ∙K –1 If G in kJ, then R in kJ……… Solved for K : –∆G o RT = ln K
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∆G o = –RT(ln K)K@ Equilibrium –RT ( ) > 1 < 1 – + product favored + – reactant favored (favorable forward) (unfavorable forward) = = G = –RT ln K Free Energy (∆G) & Equilibrium (K)
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