1. 1.Apply the design process including defining a problem, brainstorming, researching and generating ideas, identifying criteria and specifying constraints, exploring possibilities, selecting an approach, developing a design proposal, making a model or prototype, testing and evaluating a design, using specifications, refining a design, creating or making it, and communicating processes and results. 2.Select and use the appropriate tools and equipment in making two-dimensional and three-dimensional representations of design solutions, forming and molding processes, machining processes, and assembly processes. 3.Select and use tools and instruments in the testing and evaluation of design solutions. 4.Explain that technological problems require a multidisciplinary approach. (ITEA, STL 10-L) 5.Identify and describe applications of mechanical technology in the designed world such as levers, inclined planes, wedges, wheels and axles, pulleys, screws, gears, cams and linkages 6.Explain science concepts and mathematic processes applied in mechanical technology such as force, motion, energy, work, power, efficiency, gravity and friction

3. The systematic application of mathematical, scientific, and technical principles, to create useful machinery or products that make life easier.

4. To familiarize students with the functioning and applications of mechanical technology systems by having them analyze the functioning of mechanical systems in terms of their common components, basic system design, safety considerations, and simple controls.

5. Sketch the simple two- dimensional mechanisms on your work sheet. We will do the first one together. 1.Extend the Input and Output bars. 2.Determine the pivot point. This is the point that one of the bars will rotate around. 3.Determine the linkage point. This is the point which two or more bars are connected

6. There are several engineering resources (core technologies) that are the “building blocks” of all technology systems. Core Technologies Mechanical StructuralElectrical ElectronicThermal FluidOptical Bio-TechMaterial

7. The technology of putting together mechanical parts to produce, control, and transmit motion. Mechanical Technology – Example applications: gear systems in a car transmission, brakes on a bicycle, agitator in a washing machine, latch on a door.

8. Simple machines make our work easier. – We use less effort to move an object. All simple machines belong to one of two families –The lever family and the inclined plane family. There are six simple machines –lever, wheel and axle, pulley, wedge, inclined plane, and screw.

9. Transfer kinetic energy (the energy of motion) Reduce the effort needed to move a load Change the direction or amount of motion Change the type of motion (rotary to straight line)

10. Effort (E) = the input force Either the user or some type of engine supplies this force. Load (R) = the output force. Also known as the force resisting the motion.

11. Mechanical Advantage (MA) = a measure of how much effort is decreased by the simple machine. Mechanical Advantage = Load Effort MA = RERE

12. Work : The force applied on an object times the distance traveled by the object. Work = (Force)Distance = (F)d Starting Position Force Finishing Position Distance

13. Friction results from two bodies moving against each other in different directions. –Friction always opposes motion and makes doing work harder. –Lubricants (graphite, oil, grease, silicone) and bearings are used to combat friction. –Sometimes, friction is a good thing! Efficiency is the ratio of the work that results to the amount of work put into the machine.

14. Power is the rate at which work is performed. Energy describes the amount of work that can be performed by a force. P= WtWt E=W P = power W = work t = time E = energy

15. A lever is a stiff bar which rotates around a point called the fulcrum. The forces on the lever are the Effort (E) and the load (R).

16. E = Effort R = Load LE = Length (distance) from fulcrum to Effort LR = Length (distance) from fulcrum to Load (R)

17. Moment = Force x distance to fulcrum CW (-)CCW (+) The Effort is positive because it is rotating in a counter clock wise rotation around the fulcrum. The Load is negative because it is rotating in a clock wise rotation around the fulcrum.

18. Moment 1 = Moment 2 Force 1 x distance 1 = Force 2 x distance 2 300 lb x 4 ft = 1200 lb x 1 ft 1200 ft-lb = 1200 ft-lb

19. Mechanical Advantage = Load Effort MA = LE LR = 1200 lb 300 lb = 4 = 4 ft 1 ft = 4 RERE LE LR = or LE(E) = LR(R) RERE =

20. You are given a board that is 8 feet long and a rock to use as a fulcrum and you need to lift a heavy object. Where would you place the rock? Why? LE becomes very large. LR becomes very small. Place the rock as close as possible to the load

21. If LE greater than LR, then MA greater than 1 If LE less than LR, then MA less than 1

22. Since LE greater than LR, then MA greater than 1

23. Since the LE less than LR, then MA less than 1

24. Given: LE = 6 ft, LR = 3 ft, E = 1 lb Find R. Solution: LE R LR E == 6 ft 3 ft = 2 So.. 2 = R 1lb = 2 lb

25. Given: R = 8 lb, LE = 4 ft, E = 4 lb Find LR. Solution: LE R LR E == 4 ft LR = 8 lb 4 lb = LR= 2 ft

29. Mechanical Advantage = Load Effort MA = Radius to Effort Radius to Load = LE LR

30. A wheel with a 12 inch radius is used to turn an axle with a radius.5 inches. What is the mechanical advantage? MA = Radius to Effort Radius to Load = LE LR MA = Radius of Wheel Radius of Axel = 12 in.5 in = 24

31. Consider an axle used to drive the wheels of a car. The wheel radius is 12 inches, while the axle radius is 1 inch. What is the mechanical advantage? MA = Radius to Effort Radius to Load = LE LR MA = Radius of Axle Radius of Wheel = 1in 12 in = 0.083

32. You need to know the Circumference of Wheel S S = Distance traveled in one revolution C = (Π)Wheel Diameter = (3.14)D

33. If your car has tires with a diameter of 24 inches how many times will the tires rotate if the car travels 100 feet? C = (Π)Wheel Diameter = (3.14)2 ft = 6.28 ft. 24 inches = 2 feet 100 ft 6.28 ft S = Distance traveled in one revolution = 6.28 ft Number of Revolutions == 15.9 revolutions

35. Work at Effort end = Work at Load end (Effort) Dist. traveled by rope = (Load) Dist. moved by Load MA = The number of strands supporting the load. (The end strand ONLY counts when the effort is pointing upward.)

36. Fixed Pulley Movable Pulley Block & Tackle MA = 1 MA = 2 MA = 4

37. The pulley system shown is used to lift a load of 60 lbs a distance of 2’. How much effort must be applied, and how much rope do you need to pull?

38. MA = # of strands = 6 6 = RERE = 60 lb E Effort = 10 lb Distance traveled = 2 ft * 6 Distance traveled = 12 ft What is the tradeoff for reducing the effort?

40. R or Load E or Effort MA = RERE The Effort is parallel to the Inclined Plane. The Load is 90 0 to the ground. Or in the direction of gravity.

41. H or Height of Inclined Plane L or Length of Inclined Plane MA = LHLH The Length is how long the Inclined Plane is. The Height is vertical distance between the starting point and ending point.

42. In the diagram below, L = 24 inches, H = 6 inches and the Effort = 60 lb Find the mechanical advantage and the maximum load that can be moved. What is the tradeoff for reducing the effort? A B H=6 L=24 R E=60 

43. A B H L R E  MA = L 24 in H 6 in == 4 Mechanical Advantage = Load Effort 4 = Load 60 lb Load = 240 lb In order to move the 240 lb 6 inches off the ground, we need to travel a distance of 24 inches along the incline with an effort of 60 lb.

45. Effort Inclined Plane Effort Wedge What determines if an object is an inclined plane or a wedge? Where the effort and load are applied.

46. Single L H Double L H Mechanical Advantage = Load Effort MA = LHLH

47. Find the mechanical advantage and the maximum separation load for a wedge with an incline length of 10 inches, an overall height of 4 inches, and which is exerting an effort of 100 pounds.

48. Effort MA = LHLH = 10 in 4 in = 2.5 Mechanical Advantage = Load Effort 2.5 = Load 100 lb = Load = 250 lb

50. 1/4 - 20 UNC 1/4 = the outer diameter of the threads. 20 = the number of threads per inch of screw length. UNC refers to Unified National Coarse thread.

51. OD 1in. Number of Threads per Inch View A Pitch

52. Pitch = Number of Threads per Inch 1in.

53. Mechanical Advantage = Load Effort MA = Circumference Pitch = CPCP

54. A screw with 18 threads per inch is turned by a screwdriver having a handle diameter of 1 inch. What is the mechanical advantage of the screw? MA = Circumference Pitch = CPCP

55. Pitch = Circumference = (3.14) 1 in = 3.14 in 1 in 18 = 0.055 in MA = Circumference Pitch = CPCP = 3.14 in 0.055 in = 57.09

56. Elements of the engineering-design process can be used in short term problem-solving activities: a) learn and practice systematic problem solving, b) develop and apply their creativity and ingenuity c) make concrete applications of mathematics and science skills and concepts.

57. 1.Follow all directions the first time they are given. 2.Be courteous in language and actions. 3.Be on time and prepared to participate. 4.Respect other people and their property. 5.Eye protection must be worn while students are processing materials.

58. Challenge Problem To create a device that will toss a ball accurately within a given range. Rules 1.A team will have two members. 2.Each team member will operate the of the device, attempting three shots. 3.The ball may not be propelled by a launcher that is separate from the device. 4.The energy source (rubber band) must be attached to the device. 5.Team members may retrieve and supply balls to the shooter. 6.Four (4) rubber bands provided by the teacher are the only energy source to be used. 7.The device may extend in front of the shooting line, but the ball must be released from behind the line.