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Institute of Technology and Management Vadodara. Presentation By :- Malakar Devesh D. En No. - 130950111003 Electronic & Communication Eng. 2 nd year / 3 rd Sem ELECTRONIC DEVICES AND CIRCUITS : 2131006 Krutika Newad En No. - 140950111002 Paras Bhrambhatt En No. - 140950111001
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Voltage Amplifiers
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Voltage gain AAc output voltage divided by ac input voltage CCan be derived by using the model of a transistor AAc collector resistance divided by the ac resistance of the emitter diode
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A VDB common-emitter amplifier +V CC RERE R2R2 RCRC R1R1 RLRL v in v out
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re’re’ R2R2 RCRC R1R1 RLRL v in model of the common-emitter amplifier icic ibib v out z in(stage) = R 1 R 2 r e ’ This model best illustrates that
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re’re’ R2R2 R1R1 v in T model of the common-emitter amplifier icic RCRC RLRL v out ieie r c = R C R L A V = rcrc re’re’ This model best illustrates that v out v in A V = i c i e
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Calculating voltage gain Solve the dc circuit to find the emitter current. Use the emitter current to find r e ’. Combine R C and R L to find r c. Divide r c by r e ’.
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Loading effect of input impedance An ideal ac voltage source has zero source resistance The input impedance of a stage includes biasing resistors and base input impedance When the ac source is not stiff, the input voltage is less than the source voltage
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Real signal sources are not ideal. vgvg RgRg z in(stage) v in When a source is not stiff, use: v in = z in(stage) + z in(stage) RgRg vgvg
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Multistage amplifier TTwo or more amplifiers cascaded PProvides increased gain TTwo CE stages produce an amplified in-phase signal The overall voltage gain: A V = A V1 A V2 To get more gain, a cascade amplifier can be used. Stage 1 A V1 Stage 2 A V2 v in RLRL v out z in(stage 2)
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vgvg RgRg z in(stage 1) RCRC icic RCRC icic RLRL Ac equivalent circuit for the two-stage amplifier z in(stage 2) The 2nd stage loads the 1 st stage: R c1 = R c1 ║ Z in (stage 2)
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Swamped amplifier SSome of the emitter resistance is unbypassed to get negative feedback VVoltage gain is stabilized IInput impedance is increased LLarge-signal distortion is decreased
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+V CC rErE R2R2 RCRC R1R1 RLRL v in v out RERE ac feedback resistor Swamped amplifier circuit
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re’re’ R2R2 R1R1 v in T model of the swamped common-emitter amplifier icic RCRC RLRL v out rere A V = rcrc r e ’ + r e z in(base) = (r e ’ + r e ) Emitter feedback decreases the gain and increases the impedance.
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V BE IEIE Q Large signals produce distortion since r e ’ is non-linear. Input signal r e ’ = v be ieie
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re’re’ R2R2 R1R1 v in icic RCRC RLRL v out rere This resistor is linear and can swamp r e ’.
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vbvb ieie Q v b versus i e in a swamped amplifier Input signal r e ’ + r e
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Emitter ac feedback A swamped amplifier is an example of single- stage feedback Decreases voltage gain (but the gain is more stable) Increases the base input impedance Decreases large-signal distortion
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Two-stage feedback Stage 1Stage 2 v in RLRL v out rfrf The feedback signal can be connected to the emitter end of resistor r e in stage 1.
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+V CC rErE R2R2 RCRC R1R1 v in RERE To stage 2 Feedback from stage 2 Stage 1
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Voltage gain with two-stage feedback: Stage 1Stage 2 v in RLRL v out rfrf A V = rfrf r e(stage 1) + 1
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CC amplifier KKnown as an emitter follower TThe collector is at ac ground SStable voltage gain HHigh input impedance LLow distortion
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+V CC RERE R2R2 R1R1 RLRL v in The common-collector or emitter follower amplifier v out ac ground
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re’re’ R2R2 R1R1 v in T model of the emitter follower amplifier v out = i e r e rere r e = R E R L v in = i e (r e + r e ’ ) rere r e + r e ’ A V =
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rere R2R2 R1R1 v in model of the emitter follower amplifier v out (r e + r e ’ ) z in(stage) = R 1 R 2 (r e + r e ’ )
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RCRC RLRL RCRC RLRL v th The output side of a common-emitter amplifier Applying Thevenin’s theorem: The output impedance is equal to R C.
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re’re’ R2R2 R1R1 RGRG T model of the emitter follower amplifier RERE RLRL A v th z out RLRL A Apply Thevenin’s theorem to point A:
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Output impedance of the emitter follower amplifier re’ +re’ + R 1 R 2 R G ( ) z out = R E The current gain of the amplifier steps down the impedance of the base circuit. Thus, the output impedance of this amplifier is small.
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Common-collector buffer AA common-emitter (CE) stage with a low resistance load overloads with a small voltage gain AA common-collector (CC) stage placed between a CE stage and the load reduces overload and acts as a buffer
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Darlington pair Two transistors connected with the emitter of the first transistor connected to the base of the second transistor The overall gain is equal to the product of the individual current gains
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Darlington connection Q1Q1 Q2Q2 = Darlington transistor Darlington transistors are manufactured with transistors in one case
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Zener follower A combination of a zener diode and an emitter follower Provides a regulated output voltage with a large load current The zener current is much smaller than the load current
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Zener follower circuit +V CC RLRL RSRS V out VZVZ V out = V Z - V BE I B = I out dc z out = r e ’ + dc RZRZ
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R1R1 Two-transistor voltage regulator VZVZ R2R2 Q1Q1 Q2Q2 R3R3 R4R4 RLRL +V in V out V out = R 3 + R 4 R4R4 (V Z + V BE )
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Common-base amplifier The base is at ac ground The input drives the emitter and the output is taken from the collector No current gain but has a high voltage gain Low input impedance High output impedance High frequency applications
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CB amplifier circuit
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Comparison of Amplifier Configurations
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Numerical Comparison of Amplifier configurations for the Same Transistor and DC Biasing
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Thank You
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