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Published byValentine Jordan Modified over 8 years ago
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Trig Functions of Angles Beyond Right Triangles (5.2)(3)
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SAT Prep Quick poll! 1.200 is what percent of 20? (Free response)
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SAT Prep Quick poll! 2. 66 2 + 2(34)(66) + 34 2 = (Free response)
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SAT Prep Quick poll! 3.
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POD– if we have time Express csc θ in terms of cos θ.
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POD Express csc θ in terms of cos θ.
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Another look at trig ratios Consider an angle θ in standard position. We know that sin θ is the ratio y/r. In a unit circle, what is r? So, what is sin θ? Using these letters, what are the other five trig ratios? θ x y (x,y) r
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Another look at trig ratios These ratios hold, even beyond the acute angles in the first quadrant. functionratio unit circle sin θ y/ry cos θx/rx tan θy/xy/x csc θ r/y1/y sec θ r/x1/x cot θ x/yx /y θ x y (x,y) r r r
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Another look at trig ratios These ratios hold, even beyond the acute angles in the first quadrant. functionratio unit circle sin θ y/ry cos θx/rx Can you see why the coordinates of the point traveling around the unit circle are (cos θ, sinθ)? θ x y (x,y) r r r
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Another look at trig ratios Consider an angle θ in standard position. We’ve considered the idea that tan θ = sin θ/cos θ. Given this ratio, how else could we think of tangent? θ x y (x,y) r
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Another look at trig ratios Consider an angle θ in standard position. We’ve considered the idea that tan θ = sin θ/cos θ. Given this ratio, how else could we think of tangent? Tangent represents the slope of the terminal side, or the “slope” of the angle, if you will. θ x y (x,y) r
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Another look at trig ratios Although the trig functions are all positive in a right triangle (or in the first quadrant), they change signs depending on where the terminal side lands. In which quadrant(s) are sine positive and negative? What about cosine and tangent? θ x y (x,y) r r r
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Trig ratios as functions We can consider these trig ratios as functions of the rotation of an angle. Suppose we trace the values of the y-coordinate as the angle rotates. Or trace the values of the x-coordinate? What are we graphing? What are the independent and dependent variables? How do we think of the domain and range of the functions?
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An animated look at sine We’re working toward the graphs of these trig functions, where the angle is x, and the trig ratio is y. Here’s a quick look at y = sin x.y = sin x
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Trig ratios as functions What are the domains of each of the six functions? sin θ csc θ cos θ sec θ tan θ cot θ θ x y (x,y) r r r
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Trig ratios as functions What are the domains of each of the six functions? sin θ R csc θ R ≠ 0°± 180n°, R ≠ ± πn cos θ R sec θ R ≠ 90°± 180n°, R ≠ π/2 ± πn tan θ R ≠ 90°± 180n°, R ≠ π/2 ± πn cot θ R ≠ 0°± 180n°, R ≠ ± πn θ x y (x,y) r r r
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Trig ratios as functions What are the ranges of each of the six functions? sin θ csc θ cos θ sec θ tan θ cot θ Graph the sine and tangent functions on calculators. θ x y (x,y) r r r
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Trig ratios as functions What are the ranges of each of the six functions? sin θ |R| ≤ 1 csc θ |R| ≥ 1 cos θ |R| ≤ 1 sec θ |R| ≥ 1 tan θR cot θR θ x y (x,y) r r r
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Use it Find the values of the six trig functions for 3π/2.
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Use it Find the values of the six trig functions for 3π/2. sin θ = -1 cos θ = 0 tan θ = undefined csc θ = -1 sec θ = undefined cot θ = 0
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Use it Find the values of the six trig functions for θ. θ (-15,8)
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Use it Find the values of the six trig functions for θ. sin θ = 8/17 cos θ = -15/17 tan θ = -8/15 csc θ = 17/8 sec θ = -17/15 cot θ = -15/8 θ (-15,8)
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Use it An angle θ is in standard position, with its terminal side in quadrant III, along the line y = 3x. Find the values of the six trig functions. (Hint, draw a picture, find a point.)
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Use it An angle θ is in standard position, with its terminal side in quadrant III, along the line y = 3x. Find the values of the six trig functions. (Hint, draw a picture, find a point.) θ (-1, -3) r r = what?
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Use it An angle θ is in standard position, with its terminal side in quadrant III, along the line y = 3x. Find the values of the six trig functions. (Hint, draw a picture, find a point.) sin θ = -3/√10 = -3√10/ 10 cos θ = -1/√10 = -√10/ 10 tan θ = 3 csc θ = -√10/3 sec θ = -√10 cot θ = 1/3
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