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x 2 = 16 ax 2 + bx + c The parabola is used to make lights that have a focused beam as those used in motor vehicles. It is also used in parabolic.

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Presentation on theme: "x 2 = 16 ax 2 + bx + c The parabola is used to make lights that have a focused beam as those used in motor vehicles. It is also used in parabolic."— Presentation transcript:

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2 x 2 = 16 ax 2 + bx + c

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5 The parabola is used to make lights that have a focused beam as those used in motor vehicles. It is also used in parabolic louvres and as light fixtures inside buildings.

6 1. To factorize…. 2. To solve …. 3. To draw the graph … 4. To locate the roots of the equation. 5. To locate the axis of symmetry … 6. To state the maximum or minimum value … 7. To locate and state the turning point … 8. To use the graph to solve simple inequalities

7 To factorize a x 2 + bx + c 1. Find the product ac 2. Find two factors of ac that will add to give the value of b 3. Replace bx by the two factors found in 2. 4. Factorize in pairs.

8 Factorize 2x 2 – x – 3 a = 2 b = -1 c = -3 ac = 2 x -3 = -6 Two factors of -6 are -2 and 3 but -2 + 3 = 1 which is not equal to b. Use the two factors 2 and -3 ( check that 2 + (-3 ) = -1 which is equal to b) The expression is now re-written as 2x 2 + 2x – 3x -3 (factorize by pairing) 2x(x + 1) -3(x + 1) (x + 1)(2x – 3)

9 1. Take all terms to one side of the equation. 2. Factorize the equation. 3. Put each factor equal to 0 and solve for x. 4. ALL QUADRATC EQUATIONS YIELD TWO ANSWERS! Perfect squares give two identical values.

10 To solve 2x 2 – x = 3 ( Take all terms to one side of the equation.) 2x 2 – x – 3 = 0 ( Factorize the equation.) (x+1)(2x – 3) = 0 (Put each factor equal to 0 and solve for x.) x + 1 = 0and2x – 3 = 0 x = -1 x = 1.5 The two solutions are x = -1 and 1.5

11 1. Choose at least 5 values of x from a given range. 2. Substitute each value into the equation and find the corresponding values of y. 3. Plot each point on a graph page. 4. Draw a smooth curve connecting the points.

12 The first two steps can be represented in the table as shown below. Working for the values of y do not need to be shown but if shown you will not lose any marks. x-20123 y70-3-2312

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14 The roots are the values of x for which the function is equal to zero. i.e. the answer you get when you solve: y = 2x 2 – x – 3 = 0 Remember when we solved this equation we got: x = -1 or 1.5. The axis of symmetry is the average of the roots. x = ½ (-1 + 1.5) = 0.25

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16  In this case the turning point is a minimum.  The minimum point is the coordinates of the point where the axis of symmetry crosses the curve.  The minimum point for this graph is (0.25, -3.1)  The minimum value is -3.1

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19  A graph that is already drawn can be used to determine the solution to other equations or inequalities by drawing a suitable line on the curve that was already drawn.  For example to solve 2x 2 – x – 3 = 2 we simply need to 1. draw the line y = 2 on the graph of 2x 2 – x – 3 = 0 and 2. state the values of x where the curve and the line intersect.

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22  The solutions are the x coordinates of the points where the curve and the line intersect. QUESTION:  Do you think this method can be used to solve 2x 2 – x – 3 = x 2 + 4x – 5?  How would you do this?

23 To solve 2x 2 – x – 3 < 3  Draw the curve y = 2x 2 – x – 3 and the line y = 3 on the same graph.  Draw vertical lines from the points of intersection to the x-axis.  Shade the region on the graph that makes the inequality true.  State the range of values of x for all points on the curve within the shaded area.

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