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Aim: How to measure energy absorbed during a phase change DO NOW: 1. A 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and its temperature.

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Presentation on theme: "Aim: How to measure energy absorbed during a phase change DO NOW: 1. A 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and its temperature."— Presentation transcript:

1 Aim: How to measure energy absorbed during a phase change DO NOW: 1. A 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and its temperature changes from 25°C to 175°C. Calculate the specific heat capacity of iron. 2. How many joules of heat are needed to raise the temperature of 10.0 g of aluminum from 22°C to 55°C, if the specific heat of aluminum is 0.90 J/g°C? 3. To what temperature will a 50.0 g piece of glass raise if it absorbs 5275 joules of heat and its specific heat capacity is 0.50 J/g°C? The initial temperature of the glass is 20.0°C.

2 Energy is absorbed Energy is released

3 Vocab Potential Energy- stored energy Kinetic Energy- energy having to do with motion Heat of Fusion- the amount of heat needed to change solid to liquid at constant temperature Heat of Vaporization- the amount of heat needed to change liquid to gas at constant temperature

4 Heat of Fusion amount of heat needed to be absorbed to convert a unit of mass of a substance from a solid to a liquid at its melting point q= mH f Look at Table B: heat of fusion for water is 334 joules per gram. Example: How many joules are required to melt 255 g of ice at 0 o C?

5 Heat of Vaporization amount of heat needed to be absorbed to convert a unit mass of a substance from its liquid phase to gas phase. q = H v m Look at Table B: heat of vaporization for water is 2260 joules per gram. Example: How many joules of energy are required to vaporize 423 g of water at 100 o C and 1 atm?

6 Practice 1.What is the heat of solidification for 3.4 g of water? 2. How much energy is released to the environment by 50.0 grams of condensing water vapor? 3. Is melting endothermic or exothermic? Explain.

7 Practice 4. Calculate the amount of heat needed to melt 35.0 g of ice at 0 ºC. Express your answer in kilojoules. 5. How many joules must be added to 10.0g of water to raise its temperature from 10 C to 15 C.

8 1 2 3 4 5 q=mH f q=mH v

9 Heating Curve 1.Temperature of the ice (solid) is increasing; increase in temperature means an increase in kinetic energy. 2.At 0 o C the ice begins to melt. During melting, the temperature stays the same; there is no change in kinetic energy. There is a change in potential energy; potential energy is increasing. 3.The temperature of the water now rises from 0 o C to 100 o C.

10 Heating Curve 4. At 100 o C, the water boils (changes to gas). When the water boils, the temperature stays the same; no change in kinetic energy. There is a change in potential energy; potential energy increases. 5. After all the water boils, the temperature of the gas rises.

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