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1.8 Perimeter, Circumference, and Area SOL G11 & G14 Objects: TSW … find the perimeter or circumference of basic shapes. find the area of basic shapes.

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Presentation on theme: "1.8 Perimeter, Circumference, and Area SOL G11 & G14 Objects: TSW … find the perimeter or circumference of basic shapes. find the area of basic shapes."— Presentation transcript:

1 1.8 Perimeter, Circumference, and Area SOL G11 & G14 Objects: TSW … find the perimeter or circumference of basic shapes. find the area of basic shapes.

2 Perimeter Is the sum of the length of its sides Area Number of square units it encloses Circumference The distance around a circle

3 Perimeter and Area of a Rectangle A is Area, P = Perimeter b is the base h is the height P = 2b + 2h units A = bh units 2 Example: find the area and perimeter of 10 15 b h P =2(15) + 2(10) =50 units A =(15) (10) =150 units 2

4 Example 1: The botany club members are designing a rectangular garden for the courtyard of your school. They plan to place edging on the outside of the path. How much edging material will they need? Width = 4 + 16 + 4 = 24 ft. Length = 4 + 22 + 4 = 30 ft. P = 2(b) + 2(h) = 2(24) + 2(30) = 108ft. They will need a 108ft. of edging to go around the courtyard.

5 Perimeter and Area of a Square A is Area, P = Perimeter s is side length P = 4s units A = s 2 units 2 Example: find the area and perimeter of 10 s P =4(10) =40 units A =(10) 2 =100 units 2

6 Perimeter and Area of a Triangle A is Area, P = Perimeter a, b, and c side length Base b, and height h P = a + b + c units A = ½ bh units 2 Example: find the area and perimeter of c P =13 + 8 + 17 =38 units A =½ (17)(6) =51 units2 a h b 8 13 6 17

7 Circumference and Area of a Circle A is Area, C = Circumference radius r, and diameter d C = πd, or C = 2πr A = πr 2 units 2 Example: find the area and circumference of C = 8π ≈8π ≈ 25.13 units A = π 4 2 = 50.27 units 2 r d 4 8 C = 2 π( 4) ≈ 25.13 units 16 π ≈

8 Example 2: What is the circumference of the circle in terms of π ? What is the circumference of the circle to the nearest tenth? A.) M B.) T C = πd = 15π units = 47.1238898 units ≈ 47.1 units C = 2πr = 2π(4) units = 8π units = 25.13274123 units ≈ 25.1 units

9 Got It? 2.) a.) What is the circumference of a circle with radius 24 m in terms of π ? b.) What is the circumference of a circle with diameter 24 m to the nearest tenth? C = πd = 24π m = 75.39822369 m ≈ 75.4 m C = 2πr = 2π(24) m = 48π m

10 Example 3: What is the perimeter of EFG? EF = 8 units GF = 6 units GE = (-3 – 3) 2 + (-2 – 6) 2 = (-6) 2 + (-8) 2 = 36 + 64 = 100 = 10 units P = 8 + 6 + 10 = 24 units

11 Got It? 3.) Graph quadrilateral JKLM with vertices J(-3, -3), K(1, -3), L(1, 4), and M(-3, 1). What is the perimeter of JKLM? LK = 7 units JK = 4 units JM = 4 units ML = (-3 – 1) 2 + (1 – 4) 2 = (-4) 2 + (-3) 2 = 16 + 9 = 25 = 5 units P = 7 + 4 + 4 + 5 = 20 units

12 Example 4: You want to make a rectangular banner similar to the one at the right. The banner shown is 2 ½ ft wide and 5 ft high. To the nearest square yard, how much material do you need? Convert the measurements to yards: Width: ft. = yd 5252 1 yd 3 ft 5656 1 yd 3 ft 5353 Height: 5 ft. = yd 5353 25 18 Area: yd yd = yd 5656 I will need 2 yd 2 of material

13 Got It? 4.) You are designing a poster that will be 3 yd wide and 8 ft high. How much paper do you need to make the poster? Give your answer in square feet. Convert the measurement to feet: Width: 3 yds = 9 ft Height: 8 ft. Area: 9(8) ft 2 = 72 ft 2

14 Example 5: What is the area of K in terms of π ? A = π r 2 = π 8 2 = 64 π m 2 Got It? 5.) The diameter of a circle is 14 ft. a.) What is the area of the circle in terms of π? b.) What is the area of the circle using an approximation of π? A = π r 2 = π 7 2 = 49 π units 2 49 π ft 2 ≈ 153.93804 ft 2

15 Postulate 1.10: Area Addition Postulate The area of a region is the sum or the areas of its nonoverlapping parts. Example 6: Rect. 1: 3(3) = 9 cm 2 Rect. 2: 3(6) = 18 cm 2 Rect. 3: 3(9) = 27 cm 2 Total Area 54 cm 2

16 Example 7: What is the area of the figure? Square: 4 2 = 16 ft 2 Rect.: 4(8) = 32 ft 2 Triangle: ½ 8(4) = 16 cm 2 Total Area = 16 + 32 + 16 = 64 ft 2


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