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Chapter 1: Chemistry and the Atomic/Molecular View of Matter Chemistry: The Molecular Nature of Matter, 6E Brady/Jespersen/Hyslop
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E 1.2- Scientific Method Approach to gathering information & formulating explanations. Scientists perform experiments in laboratories under controlled conditions 1.Make observations/collect data 2.Law or Scientific Law 3.Hypothesis 4. Theory 2
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Atomic Theory Most significant theoretical model of nature Atoms Tiny submicroscopic particles Make up all chemical substances Make up everything in Macroscopic world Smallest particle that has all properties of given element Composed of: Electrons Neutrons Protons 3
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E 1.3- Matter & Its Classifications Matter Anything that has mass & occupies space Mass How much matter given object has Weight Force with which object is attracted by gravity Ex. Mass vs. Weight Astronaut on moon & on earth Weight on moon = 1 / 6 weight on earth Same mass regardless of location 4
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Matter Chemical Reactions Transformations that alter chemical compositions of substances Decomposition Chemical reaction where 1 substance broken down into 2 or more simpler substances Ex. 5 Molten sodium chloride Sodium metal Na + chlorine gas Cl 2 Electric current
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Elements Substances that can’t be decomposed into simpler materials by chemical reactions Substances composed of only 1 type of atom H 2, O 2, Cl 2, Br 2, Na, Ca, Fe More complex substances composed of elements in various combinations 6 diamond = carbongoldsulfur
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Chemical Symbols for Elements Chemical Symbol One or two letter symbol for each element name First letter capitalized, second letter lower case Ex. C = carbonS = sulfur Ca = calciumAr = argon Br = bromineH = hydrogen Cl = chlorineO = oxygen Used to represent elements in chemical formulas Ex. Water = H 2 O Carbon dioxide = CO 2 Most based on English name Some based on Latin or German names 7
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Chemical Symbols English NameChemical SymbolLatin Name SodiumNaNatrium Potassium KKalium IronFeFerrum CopperCuCuprum SilverAgArgentum GoldAuAurum MercuryHgHydrargyrum AntimonySbStibium TinSnStannium LeadPbPlumbum TungstenWWolfram (German) 8
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Compound Formed from 2 or more atoms of different elements Always combined in same fixed ratios by mass Can be broken down into elements by some chemical changes Ex. Water decomposed to elemental hydrogen & oxygen Mass of oxygen = 8 × mass of hydrogen 9
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Pure Substance vs. Mixture Pure substances Elements and compounds / H 2 O, Na, N 2, … Composition always same regardless of source Mixture Can have variable compositions Made up of two or more substances Ex. CO 2 in water—varying amounts of “fizz” in soda 2 broad categories of mixtures: Heterogeneous Mixtures Homogeneous Mixtures 10
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Homogeneous Mixtures Same properties throughout sample Solution Thoroughly stirred homogeneous mixture Ex. Liquid solution Sugar in water Salt in water Gas solution Air Contains nitrogen, oxygen, carbon dioxide & other gases Solid solution US 5¢ coin – Metal Alloy Contains copper & nickel metals 11 Other examples -Flour -Milk powder -Potable water -Gasoline
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Heterogeneous Mixtures 2 or more regions of different properties Solution with multiple phases Separate layers Ex. Salad dressing Oil & vinegar Ice & water Same composition 2 different physical states Ether and water Soil 12
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Physical Change No new substances formed Substance may change state or the proportions Ex. Ice melting or water freezing Sugar or salt dissolving Melting of metals Condensation of vapor or evaporation of water Stirring iron filings & sulfur together 13
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Chemical Change or Chemical Reaction Formation of new substance or compound Involves changing chemical makeup of substances New substance has different physical properties Can’t be separated by physical means Ex. Fool’s gold Compound containing sulfur & iron No longer has same physical properties of free elements Can’t be separated using magnet 14
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Learning Check: ChemicalPhysical Magnesium burns when heated Magnesium metal tarnishes in air Magnesium metal melts at 922 K Grape Kool-aid lightens when water is added 15 For each of the following, determine if it represents a Chemical or Physical Change: X X X X
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Classification of Matter 16
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Learning Check: Classification Hot Cocoa Ice (H 2 O) White Flour Table Salt (NaCl) Pure substance Element Compound Molecule Heterogeneous Mixture Homogeneous Mixture 17 X X X XX X X
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E 1.5- Atoms and Molecules Chemical Formulas Atoms combine to form more complex substances Discrete particles Each composed of 2 or more atoms Ex. Molecular oxygen, O 2 Carbon dioxide, CO 2 Ammonia, NH 3 Sucrose, C 12 H 22 O 11 18
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Chemical Formulas Specify composition of substance Chemical symbols Represent atoms of elements present Subscripts Given after chemical symbol Represents relative numbers of each type of atom Ex. Fe 2 O 3 : iron & oxygen in 2:3 ratio 19
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Chemical Formulas Free Elements Element not combined with another in compounds Just use chemical symbol to represent Ex. Iron FeNeonNe SodiumNaAluminumAl Diatomic Molecule Molecules composed of 2 atoms each Many elements found in nature Ex. OxygenO 2 NitrogenN 2 HydrogenH 2 ChlorineCl 2 20
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Depicting Molecules Want to show: Order in which atoms are attached to each other 3-dimensional shape of molecule Three ways of visualizing molecules: 1. Structural formula 2. Ball-and-Stick model 3. Space filling model 21
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E 1. Structural Formulas Use to show how atoms are attached Atoms represented by chemical symbols Chemical bonds attaching atoms indicated by lines 22 H 2 O water CH 4 methane
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E 3-D Representations of Molecules Use touching spheres to indicate molecules Different colors indicate different elements Relative size of spheres reflects differing sizes of atoms 23 Hydrogen molecule, H 2 Oxygen molecule, O 2 Nitrogen molecule N 2 Chlorine molecule, Cl 2
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E 2. “Ball-and-Stick” Model Spheres = atoms Sticks = bonds 24 Chloroform, CHCl 3 Methane, CH 4
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E 3. “Space-Filling” Model Shows relative sizes of atoms Shows how atoms take up space in molecule 25 Chloroform, CHCl 3 Methane CH 4 Water H 2 O
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E More Complicated Molecules Sometimes formulas contain parentheses How do we translate into a structure? Ex. Urea, CO(NH 2 ) 2 Expands to CON 2 H 4 Atoms in parentheses appear twice 26 Ball-and-stick model Space-filling model
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Hydrates Crystals that contain water molecules Ex. plaster: CaSO 4 ∙2H 2 O calcium sulfate dihydrate Water is not tightly held Dehydration Removal of water by heating Remaining solid is anhydrous (without water) 27 Blue = CuSO 4 5H 2 O White = CuSO 4
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Counting Atoms 1.Subscript following chemical symbol indicates how many of that element are part of the formula No subscript implies a subscript of 1. 2.Quantity in parentheses is repeated a number of times equal to the subscript that follows. 3.Raised dot in formula indicates that the substance is a hydrate Number preceding H 2 O specifies how many water molecules are present. 28
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Counting Atoms Ex. 1 (CH 3 ) 3 COH Subscript 3 means 3 CH 3 groups So from(CH 3 ) 3, we get 3 × 1C = 3C 3 × 3H = 9H #C = 3C + 1C = 4 C #H = 9H + 1H = 10 H #O = 1 O Total # of atoms = 15 atoms 29
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Counting Atoms Ex. 2 CoCl 2 · 6H 2 O The dot 6H 2 O means you multiple both H 2 & O by 6 So there are: #H6 × 2 = 12 H #O6 × 1 = 6 O #Co1 × 1 = 1 Co #Cl2 × 1 = 2 Cl Total # of atoms = 21 atoms 30
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Your Turn! a.Na 2 CO 3 b.(NH 4 ) 2 SO 4 c.Mg 3 (PO 4 ) 2 d.CuSO 4 ∙5H 2 O e.(C 2 H 5 ) 2 N 2 H 2 31 a.___Na, ___ C, ___ O b.___N, ___H, ___S, ___O c.___Mg, ___P, ___O d.___Cu, ___S, ___O, ___H e.___C, ___H, ___N 321 2814 328 1 1 910 Count the number of each type of atom in the chemical formula given below 4 12 2
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E 1.6- Chemical Reactions When 1 or more substances react to form 1 or more new substances Ex. Reaction of methane, CH 4, with oxygen, O 2, to form carbon dioxide, CO 2, & water, H 2 O. Reactants = CH 4 & O 2 Products = CO 2 & H 2 O 32
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Chemical Equations Use chemical symbols & formulas to represent reactants & products. Reactants on left hand side Products on right hand side Arrow ( ) means “reacts to yield” Ex. CH 4 + 2O 2 CO 2 + 2H 2 O Coefficients Numbers in front of formulas Indicate how many of each type of molecule reacted or formed Equation reads “methane & oxygen react to yield carbon dioxide & water” 33
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Conservation of Mass in Reactions Mass can neither be created nor destroyed This means that there are the same number of each type of atom in reactants & in products of reaction If # of atoms same, then mass also same 34 CH 4 + 2O 2 CO 2 + 2H 2 O 4 H + 4O + C = 4 H + 4O + C
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Balanced Chemical Equation Ex. 2C 4 H 10 + 13O 2 8CO 2 + 10H 2 O 35 4 C & 10 H per molecule 2 O per molecule 2 H & 1 O per molecule 1 C & 2 O per molecule
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Balanced Chemical Equation Ex. 2C 4 H 10 + 13O 2 8CO 2 + 10H 2 O 36 2 molecules of C 4 H 10 13 molecules of O 2 10 molecules of C 4 H 10 8 molecules of CO 2 Coefficients Number in front of formulas Indicate number of molecules of each type Adjusted so # of each type of atom is same on both sides of arrow Can change
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Balanced Chemical Equations How do you determine if an equation is balanced? Count atoms Same number of each type on both sides of equation? If yes, then balanced If no, then unbalanced Ex. 2C 4 H 10 + 13O 2 8CO 2 + 10H 2 O ReactantsProducts 2×4 = 8 C8×1 = 8 C 2×10 = 20 H10×2 = 20 H 13×2 = 26 O (8×2)+(10×1)= 26 O 37
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Learning Check Fe(OH) 3 + 2 HNO 3 Fe(NO 3 ) 3 + 2 H 2 O Not Balanced Only Fe has same number of atoms on either side of arrow. 38 ReactantsProducts Fe11 3 + (2×3) = 9 (3×3) + 2 = 11 O 3 + 2 = 5(2×2) = 4 H 23 N
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E Your Turn! How many atoms of each element appear on each side of the arrow in the following equation? 4NH 3 + 3O 2 → 2N 2 + 6H 2 O 39 ReactantsProducts N(4 × 1) = 4(2 × 2) = 4 O(3 × 2) = 6(6 × 1) = 6 H(4 × 3) = 12(6 × 2) = 12
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Brady/Jespersen/Hyslop Chemistry: The Molecular Nature of Matter, 6E 40 * All Review Questions are required Focus On the following 1.5 1.11 1.12 1.14 1.29 1.32 1.33 1.41 1.48 1.53
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