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14.0 Math Review 14.4 Interpolation. Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ.

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Presentation on theme: "14.0 Math Review 14.4 Interpolation. Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ."— Presentation transcript:

1 14.0 Math Review 14.4 Interpolation

2 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42

3 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42

4 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 300 CFM = drop in w.g.? Step 1: CFM Total Difference : 400 – 200 = 200

5 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 2: CFM Ratio Factor : 400 – 300 = 100 300 CFM = drop in w.g.?

6 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 2: CFM Ratio Factor : 400 – 300 = 100 Step 3: CFM Ratio: 100 ÷ 200 = 0.5 Step 1: CFM Total Difference : 400 – 200 = 200 300 CFM = drop in w.g.?

7 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 4: w.g. total difference:.09 –.04 = 0.05 Step 3: CFM Ratio: 100 ÷ 200 = 0.5 300 CFM = drop in w.g.?

8 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 4: w.g. total difference:.09 –.04 = 0.05 Step 3: CFM Ratio: 100 ÷ 200 = 0.5 300 CFM = drop in w.g.?

9 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 5: CFM Ratio is multiplied by the w.g. total difference: 0.5 x 0.05 = 0.025 Step 2: CFM Ratio Factor : 400 – 300 = 100 300 CFM = drop in w.g.?

10 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 5: 0.5 x 0.05 = 0.025 Step 6: Final Answer: 0.09 - 0.025 = 0.065 3000.065 300 CFM = drop in w.g.?

11 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 375 CFM = w.g.? Step 1: CFM Total Difference: 400 – 200 = 200

12 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 2: CFM Ratio Factor: 400 – 375 = 25 Step 1: CFM Total Difference: 400 – 200 = 200 375 CFM = w.g.?

13 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 3: CFM Ratio: 25 ÷ 200 = 0.125 Step 2: CFM Ratio Factor: 400 – 375 = 25 375 CFM = w.g.? Step 1: CFM Total Difference: 400 – 200 = 200

14 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 4 w.g. Total Difference:.09 -.04 = 0.05 Step 3 CFM Ratio: 25 ÷ 200 = 0.125 375 CFM = w.g.?

15 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 5: CFM Ratio is multiplied by the w.g. total difference: 0.125 x 0.05 = 0.00625 375 CFM = w.g.?

16 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 6:.09 -.00625 =.08375 Step 5: 0.125 x 0.05 = 0.00625.08375375 CFM 375 CFM = w.g.?

17 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 If wet coil w.g. is 0.188 what is the CFM? Step 1: w.g. Total Difference: 0.29 – 0.17 =.12

18 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 1: w.g. Total Difference: 0.29 – 0.17 =.12 Step 2: w.g. Ratio Factor: 0.29 – 0.188 = 0.102 w.g. 0.188 - CFM?

19 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 3: w.g. Ratio: 0.102 ÷ 0.12 = 0.85 Step 2: w.g. Ratio Factor: 0.29 – 0.188 = 0.102 w.g. 0.188 - CFM? Step 1: w.g. Total Difference: 0.29 – 0.17 =.12

20 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 4: CFM Total Difference: 800 – 600 = 200 Step 3: w.g Ratio: 0.102 ÷ 0.12 = 0.85 w.g. 0.188 - CFM?

21 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 5: w.g. Ratio is multiplied by the CFM total difference: 0.85 x 200 = 170 w.g. 0.188 - CFM?

22 Interpolation Air Resistance Across The Coil Model Number Air Volume CFM Dry Coil in. w.g. Wet Coil in. w.g. XYZ 2000.030.04 4000.080.09 6000.140.17 8000.220.29 10000.310.42 Step 6: 800 – 170 = 630 Step 5: 0.85 x 200 = 170 0.188630 CFM w.g. 0.188 - CFM?

23 Interpolation Freezing point °F Antifreeze Specific Gravity @60°F % of water in solution -20Glycerine1.14550 -47Glycerine1.17140 -22Glycerine1.19730 -6Propylene Glycol1.03460 -26Propylene Glycol1.04150 -60Propylene Glycol1.04540 -13Diethylene Glycol1.07850 -27Diethylene Glycol1.08145 -42Diethylene Glycol1.08640 -23Ethylene glycol1.05661 -28Ethylene glycol1.06356 -34Ethylene glycol1.06951 -40Ethylene glycol1.07347 Scale for Hygrometer 1.00 to 1.12 Need to be freeze protected to - 30 F 34

24 Specific Gravity Archimedes of Syracuse 287 – 212 BC

25 Propylene Glycol Hydrometer : used to measure Specific Gravity

26 Interpolation Freezing point °F Antifreeze Specific Gravity @60°F % of water in solution -20Glycerine1.14550 -47Glycerine1.17140 -22Glycerine1.19730 -6Propylene Glycol1.03460 -26Propylene Glycol1.04150 -60Propylene Glycol1.04540 -13Diethylene Glycol1.07850 -27Diethylene Glycol1.08145 -42Diethylene Glycol1.08640 -23Ethylene glycol1.05661 -28Ethylene glycol1.06356 -34Ethylene glycol1.06951 -40Ethylene glycol1.07347 Scale for Hygrometer 1.00 to 1.12 Need to be freeze protected to - 30 F 34.004


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