Download presentation
Presentation is loading. Please wait.
Published byBrenda Charles Modified over 8 years ago
1
A sample of neon is at 89 o C and 123 kPa. If the pressure changes to 145 kPa and the volume remains constant, find the new temperature, in K. Gay-Lussac
2
P1 = P2 T2 = T1P2 T1 T2 P1. T2 = (362K) (145 kPa). (123 kPa) T2 = 427 K Gay-Lussac
4
3.04 mol NO 2 x 22.4 L NO 2 = 68.1 L NO 2 1 mol NO 2
5
A sample of iodine gas has a volume of 25 L, a temperature of 25 o C and a pressure of 953 mmHg. How many grams of iodine are in the sample? IDEAL GAS LAW
6
V = 25 L T = 25 o C+273 = 298K P = 953 mmHg = 1.25 atm n= ? mol n = (1.25 atm) (25 L) (0.08206 )(298K) n = 1.28 mol n = 1.28 mol I2 253.8 g I2 = 330g I2 1 mol I2 PV = nRT n = PV RT L∙atm K∙mol
7
A gas at STP occupies 28 cm 3 of space. If the pressure changes to 3.8 atm and the temperature increases to 203 o C, find the new volume in mL. Combined
8
P1V1 = P2V2 V2 = P1V1n2T2 n1T1 n2T2 n1T1P2. V2 = (1atm)(0.028L)(n 2 )(476K). (n 1 )(273K)(3.8atm) V2 = 0.0128 L = 13 mL Combined
9
25.0 g of methane (CH 4 ) has a pressure of 4.44 atm at 250. o C. Find the volume occupied by the gas. IDEAL GAS LAW
10
n = 25.0 g CH 4 1 mol CH4 16.04 g CH 4 n = 1.56 mol CH 4 P = 4.44 atm T = 250. o C+273 = 523K V= ? V = (1.56 mol)(0.08206)(523K) 4.44 atm V = 15.1 L PV = nRT V = nRT P L∙atm K∙mol
11
In a thermonuclear device,the pressure of the 0.50 L of gas within the bomb casing reaches 4.0x10 6 atm. When the bomb casing is destroyed by the explosion, the gas is released into the atmosphere where it reaches a pressure of 1.00 atm. What is the volume of the gas after the explosion? Boyle
12
P1V1 = P2V2V2 = P1V1. P2 V2 = (4.0 x 10 6 atm)(0.50 L). (1.00 atm) V2 = 2.0 x 10 6 L Boyle
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.