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Published byAgnes Jones Modified over 8 years ago
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Amy Truman
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Consider a luminous knot in a quasar jet that has been observed to move transversely across the sky with an apparent speed of beta = 3.6. ◦ Show that the actual speed of the material in the jet 0.95 < beta < 1. In doing so, be sure to include a carefully drawn and labeled (by you) side-view figure that clearly identifies and defines all the quantities you use and how you use them.
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◦ Assuming the slowest possible speed from the range in part 1, determine the angle between the jet and the line of sight. ◦ Plot the observed speed as a function of the angle between the jet and the line of sight and note the maximum angle for which superluminal motion can be observed.
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A = Quasar B = Observer C = Jet Diagram
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Jet emitted at t=0 We will see it emitted at t 1 ◦ t 1 =(D+vtcosθ)/c We will see jet arrive at position C at t 2 ◦ t 2 =t+(D/c) Time elapsed ◦ Δt=t 2 -t 1 =(t+D/c)-(D+vtcosθ)/c =t(1-βcosθ)
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Angular Separation ◦ φ=vtsinθ/D Infer a transverse velocity ◦ β app =v app /c =(1/c)(DΔφ/Δt) =vsinθ/c(1-βcosθ) =βsinθ/(1-βcosθ)
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When solving for cosθ ◦ cosθ=β When solving for sinθ ◦ sinθ=(1-cos 2 θ) 1/2 =(1-β 2 ) 1/2 =1/γ γ=(1-β 2 ) 1/2 Plugging cosθ and sinθ back into the original equation
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BetaTheta cosθ=β θ=cos -1 β=15.5
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Plug both theta and beta back into the apparent beta to check
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The actual speed of the jet is about 0.964c at an angle of 15.5°
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