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Algebra Unit 5 Jeopardy Problem Graphing Equations A Equations B Mystery Solving 111111 22222 2 333333 444444 555555 666666 Final.

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Presentation on theme: "Algebra Unit 5 Jeopardy Problem Graphing Equations A Equations B Mystery Solving 111111 22222 2 333333 444444 555555 666666 Final."— Presentation transcript:

1 Algebra Unit 5 Jeopardy Problem Graphing Equations A Equations B Mystery Solving 111111 22222 2 333333 444444 555555 666666 Final

2 Problem Solving 1 A softball is thrown upward. Its path can be modeled by the equation: h(t) = -16t 2 + 32t + 5 Where h is the height of the ball in feet, and t is time in seconds. A.Where on the graph/how do you find the maximum height of the ball? B.Where on the graph/how do you find the starting height of the ball? C.Where on the graph/how do you find when the ball hits the ground? D.Where on the graph/how do you find how long the ball is in the air?

3 Problem Solving 1 Answer

4 Problem Solving 2 A soccer ball is kicked from the ground, and its height in meters above the ground is modeled by the function: h(t) = -4.9t 2 + 19.6t Where t represents the time in seconds after the ball is kicked. How long is the ball in the air?

5 Problem Solving 2 Answer

6 Problem Solving 3 A soccer ball is kicked from the ground, and its height in meters above the ground is modeled by the function: h(t) = -4.9t 2 + 19.6t Where t represents the time in seconds after the ball is kicked. What is the maximum height of the ball?

7 Problem Solving 3 Answer

8 Problem Solving 4 A golf ball is hit from the ground, and its height in feet above the ground is modeled by the function: h(t) = -16t 2 + 180t Where t is the time in seconds after the ball is hit. What is the maximum height of the ball? When does it reach its maximum height?

9 Problem Solving 4 Answer

10 Problem Solving 5 A golf ball is hit from the ground, and its height in feet above the ground is modeled by the function: h(t) = -16t 2 + 180t Where t is the time in seconds after the ball is hit. When does the ball hit the ground?

11 Problem Solving 5 Answer h(t) = -16t 2 + 180t The ball hits the ground on the x-intercept Solve by quadratic formula or factoring: -16t(t – 11.25) = 0 -16t = 0 t – 11.25 = 0 t = 0 t = 11.25 The ball hits the ground at 11.25 seconds

12 Problem Solving 6 Each year a school’s booster club holds a dance to raise funds. In the past the profit the club made after paying for the band and other costs has been modeled by the function: P(t) = -16t 2 + 800t – 4000 Where t represents the ticket price in dollars. Will the booster club ever make a profit of $5000? $7000?

13 Problem Solving 6 Answer

14 Graphing 1

15 Graphing 1 Answer

16 Graphing 2 Find the roots of the following equation by graphing: Y = -0.5x 2 + 8

17 Graphing 2 Answer Y = -0.5x 2 + 8 Roots: (-4, 0) and (4, 0)

18 Graphing 3 DAILY DOUBLE! Y = 2x 2 - 7x + 3 A.Vertex B.AOS C.Y-intercept D.Graph E.Domain and range

19 Graphing 3 Answer (6 points!)

20 Graphing 4

21 Graphing 4 Answer

22 Graphing 5 Graph the inequality: Y < -(x – 4) 2 + 7

23 Graphing 5 Answer Y < -(x – 4) 2 + 7 1.Make a table of values 2.Use a dashed line 3.Shade below the vertex Which is at (4, 7)

24 Graphing 6 Graph the inequality: y > 0.5x 2 – 4

25 Graphing 6 Answer y > 0.5x 2 – 4 1.Make a table of values 2.Use a dashed line 3.Shade above the vertex which is at (0, -4)

26 Equations A 1 Use the zero-product property to find the solutions: (2x – 9)(x + 4) = 0

27 Equations A 1 Answer (2x – 9)(x + 4) = 0 2x – 9 = 0 x + 4 = 0 x = 4.5 x = -4

28 Equations A 2 Use square roots to find the zeros: 4x 2 – 6 = 19

29 Equations A 2 Answer

30 Equations A 3 Find the solutions by FACTORING: 0 = 6x 2 + 12x

31 Equations A 3 Answer 0 = 6x 2 + 12x 0 = 6x(x + 2) (GCF) 0 = 6x 0 = x + 2 (zero-product property) 0 = x -2 = x

32 Equations A 4 COMPLETE the SQUARE to find the x-intercepts: x 2 + 2x = 15

33 Equations A 4 Answer x 2 + 2x = 15 x 2 + 2x + 1 = 15 + 1 (x + 1) 2 = 16 x + 1 = 4 x + 1 = -4 x = 3 x = -5

34 Equations A 5 Write the equation for the parabola in vertex form:

35 Equations A 5 Answer y = a(x – h) 2 + k Vertex (1, 2) (h, k) Point (0, -1) (x, y) y = a(x – h) 2 + k -1 = a(0 – 1) 2 + 2 -1 = a + 2 -3 = a y = -3(x – 1) 2 + 2

36 Equations A 6 Use the QUADRATIC FORMULA to find the zeros: 5x 2 + 2x = 3

37 Equations A 6 Answer

38 Equations 1 B Find the x-intercepts by using SQUARE ROOTS: -4X 2 – 8 = -12

39 Equations 1 B Answer

40 Equations 2 B Find the solutions by FACTORING: x 2 + 8x + 12 = 0

41 Equations 2 B Answer x 2 + 8x + 12 = 0 (x + 6)(x + 2) = 0 x + 6 = 0 x + 2 = 0 x = -6 x = -2

42 Equations 3 B Find the roots of the equation by FACTORING: 2x 2 – 15 = -7x

43 Equations 3 B Answer 2x 2 – 15 = -7x 2x 2 + 7x – 15 = 0 (2x – 3)(x + 5) = 0 2x – 3 = 0 x + 5 = 0 x = 1.5 x = -5

44 Equations 4 B Find the x-intercepts by COMPLETING the SQUARE: x 2 + 7x – 30 = 0

45 Equations 4 B Answer x 2 + 7x – 30 = 0 x 2 + 7x = 30 x 2 + 7x + 12.25 = 30 + 12.25 (x + 3.5) 2 = 42.25 x + 3.5 = 6.5 x + 3.5 = -6.5 x = 3 x = -10

46 Equations 5 B Use the QUADRATIC FORMULA to find the solutions: 3x 2 + 21x – 4 = 0

47 Equations 5 B Answer

48 Equations 6 B Rewrite the equation in vertex form, then state the vertex and AOS: y = -3x 2 – 12x + 6

49 Equations 6 B Answer

50 Mystery 1 Name 3 words that also mean solutions.

51 Mystery 1 Answer Solutions: Roots Zeros x-intercepts

52 Mystery 2 Match the graph with the value of the discriminant: 1. 2. 3. A. d = 12 B. d = -12 C. d = 0

53 Mystery 2 Answer 1.1 x-intercept 2. 2 x-intercepts 3. no x-intercepts b 2 – 4ac = 0 b 2 – 4ac = positive b 2 – 4ac = negative C (d = 0) A (d = 12) B (d = -12)

54 Mystery 3

55 Mystery 3 Answer

56 Mystery 4 State the vertex, AOS, is the vertex a maximum or minimum? y = 3x 2 – 15x + 2

57 Mystery 4 Answer

58 Mystery 5 Is the data linear or quadratic? Write a rule for the data:

59 Mystery 5 Answer

60 Mystery 6 Without graphing, answer the following questions: y = -5(x + 8) 2 – 6 A.Vertex B.AOS C.y-intercept D.Vertex is a max or min E.Graph is more wide or narrow than y = x 2 F.Domain G.Range

61 Mystery 6 Answer

62 Final An owner of a company that produces handcrafter music stands hires a consultant to help set the selling price for the product. The consultant generates the rule: P(x) = -0.3x 2 + 75x – 2000 Where x represents the selling price of the stands. A.At what price should the stands be sold to earn the maximum profit? B.What is the maximum profit? C.What are the break-even points? (the selling price for which the profit = 0 hint plug in 0 for P(x)!) D. What is the domain and range, only consider where the company is making a profit.

63 Final Answer


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