1. Chapter 19 Gas Stoichiometry

2. The next two slides contain GFM problems involving PV=nRT. The first is the last problem from yesterdays lecture if we did not get to it. The next problem is an extra problem if we finished yesterdays lecture.

3. 1.00g of a gas occupies 0.820 dm 3 at 760 torr and 3.0°C. The gas is most likely: (a) BH 3 (b) B 2 H 6 (c) (d) B 3 H 12

4. A chemist collects 23.6g of an unknown gas from the air. It occupies a volume of 12.0 L at standard temperature and pressure. What common gas do you think the chemist has collected?

5. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl

6. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr

7. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr 119g KBr mol KBr

8. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr 119g KBr mol KBr 2 mol KBr 1 mol Br 2

9. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr 119g KBr mol KBr 2 mol KBr 1 mol Br 2 22.4 dm 3

10. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr 119g KBr mol KBr 2 mol KBr 1 mol Br 2 22.4 dm 3 1 dm 3 1000 cm 3

11. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr 119g KBr mol KBr 2 mol KBr 1 mol Br 2 22.4 dm 3 1 dm 3 1000 cm 3 = 1880 cm 3

12. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O 3

13. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O 3 5.00 dm 3 O 2

14. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O 3 5.00 dm 3 O 2 22.4 dm 3 mol O 2

15. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O 3 5.00 dm 3 O 2 22.4 dm 3 mol O 2 3 mol O 2 4 mol Al

16. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O 3 5.00 dm 3 O 2 22.4 dm 3 mol O 2 3 mol O 2 4 mol Al mol Al 27.0 g

17. In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O 3 5.00 dm 3 O 2 22.4 dm 3 mol O 2 3 mol O 2 4 mol Al mol Al 27.0 g = 8.04 g

18. How many cm 3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm 3 of hydrogen chloride gas at STP? H 2 + Cl 2 → 2HCl

19. How many cm 3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm 3 of hydrogen chloride gas at STP? H 2 + Cl 2 → 2HCl

20. How many cm 3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm 3 of hydrogen chloride gas at STP? H 2 + Cl 2 → 2HCl This is a volume – volume calculation. We can use a shortcut for these type of calculations. 50.0 cm 3 HCl

21. How many cm 3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm 3 of hydrogen chloride gas at STP? H 2 + Cl 2 → 2HCl This is a volume – volume calculation. We can use a shortcut for these type of calculations. 50.0 cm 3 HCl 2 cm 3 HCl 1 cm 3 Cl 2 = 25.0 cm 3

22. Homework (Period 1) Worksheet: Ideal Gas Equation (due in two days). Worksheet: Gas Stoichiometry (due in two days). Lab Summary: “Molecular Mass of a Gas” (due in two days). Study Guide Chapter 19 (due in two days).

23. Homework (Period 6) Worksheet: Ideal Gas Equation (due tomorrow). Lab Summary: “Molecular Mass of a Gas” (due tomorrow). Study Guide Chapter 19 (due tomorrow). Worksheet: Gas Stoichiometry (due in two days).