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BJORGE JEOPARDY 100 200 300 400 100 200 300 400 100 200 300 400 I’m in my Element! Gold? Au Yeaaaah!Drop the Base Final Jeopardy Final Jeopardy.

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Presentation on theme: "BJORGE JEOPARDY 100 200 300 400 100 200 300 400 100 200 300 400 I’m in my Element! Gold? Au Yeaaaah!Drop the Base Final Jeopardy Final Jeopardy."— Presentation transcript:

1 BJORGE JEOPARDY 100 200 300 400 100 200 300 400 100 200 300 400 I’m in my Element! Gold? Au Yeaaaah!Drop the Base Final Jeopardy Final Jeopardy

2 _ Fe + _ H 2 S0 4  _ Fe 2 (SO 4 ) 3 + _ H 2 The correct balanced values (from left to right) 100

3 2 Fe + 3 H 2 S0 4  1 Fe 2 (SO 4 ) 3 + 3 H 2 100

4 For the aluminum metal to become an aluminum ion it must ___________ 3 electrons. 200

5 lose

6 If you are using electric current in order to transfer ions for the point of plating one metal on another you are using a(n) ______________ cell. 300

7 electrolytic

8 Which element undergoes oxidation and which undergoes reduction? Zn(s)  Zn 2+ (aq) + 2e- Cu 2+ (aq) + 2e- > Cu (s) 400

9 Zn(s)  Zn 2+ (aq) + 2e- oxidation Cu 2+ (aq) + 2e- > Cu (s) reduction 400

10 What is the correct arrangement of the following metals in order of decreasing reactivity (from most reactive to least reactive)? Nickel, Silver, Sodium, Zinc 100

11 Sodium, Zinc, Nickel, Silver 100

12 (g)  FOR THE FOLLOWING REDOX REACTION 3 O 2 (g)  6 O 2- 4 Al 3+ --> 4 Al (g) HOW MANY ELECTRONS ARE TRANSFERRED FROM OXYGEN TO ALUMINUM 200

13 12

14 The molar mass of copper (II) fluoride is…. 300

15 101.55 g/mol 300

16 You measures 20.0 mL of a solution of Kool- Aid with a concentration of 8.63 mol/L. If you dilute the solution to a new volume of 600.0 mL, what is the new concentration in mol/L. 400

17 0.288 mol/L 400

18 Calculate the Percent Volume (%V/V) of a 500 mL solution that is made up of 7.00 mL of solute 100

19 1.4%

20 Is the following reaction spontaneous or non-spontaneous Hg 2+ (aq) + 2e- > Hg (l) Zn(s)  Zn 2+ (aq) + 2e- 200

21 Hg 2+ (aq) + 2e- > Hg (l)reduction Zn(s)  Zn 2+ (aq) + 2e- oxidation reduction over oxidation = spontaneous 200

22 Calculate the mass needed to create a solution of nickel (III) carbonate with a concentration of 0.021 mol/L in a 1.35 L solution. 300

23 8.43 grams 300

24 Balance the reaction below, then figure out if you started with 8.00 mol of copper (I) nitrate, what mass of copper metal is produced? _ CuNO 3 (aq) + _ Ge (s) +  _ Ge(NO 3 ) 4 (aq) + _ Cu (s) 400

25 508.4 grams 400

26 Write the half reactions and identify which element undergoes oxidation, reduction, and which is the spectator. _ CuNO 3 (aq) + _ Ge (s) +  _ Ge(NO 3 ) 4 (aq) + _ Cu (s) Final

27 Ge(s)  Ge 4+ (aq) oxidation Cu + (aq)  Cu (s) reduction NO 3 -  NO 3 - spectator Final


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