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Geometry 6.3 Keep It in Proportion.

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Presentation on theme: "Geometry 6.3 Keep It in Proportion."โ€” Presentation transcript:

1 Geometry 6.3 Keep It in Proportion

2 6.3 Theorems About Proportionality
Objectives Prove the Angle Bisector/Proportional Side Theorem Prove the Triangle Proportionality Theorem Prove the Converse of the Triangle Proportionality Theorem Prove the Proportional Segments Theorem associated with parallel lines Prove the Triangle Midsegment Theorem

3 10 4 = 5 2 ๐‘œ๐‘Ÿ = 2 5 7 2.8 = 5 2 ๐‘œ๐‘Ÿ = 2 5

4 Problem 1: Proving the Angle Bisector/Proportional Side Theorem
A bisector of an angle in a triangle divides the opposite side into two segments whose lengths are in the same ratio as the lengths of the sides adjacent to the angle.

5 Problem 2: Applying the Angle Bisector/Proportional Side Theorem
Together 1-5 ๐‘ฅ 300 = Cross-Multiply Then Divide ๐‘ฅ= 1200๐‘ฅ300 รท500 ๐‘ฅ=720 ๐‘“๐‘’๐‘’๐‘ก 1200 x 300 500

6 Problem 2: Applying the Angle Bisector/Proportional Side Theorem
๐‘ฅ 30 = 8 24 Cross-Multiply Then Divide ๐‘ฅ= 8๐‘ฅ30 รท24 ๐‘ฅ=10=๐ท๐ต ๐‘ฅ

7 Problem 2: Applying the Angle Bisector/Proportional Side Theorem
9 ๐‘ฅ = 11 22 Cross-Multiply Then Divide ๐‘ฅ= 9๐‘ฅ22 รท11 ๐‘ฅ=18=๐ด๐ถ ๐‘ฅ

8 Problem 2: Applying the Angle Bisector/Proportional Side Theorem
The Ratio of Sides 14 7 = 2 1 = ๐ด๐ต ๐ด๐ถ AB is twice AC AB=2AC AC + AB = 36 AC + 2AC = 36 3AC=36 AC=12 AB = 2AC AB = 24

9 Problem 2: Applying the Angle Bisector/Proportional Side Theorem
14 6 = 16 ๐‘ฅ Cross-Multiply Then Divide ๐‘ฅ= 16๐‘ฅ6 รท14 ๐‘ฅ=6.9=๐ท๐ถ ๐ด๐ถ=6+๐‘ฅ ๐ด๐ถ=6+6.9=12.9 ๐ด๐ถ=6+๐‘ฅ ๐‘ฅ

10 Problem 3 Triangle Proportionality Theorem
If a line parallel to one side of a triangle intersects the other two sides, then it divides the two sides proportionally

11 Problem 4: Converse of the Triangle Proportionality Theorem
If a line divides two sides of a triangle proportionally, then it is parallel to the third side

12 Problem 5 Proportional Segments Theorem
If three parallel lines intersect two transversals, then they divide the transversals proportionally Collaborate 1-4 (3 Minutes)

13 Problem 5 Proportional Segments Theorem

14 Problem 5 Proportional Segments Theorem

15 Problem 5 Proportional Segments Theorem

16 Problem 6 Triangle Midsegment Theorem
The midsegment of a triangle is parallel to the third side of the triangle and is half the measure of the third side of the triangle If ๐ฝ๐บ is given as a midsegment, then what can we conclude? ๐ฝ๐บ ๐‘–๐‘  ๐‘Ž ๐‘š๐‘–๐‘‘๐‘ ๐‘’๐‘”๐‘š๐‘’๐‘›๐‘ก ๐‘œ๐‘“ โˆ†๐ท๐‘€๐‘† ๐ฝ๐บ โˆฅ ๐ท๐‘† ๐ฝ๐บ= 1 2 ๐ท๐‘† ๐ท๐‘†=2๐ฝ๐บ

17 Problem 6 Triangle Midsegment Theorem
Collaborate 3-4 (2 Minutes)

18 Problem 6 Triangle Midsegment Theorem

19 3๐‘ฅ 18 12 = 3 2 3๐‘ฅ+2๐‘ฅ+12+18=55 5๐‘ฅ+30=55 5๐‘ฅ=25 ๐‘ฅ=5 ๐‘„๐‘‡=2๐‘ฅ=2โˆ—5=10 2๐‘ฅ ?????

20 Formative Assessment Skills Practice 6.3
Vocabulary Pg. 527 (1-5) Matching Problem Set Pg (1-12) Problem Set Pg (21-28)

21 Formative Assessment: Day 2
Assignment 6.2 and 6.3 Handout Collaborate as a group Turn in an individual assignment before we leave for the assembly


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