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5.4 To represent chemical change in the form of balanced equations Balancing Equations.

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Presentation on theme: "5.4 To represent chemical change in the form of balanced equations Balancing Equations."— Presentation transcript:

1 5.4 To represent chemical change in the form of balanced equations Balancing Equations

2 All matter is made up of atoms Atoms combine in chemical reactions to form compound Each element has the same type of atoms

3 NaOH Na – 1 atom O - 1 atom H - 1 atom NH 4 NO 3 N - 2 atoms H - 4 atoms O - 3 atoms

4 C 3 H 5 (NO 3 ) 2 C - 3 atoms H - 5 atoms N - 2 atoms O - 6 atoms TRICKY

5 4 C 2 H 4 C - 8 atoms H - 16 atoms Watch out for the # in front! The number in front of the entire molecule tells how many molecules there is. In this example there are 4 molecules! C has 2 atoms but there are 4 molecules so that means there is 8 atoms all together

6 How many atoms are in each element for these compounds? H – 1 atom N – 1 atom O – 3 atoms H – 4 atom N – 4 atom O – 12 atoms Cu – 4 atom S – 2 atom 1. HNO 3 2. 4HNO 3 3. 2Cu 2 S 4. NH 4 NO 3 5. 2Fe 2 SO 4 N– 2 atom H – 4 atom O – 3 atoms Fe– 4 atom S – 2 atom O – 8 atoms

7 H – 2 atom N – 2 atom O – 6 atoms C – 1 atom O – 5 atom S – 1 atoms Ca – 2 atom O – 2 atom H – 4 atoms 9. 4C 3 H 5 (NO 3 ) 2 10. 4Fe 2 SO 4 C– 12 atom H – 20 atom N – 8 atoms O – 24 atoms Fe– 8 atom S – 4 atom O – 16 atoms 6. 2HNO 3 7. COSO 4 8. 2Ca(OH 2 )

8 In all chemical reactions, the number of atoms of each element in the reactants will be equal to the number of atoms of each element in the products. 2H 2 + O 2 2H 2 O (balanced equation) Reactants = Products Hydrogen (H) = 4 atoms Oxygen (O) = 2 atoms Hydrogen (H) = 4 atoms Oxygen (O) = 2 atoms

9 0.5 L NaOH + HCl NaCl + H 2 O First list all the elements separately on each side Na = O = H = Cl = Reactants = Products Count all your atoms for each element 1 atom 1 atom 1 atom 1 atom 2 atoms 2 atoms 1 atom 1 atom YES… it is a balanced equation

10 0.5 L H = H = O = O = Reactants = Products First list all the elements separately on each side

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12 0.5 L H = 2 atoms O = 2 atoms O = 1 atom Second, count the number of atoms for the reactants and # of atoms for the products for each element Reactants = Products These are not the same…..so this equation is NOT balanced!

13 0.5 L H = 2 atoms O = 2 atomsO = 1 atom NEVER EVER add a number directly into compound!!! (only in front!) 2 2 44 2 The final balanced equation is Never Here! Add a number (co-efficient) in front of one or more of the molecules to make the equation balanced.

14 Fe 2 O 3 + C  CO 2 + Fe Reactants = Products Fe = O = C = 2 atoms 1 atom 3 atoms 2 atoms 1 atom 1 atom 6 6 4 33 4 The final balanced equation is:

15 Al + CuCl 2  AlCl 3 + Cu Reactants = Products Al = Cu = Cl = 1 atom 1 atom 1 atom 1 atom 2 atoms 3 atoms 66 3 22 3 The final balanced equation is:

16 Na 2 CO 3 + Ca(OH) 2  CaCO 3 + NaOH Reactants = Products Na = C = O =O = H = Ca =Ca = 2 atoms 1 atom 1 atom 1 atom 5 atoms 4 atoms 2 atoms1 atom 1 atom1 atom 5 2 2 A solution of sodium carbonate (Na 2 CO 3 ) reacts with a solution of calcium hydroxide (Ca(OH) 2 ) to give precipitate of calcium carbonate (CaCO 3 ) and a solution of sodium hydroxide (NaOH). Write a balanced equation for this reaction

17 o When balancing equations o First list elements on each side o Second count atoms for each element o Add a number in front of molecule to balance the atoms o NEVER EVER add a number in between a molecule!!! (always put it in front)

18  WORKSHEET # 11  Study guide, Module 3, page 38


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