1. Shantilal Shah Government Engineering College Bhavnagar Electrical Engg. Department

2. Branch :- ELECTRICAL Semester :- 3 rd Batch:- B1

3. SUBJECT: ANALOG ELECTRONICS SUBJECTED BY: PROF. A. M.UPADHYAY

4. Group members NAME ENROLL.NO 1) Gamit sujal J. (130430109018) 2) Chaudhari piyush U. (130430109008)

6. What is an Op-Amp? – The Surface An Operational Amplifier (Op-Amp) is an integrated circuit that uses external voltage to amplify the input through a very high gain. We recognize an Op-Amp as a mass- produced component found in countless electronics. What an Op-Amp looks like to a lay-person What an Op-Amp looks like to an engineer

7. History of the Op-Amp – The Dawn The Vacuum Tube Age The First Op-Amp: (1930 – 1940) Designed by Karl Swartzel for the Bell Labs M9 gun director Uses 3 vacuum tubes, only one input, and ± 350 V to attain a gain of 90 dB Loebe Julie then develops an Op-Amp with two inputs: Inverting and Non-inverting

8. Mathematics of the Op-Amp The gain of the Op-Amp itself is calculated as: G = V out /(V + – V - ) The maximum output is the power supply voltage When used in a circuit, the gain of the circuit (as opposed to the op-amp component) is: A v = V out /V in

9. Op-Amp Characteristics Open-loop gain G is typically over 9000 But closed-loop gain is much smaller R in is very large (MΩ or larger) R out is small (75Ω or smaller) Effective output impedance in closed loop is very small

10. Symbols for Ideal and Real Op Amps OpAmpuA741 LM111LM324

11. Terminals on an Op Amp Non-inverting Input terminal Inverting input terminal Output terminal Positive power supply (Positive rail) Negative power supply (Negative rail)

12. Open Circuit Output Voltage v o = A v d Ideal Op Amp v o = ∞ (v d )

13. Open Circuit Output Voltage Real Op Amp Voltage Range Output Voltage Positive SaturationA v d > V + v o ~ V + Linear RegionV - < A v d < V + v o = A v d Negative Saturation A v d < V - v o ~ V - The voltage produced by the dependent voltage source inside the op amp is limited by the voltage applied to the positive and negative rails.

14. Voltage Transfer Characteristic Range where we operate the op amp as an amplifier. vdvd

15. Ideal Op Amp i 2 = 0 i 1 = 0 Because Ri is equal to ∞ , the voltage across Ri is 0V. v 1 = v 2 v d = 0 V v1v1 v2v2

16. Ideal Operational Amplifier The “ideal” op amp is a special case of the ideal differential amplifier with infinite gain, infinite R id and zero R o. and If A is infinite, v id is zero for any finite output voltage. Infinite input resistance R id forces input currents i + and i - to be zero. The ideal op amp operates with the following assumptions: It has infinite common-mode rejection, power supply rejection, open-loop bandwidth, output voltage range, output current capability and slew rate It also has zero output resistance, input-bias currents, input- offset current, and input-offset voltage.

17. Almost Ideal Op Amp Ri = ∞  Therefore, i 1 = i 2 = 0A Ro = 0  Usually, v d = 0V so v 1 = v 2 The op amp forces the voltage at the inverting input terminal to be equal to the voltage at the noninverting input terminal if there is some component connecting the output terminal to the inverting input terminal. Rarely is the op amp limited to V - < v o < V +. The output voltage is allowed to be as positive or as negative as needed to force v d = 0V.

18. Inverting Amplifier: Input and Output Resistances R out is found by applying a test current (or voltage) source to the amplifier output and determining the voltage (or current) after turning off all independent sources. Hence, v s = 0 But i 1 =i 2 Since v - = 0, i 1 =0. Therefore v x = 0 irrespective of the value of i x.

19. Inverting Amplifier:Voltage Gain The negative voltage gain implies that there is a 180 0 phase shift between both dc and sinusoidal input and output signals. The gain magnitude can be greater than 1 if R 2 > R 1 The gain magnitude can be less than 1 if R 1 > R 2 The inverting input of the op amp is at ground potential (although it is not connected directly to ground) and is said to be at virtual ground. But i s = i 2 and v - = 0 (since v id = v + - v - = 0) and

20. The Non-inverting Amplifier: Configuration The input signal is applied to the non-inverting input terminal. A portion of the output signal is fed back to the negative input terminal. Analysis is done by relating the voltage at v 1 to input voltage v s and output voltage v o.

21. Non-inverting Amplifier: Voltage Gain, Input Resistance and Output Resistance Since i - =0and But v id =0 Since i + =0 R out is found by applying a test current source to the amplifier output after setting v s = 0. It is identical to the output resistance of the inverting amplifier i.e. R out = 0.

22. Non-inverting Amplifier: Example Problem: Determine the output voltage and current for the given non-inverting amplifier. Given Data: R 1 = 3k , R 2 = 43k , v s = +0.1 V Assumptions: Ideal op amp Analysis: Since i - =0,

23. Types of Gain isis ifif i2i2 i isis ifif i1i1 ioio

24. Gain Error Gain Error is given by GE = (ideal gain) - (actual gain) For the non-inverting amplifier, Gain error is also expressed as a fractional or percentage error.

25. Types of Closed Loop Gain GainVariable Name EquationUnits Voltage GainAVAV v o /v s None or V/V Current GainAIAI i o /i s None or A/A Transresistance GainARAR v o /i s V/A or  Transconductance Gain AGAG i o /v s A/V or  

26. Finite Common-Mode Rejection Ratio (CMRR) A(or A dm ) = differential-mode gain A cm = common-mode gain v id = differential-mode input voltage v ic = common-mode input voltage A real amplifier responds to signal common to both inputs, called the common-mode input voltage (v ic ). In general, An ideal amplifier has A cm = 0, but for a real amplifier,

27. Op-Amp Summing Amplifier

28. Op-Amp Differential Amplifier If R 1 = R 2 and R f = R g :

29. Op Amps Applications Audio amplifiers Speakers and microphone circuits in cell phones, computers, mpg players, boom boxes, etc. Instrumentation amplifiers Biomedical systems including heart monitors and oxygen sensors. Power amplifiers Analog computers Combination of integrators, differentiators, summing amplifiers, and multipliers

30. Applications of Op-Amps Simple EKG circuit Uses differential amplifier to cancel common mode signal and amplify differential mode signal Realistic EKG circuit Uses two non-inverting amplifiers to first amplify voltage from each lead, followed by differential amplifier Forms an “instrumentation amplifier”

31. Applications of Op-Amps Filters Types: Low pass filter High pass filter Band pass filter Cascading (2 or more filters connected together) R 2 + - + V 0 __ + V cc - V cc - + R1 R1 C Low pass filter Low pass filter Cutoff frequency  Low pass filter transfer function 

32. Summary The output of an ideal op amp is a voltage from a dependent voltage source that attempts to force the voltage at the inverting input terminal to equal the voltage at the non-inverting input terminal. Almost ideal op amp: Output voltage limited to the range between V + and V -. Ideal op amp is assumed to have Ri = ∞  and  Ro = 0  Almost ideal op amp: v d = 0 V and the current flowing into the output terminal of the op amp is as much as required to force v 1 = v 2 when V + < v o < V -. Operation of an op amp was used in the analysis of voltage comparator and inverting amplifier circuits. Effect of Ri 0  was shown.

33. THANK YOU