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Data Structures for Emergency Planning Cyril Gavoille (LaBRI, University of Bordeaux) 8 th FoIKS Bordeaux – March 3, 2014
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1. Context 2. Distance in Graphs 3. Routing and Distributed Setting 4. Focus on Connectivity 5. Focus on Distance Labelling 6. Conclusion Agenda
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Context Connectivity, distance computation or navigation in road networks (=graphs)
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Connectivity Query: Is there a path connecting u to v? It takes linear time to answer the query. It takes O(1) time if linear time pre-processing of the graph is done with a labelling of the components of G.
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Assume there is a failure x (node or edge) due to: flooding, earthquake, damage, attack … How to find efficiently the connected component of any node u in G\{x}? ➟ Update all the component labels with a linear time traversal of G\{x}, and then answer in O(1) for each query node u.
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Main issue: G is extremely large, and even linear time is too much in case of emergency! We would like the answer immediately. If we pre-process G accordingly, can we then quickly answer queries “is there a path from u to v in G\{x}”?
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Yes we can! Pre-process G in a more clever way. Identify cut- vertices, the component-tree and design an efficient NCA data structure (all take linear time). u,v are not connected in G\{x} iff x is a cut-vertex on the path from c(u) to c(v) in the component-tree.
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Rem: in case of flooding, this looks like … What about if we ask, say, for two failures x 1,x 2 ? ➟ Still feasible in constant time with a more complex data structure based on cactus graphs.
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And for any failure set X? Can we prevent emergency in order to answer connectivity query in G\X in time O(|X|) or Õ(|X|)? ➟ No efficient solution is known if more than TWO nodes can fail. Best solution requires query time O(|X|. √n) using fully-dynamic data structures [Eppstein et al. - J. ACM’98] ➟ Solution if X contains only edges with query time O(|X|. log 2 n. loglogn) [Patrascu,Thorup - FOCS’07]
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General Setting (for emergency planning) Pre-process a graph G st., for any failure set X, one can pre-process X in time Õ(f(|X|)) st. queries on nodes u,v,… of G\X can be answered as fast as possible. ➟ This differs from a dynamic data structure by the fact that during the query pre-processing of X, the initial data structure for G is NOT updated.
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General Setting (for emergency planning) We can convert these “semi-dynamic” into fully- dynamic data structures with sub-linear amortized update time in a lazy manner: - If |X| is small, solve (u,v,X) (history of events) - If |X| is large, reset X and the data structure for G\X ➟ Adding edges (or nodes then edges) is much more easy...
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1. Context 2. Distance in Graphs 3. Routing and the Distributed Setting 4. Focus on Connectivity 5. Focus on Distance Labelling 6. Conclusion Agenda
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Distance in Graphs Goal: Answer d G\X (u,v) given (u,v,X) for G (a weighted undirected graph) (a weighted undirected graph) Matrix distance requires space O(n 2 ) and constant query time (|X|=0). ➟ Space Õ(n 2 ) for |X|≤2 (nodes or edges) and O(logn) query time. [Demetrescu et al. - SIAM J. Computing’08] [Duan,Pettie - SODA’09]
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Space Lower Bound? Õ(n max{|X|,2} ) or Õ(n f(|X|) )? Intuition is that to solve efficiently queries of length Intuition is that to solve efficiently queries of length |X|+2, at least f(|X|) more space is required compared to the failure-free solution (|X|=0). d G (u) ➟ n d G (u,v) ➟ n 2 d G (u,v,w) ➟ n 3 (?) Õ(n 2 ) for every |X|? Associate with failure x some information of size O(n) telling to all other nodes short-cuts to avoid x in G. This is Õ(n 2 ) overall all (indep. of |X|). Construct a route from u to v by combining the |X| short-cuts. Associate with failure x some information of size O(n) telling to all other nodes short-cuts to avoid x in G. This is Õ(n 2 ) overall all (indep. of |X|). Construct a route from u to v by combining the |X| short-cuts. ➟ Theoretical Information argument cannot prove any lower bound larger than (n 2 ). Space Õ(n 2 ) for |X|≤2 (nodes or edges) and O(logn) query time. [Demetrescu et al., SIAM J. Comp.’08][Duan-Pettie, SODA’09] ¬
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1. Context 2. Distance in Graphs 3. Routing and Distributed Setting 4. Focus on Connectivity 5. Focus on Distance Labelling 6. Conclusion Agenda
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Routing query: next-hop to go from u to v? u v Routing and Distributed Setting - pre-processing to compute routing information - a node stores only routing information involving itself distributed data-structure
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Forbidden-Set Routing Design a routing scheme for G st. for every subset X of “ forbidden ” nodes (crashes, malicious faults, routing policies, …) st. routing tables can forward messages in G\X efficiently provided X. @(v) router: u L(x 1 ) … L(x k ) next-hop to v in G\{x 1 …x k }
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A Distributed Data Structure Get the labels of nodes involved in the query Get the labels of nodes involved in the query Compute/decode the answer from the labels Compute/decode the answer from the labels No other source of information is required No other source of information is required
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Some Results for F.-S. Routing [Courcelle,Twigg – STACS’07] Clique-width cw: O(cw 2 log 2 n) bit labels and routing tables for shortest path routing. Extended to every predicate expressed in MSO-logic. [Abraham,Chechik,G.,Peleg – PODC’10] Doubling dimension-: O(1+ 2 log 2 n bit labels and routing tables for stretch 1+ routing. [Abraham,Chechik,G. – STOC’12] Planar: O( log 3 n) bit routing tables and O( log 5 n) bit labels for stretch 1+routing. Every radius-2r ball can be covered by Every radius-2r ball can be covered by 2 radius-r balls 2 radius-r balls Include bounded growing graphs Include bounded growing graphs Euclidean graphs have =O(1) Euclidean graphs have =O(1)
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1. Context 2. Distance in Graphs 3. Routing and Distributed Setting 4. Focus on Connectivity 5. Focus on Distance Labelling 6. Conclusion Agenda
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(1) [Courcelle,G.,Kanté,Twigg – TGGT’08] (2) [Borradaile,Pettie,Wulff-Nilsen – SWAT’12] Pre-processing time: O(n) Query pre-processing time: O(|X|log|X|) (2) Space: O(n) & Q. Time: O(loglogn) (1) Space: O(logn) bit labels & Q. time: O(√logn) (2) can be generalized to H-minor free graphs Focus on Connectivity (in planar graphs)
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[Here X subset of edges only... much more tricky otherwise] Main Idea (1) Query = P LANAR P OINT L OCATION in O(√logn) time (polynomial coordinates) Note: space does NOT depend on |X|.
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Find G\X (u)? (find some identifier of the component of u in G\X) 1. Find the closest failure x ancestor of u 2. Next-hop when routing from x to u in the tree A Simple Solution for Trees u
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Label(z):=<[a(z),b(z)],@(z)> [a(z),b(z)]=first/last visit time in Euler tour @(z)=routing label for routing to/from z x 0 :[1,72] x 1 :[3,46] x 2 :[29,43] x 3 :[60,66]
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Find G\X (u):=(x,route(@(x),@(u))) x=A[p] (closest ancestor failure) x=A[p] (closest ancestor failure) p=P RED S (a(u))=max{s ∈ S:s≤a(u)} (predecessor) p=P RED S (a(u))=max{s ∈ S:s≤a(u)} (predecessor) S=[1 [3 [29 43] 46] [60 66] 72] A= x 0 x 1 x 2 x 1 x 0 x 3 x 2 - x 0 :[1,72] x 1 :[3,46] x 2 :[29,43] x 3 :[60,66] ➟ Space: O(logn) bit labels Query pre-processing: O(S ORT (|X|,n)) Query pre-processing: O(S ORT (|X|,n)) Query time: O(loglogn) Query time: O(loglogn) a(u)=23
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Query Time Lower Bound Why (loglogn) is required? [Patrascu,Thorup – STOC’06] Any data structure with space Õ(|X|) and supporting P RED X queries requires query time (loglogn) provided |X| ∈ [n ,n 1- ]. Given X and Find Path\X we construct an associative table Tab[Find Path\X (x i +1)]=x i in time O(|X|log|X|). Path ➟ P RED X (u)=Tab[Find Path\X (u)] ➟ Query-time(P RED X ) ≤ Query-time(Find Path\X )+O(1) 1 2 … x 1 x 2 … x k n
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1. Context 2. Distance in Graphs 3. Routing and Distributed Setting 4. Focus on Connectivity 5. Focus on Distance Labelling 6. Conclusion Agenda
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Focus on Distance Labelling Query: (1+approximate distance (u,v) in G\{x 1 …x k } given the labels of L(u),L(v),L(x 1 ),…,L(x k ) given the labels of L(u),L(v),L(x 1 ),…,L(x k ) [Abraham,Chechik,G. – STOC’12] For Planar graphs: 1. Pre-processing: Õ(n) 2. Space: O( log 5 n) bit labels 3. Query time: O(|X| log 5 n) query time Note: same bounds as for |X|=0 (up to Õ(1) factors)
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How does it work? Query: (u,v) in G\{x 1 …x k } given L(u),L(v),L(x 1 ),…,L(x k ) 1. From the labels of the query, construct a sketch graph H 2. Run Dijkstra from u to v in H that has size Õ (k) u
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How does it work? Query: (u,v) in G\{x 1 …x k } given L(u),L(v),L(x 1 ),…,L(x k ) 1. From the labels of the query, construct a sketch graph H 2. Run Dijkstra from u to v in H that has size Õ (k) u v
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How does it work? Query: (u,v) in G\{x 1 …x k } given L(u),L(v),L(x 1 ),…,L(x k ) 1. From the labels of the query, construct a sketch graph H 2. Run Dijkstra from u to v in H that has size Õ (k) u
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How does it work? Query: (u,v) in G\{x 1 …x k } given L(u),L(v),L(x 1 ),…,L(x k ) 1. From the labels of the query, construct a sketch graph H 2. Run Dijkstra from u to v in H that has size Õ (k) u v
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How does it work? Query: (u,v) in G\{x 1 …x k } given L(u),L(v),L(x 1 ),…,L(x k ) 1. From the labels of the query, construct a sketch graph H 2. Run Dijkstra from u to v in H that has size Õ (k) u v
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How does it work? Query: (u,v) in G\{x 1 …x k } given L(u),L(v),L(x 1 ),…,L(x k ) 1. From the labels of the query, construct a sketch graph H 2. Run Dijkstra from u to v in H that has size Õ (k) u v
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How does it work? Query: (u,v) in G\{x 1 …x k } given L(u),L(v),L(x 1 ),…,L(x k ) 1. From the labels of the query, construct a sketch graph H 2. Run Dijkstra from u to v in H that has size Õ (k) u v
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How does it work? Query: (u,v) in G\{x 1 …x k } given L(u),L(v),L(x 1 ),…,L(x k ) 1. From the labels of the query, construct a sketch graph H 2. Run Dijkstra from u to v in H that has size Õ (k) u v
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How does it work? Query: (u,v) in G\{x 1 …x k } given L(u),L(v),L(x 1 ),…,L(x k ) 1. From the labels of the query, construct a sketch graph H 2. Run Dijkstra from u to v in H that has size Õ (k) u v
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How does it work? Query: (u,v) in G\{x 1 …x k } given L(u),L(v),L(x 1 ),…,L(x k ) 1. From the labels of the query, construct a sketch graph H 2. Run Dijkstra from u to v in H that has size Õ (k) u v
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How does it work? Query: (u,v) in G\{x 1 …x k } given L(u),L(v),L(x 1 ),…,L(x k ) 1. From the labels of the query, construct a sketch graph H 2. Run Dijkstra from u to v in H that has size Õ (k) u v
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1. Context 2. Distance in Graphs 3. Routing and Distributed Setting 4. Focus on Connectivity 5. Focus on Distance Labelling 6. Conclusion Agenda
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Conclusion Two fundamental questions: 1. Improve the O(√n) update time bound for worst- case dynamic connectivity in general graphs. Note: Amortized randomized polylog(n) time solutions do exist but work only if we start from the empty network! Useless for emergency planning setting for which worst-case garantee on large network is the goal. 2. Prove or disprove that we can design in the emergency planning setting a distance oracle for general graphs of space Õ(n 2 ) and query time Õ(logn), for every failure set.
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