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1 College Algebra K/DC Friday, 04 December 2015 OBJECTIVE TSW solve absolute value equations and inequalities. QUIZ: Sec. 1.6 will be given after the lesson. ASSIGNMENT DUE –Sec. 1.6: pp. 134-135 (35-42 all, 44-52 even) wire basket TODAY’S ASSIGNMENT (due on Wed/Thur, 12/09-10/15) –Sec. 1.8: pp. 153-154 (9-23 odd, 27-39 odd, 40, 43-65 odd) LOOKING AHEAD –Wed/Thur, 12/09-10/15: TEST: Sec. 1.6 – 1.8 –Friday, 12/11/15: TEST: TEKS Exam FINAL EXAM –Period 7: Wednesday, 12/17/14 (12:56 PM – 2:30 PM) –Period 5: Friday, 12/19/14 (9:25 AM – 11:30 AM)
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Due on Wed/Thur, 09/10 December 2015 (TEST day). Assignment: Sec. 1.8: pp. 153-154 (9-23 odd, 27-39 odd, 40, 43-65 odd) Due on Wed/Thur, 09/10 December 2015 (TEST day). Solve each inequality. Give the solution set using interval notation.
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Due on Wed/Thur, 09/10 December 2015 (TEST day). Assignment: Sec. 1.8: pp. 153-154 (9-23 odd, 27-39 odd, 40, 43-65 odd) Due on Wed/Thur, 09/10 December 2015 (TEST day). Solve each inequality. Give the solution set using interval notation.
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1-4 Sec. 1.7: Solving Rational Inequalities Solve and graph each of the following: d) e) f)
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1-5 Friday, 12.04.2009 Turn in assignments.
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1-6 Absolute Value Equations and Inequalities 1.8 Absolute Value Equations ▪ Absolute Value Inequalities
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1-7 Absolute Value Equations What is absolute value (|x|)? It is the (positive) distance from x to 0 on a number line. What does |x| = 5 mean? It means, “What has a distance of 5 units from 0?” The answer is BOTH 5 and –5, since both have distances of 5 units from 0. Solution set: {-5, 5}
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1-8 Absolute Value Equations Properties Of Absolute Value For b > 0, |a| = b if and only if a = b or a = –b. |a| = |b| if and only if a = b or a = –b.
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1-9 Solving Absolute Value Equations Property 1 or Subtract 9. or Divide by –4. Now check. Solution set:
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1-10 Solving Absolute Value Equations Property 2 or Now check. Solution set:
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Assignment Sec. 1.8: pp. 153-154 (9-23 odd, 27-39 odd, 40, 43-65 odd) −Due on Wed/Thur, 09/10 December 2015 (TEST day). QUIZ: SEC. 1.6. You may use a calculator.
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12 College Algebra K/DC Monday, 07 December 2015 OBJECTIVE TSW solve absolute value inequalities. ASSIGNMENT DUE –Sec. 1.7: pp. 146-147 (39-44 all, 69-77 odd, 78) wire basket LOOKING AHEAD –Wed-Thur, 12/09-10/15: TEST: Sec. 1.6 – 1.8 –Friday, 12/11/15: TEST: TEKS FINAL EXAM –Period 3: Thursday, 12/17/15 (9:30 AM – 11:30 AM) –Period 6: Tuesday, 12/15/15 (12:42 PM – 2:30 PM)
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1-13 Absolute Value Inequalities What does |x| < 4 mean? It means, “What numbers have a distance less than 4 units from the origin?” The solution is all numbers in the interval (–4, 4), since every number in that interval is less than 4 units from the origin. What does |x| > 4 mean? It means, “What numbers have a distance greater than 4 units from the origin?” The solution is all numbers in the interval (–∞, –4) υ (4, ∞), since every number in these intervals is greater than 4 units from the origin. Solution set: (–4, 4) Solution set: (–∞, –4) υ (4, ∞)
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1-14 Absolute Value Inequalities Properties Of Absolute Value |a| < b if and only if –b < a < b. |a| > b if and only if a b.
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1-15 Solving Absolute Value Inequatities Property 3 Solution set: (–1, 4) Add 6. Divide by 4.
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1-16 Solving Absolute Value Inequatities Property 4 Add 6. Divide by 4. or Solution set:
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1-17 Solving Absolute Value Inequalities Requiring a Transformation Property 4 Subtract 5. Divide by –8. Reverse the direction of the inequality symbol. or Subtract 6. Solution set:
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1-18 Solving Special Cases of Absolute Value Equations and Inequalities Solution set: {–4} The absolute value of a number will be 0 if that number is 0. Therefore, is equivalent to 7x + 28 = 0.
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1-19 Solving Special Cases of Absolute Value Equations and Inequalities The absolute value of a number is always nonnegative. Therefore, is always true. Solution set: or R
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1-20 Solving Special Cases of Absolute Value Equations and Inequalities There is no number whose absolute value (distance) is less than –5. Solution set: ø Therefore, is always false.
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Due on Wed/Thur, 09/10 December 2015 (TEST day). Assignment: Sec. 1.8: pp. 153-154 (9-23 odd, 27-39 odd, 40, 43-65 odd) Due on Wed/Thur, 09/10 December 2015 (TEST day). Solve each inequality. Give the solution set using interval notation.
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Due on Wed/Thur, 09/10 December 2015 (TEST day). Assignment: Sec. 1.8: pp. 153-154 (9-23 odd, 27-39 odd, 40, 43-65 odd) Due on Wed/Thur, 09/10 December 2015 (TEST day). Solve each inequality. Give the solution set using interval notation.
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