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Entry Task The inverse variation xy = 8 relates the constant speed x in mi/h to the time y in hours that it takes to travel 8 miles. Graph this inverse variation. Then use the graph to estimate how many hours it would take to travel 8 miles jogging at a speed of 4.5 mi/h. Possible answer: 1 h 45 min
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Entry Task Factor 1) x2 – ) x2 + 7x – 18
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RATIONAL FUNCTIONS A rational function is a function of the form:
where p and q are polynomials
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Learning Target I can… Identify excluded values of rational functions.
Graph rational functions.
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A rational function is a function whose rule is a quotient of polynomials in which the denominator has a degree of at least 1. In other words, there must be a variable in the denominator. The inverse variations you studied in the previous lesson are a special type of rational function. Rational functions: Not rational functions: For any function involving x and y, an excluded value is any x-value that makes the function value y undefined. For a rational function, an excluded value is any value that makes the denominator equal to 0.
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What would the domain of a rational function be?
We’d need to make sure the denominator 0 Find the domain. If you can’t see it in your head, set the denominator = 0 and factor to find “illegal” values.
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The graph of looks like this:
If you choose x values close to 0, the graph gets close to the asymptote, but never touches it. Since x 0, the graph approaches 0 but never crosses or touches 0. A vertical line drawn at x = 0 is called a vertical asymptote. It is a sketching aid to figure out the graph of a rational function. There will be a vertical asymptote at x values that make the denominator = 0
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Finding Asymptotes VERTICAL ASYMPTOTES
There will be a vertical asymptote at any “illegal” x value, so anywhere that would make the denominator = 0 So there are vertical asymptotes at x = 4 and x = -1. VERTICAL ASYMPTOTES Let’s set the bottom = 0 and factor and solve to find where the vertical asymptote(s) should be.
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HORIZONTAL ASYMPTOTES
We compare the degrees of the polynomial in the numerator and the polynomial in the denominator to tell us about horizontal asymptotes. 1 < 2 degree of top = 1 If the degree of the numerator is less than the degree of the denominator, (remember degree is the highest power on any x term) the x axis is a horizontal asymptote. If the degree of the numerator is less than the degree of the denominator, the x axis is a horizontal asymptote. This is along the line y = 0. 1 degree of bottom = 2
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HORIZONTAL ASYMPTOTES
The leading coefficient is the number in front of the highest powered x term. If the degree of the numerator is equal to the degree of the denominator, then there is a horizontal asymptote at: y = leading coefficient of top leading coefficient of bottom degree of top = 2 1 degree of bottom = 2 horizontal asymptote at:
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OBLIQUE ASYMPTOTES If the degree of the numerator is greater than the degree of the denominator, then there is not a horizontal asymptote, but an oblique one. The equation is found by doing long division and the quotient is the equation of the oblique asymptote ignoring the remainder. degree of top = 3 degree of bottom = 2 Oblique asymptote at y = x + 5
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SUMMARY OF HOW TO FIND ASYMPTOTES
Vertical Asymptotes are the values that are NOT in the domain. To find them, set the denominator = 0 and solve. To determine horizontal or oblique asymptotes, compare the degrees of the numerator and denominator. If the degree of the top < the bottom, horizontal asymptote along the x axis (y = 0) If the degree of the top = bottom, horizontal asymptote at y = leading coefficient of top over leading coefficient of bottom If the degree of the top > the bottom, oblique asymptote found by long division.
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Example 2A: Identifying Asymptotes
Identify the asymptotes. Step 1 Write in y = form. Step 2 Identify the asymptotes. vertical: x = –7 horizontal: y = 0
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Check It Out! Example 2a Identify the asymptotes. Step 1 Identify the vertical asymptote. x – 5 = 0 Find the excluded value. Set the denominator equal to 0. +5 +5 x = 5 Add 5 to both sides. x = 5 Solve for x. 5 is an excluded value.
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Check It Out! Example 2b Identify the asymptotes. Step 1 Identify the vertical asymptote. 4x + 16 = 0 Find the excluded value. Set the denominator equal to 0. –16 –16 4x = –16 Subtract 16 from both sides. x = –4 Solve for x. –4 is an excluded value.
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Check It Out! Example 2b Continued
Identify the asymptotes. Step 2 Identify the horizontal asymptote. c = 5 y = 5 y = c Vertical asymptote: x = –4; horizontal asymptote: y = 5
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Check It Out! Example 2c Identify the asymptotes. Step 1 Identify the vertical asymptote. x + 77 = 0 Find the excluded value. Set the denominator equal to 0. –77 –77 x = –77 Subtract 77 from both sides. x = –77 Solve for x. –77 is an excluded value.
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Check It Out! Example 2c Continued
Identify the asymptotes. Step 2 Identify the horizontal asymptote. c = –15 y = –15 y = c Vertical asymptote: x = –77; horizontal asymptote: y = –15
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Find the domain, points of discontinuity, and x- and y-intercepts of each rational function. Determine whether the discontinuities are removable or nonremovable. Domain - All Reals except 2; x = 2; X-and y- intercepts (-1,0)(-3,0) and (0,3/2) Non Removable Domain - All Reals except -3; x = -3; X-and y- intercepts (4,0)(0,-4) Removable HINT: Points are removable if the discontinuity caused by (x-a) in the denominator is also in the numerator.
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Find the vertical asymptotes and holes for the graph of each rational function.
Vertical Asymptote at x = 3 Hole at x = -3 Vertical Asymptote at x = 1 Hole at x = 0 No Vertical Asymptote or holes
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Find the horizontal asymptote of the graph of each rational function.
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Graph the function. Steps: 1) Check degrees of numerator and denominator 2) Factor the numerator and denominator Asymptotes? Holes? 3) Find the x and y intercepts and plot 4) Plot a few extra pts 5)Sketch
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Homework p. 521 #1-12
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Entry Task - Thursday Getting Ready Pg. 515
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Thursday Homework P. 521 #13-41 odds
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Example 2B: Identifying Asymptotes
Identify the asymptotes. Step 1 Identify the vertical asymptote. 2x – 3 = 0 Find the excluded value. Set the denominator equal to 0. +3 +3 2x = 3 Add 3 to both sides. Solve for x. Is an excluded value.
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