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CSE 3358 NOTE SET 2 Data Structures and Algorithms 1
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Overview: 2 What are we measuring and why? Computational complexity introduction Big-O Notation
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Problem 3 For a problem Different ways to solve – differing algorithms Problem: Searching an element in an array Possible searching algorithms?
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The Selection Problem 4 Problem: Find the Kth largest number in a set Solution Possibilities:
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The Selection Problem 5 If dataset size = 10,000,000 and k = 5,000,000 Previous algos could take several days Is one algorithm better than the other? Are there better algorithms?
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Efficiency 6 Limited amount of resources to use in solving a problem. Resource Examples: We can use any metric to compare various algorithms intended to solve the same problem. Using some metrics in for some problems might not be enlightening…
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Computational Complexity 7 Computational complexity – the amount of effort needed to apply an algorithm or how costly it is. Two most common metrics (and the ones we’ll use) Time (most common) Space Time to execute an algorithm on a particular data set is system dependent. Why?
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Seconds? Microseconds? Nanoseconds? 8 Can’t use the above when talking about algorithms unless specific to a particular machine at a particular time. Why not?
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What will we use? 9 Logical units that express the relationship between the size n of a data set and the amount of time t required to process the data For algorithm X using dataset n, T(n) = amount of time needed to execute X using n. Problem: Ordering of the values in n can affect T(n). What to do?
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How we measure resource usage 10 Three primary ways of mathematically discussing the amount of resources used by an algorithm O(f(n)) Ω (f(n)) (f(n)) What is ___(f(n)) ?
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The Definitions 11 T(N) = O(f(n)) if there are positive constants c and n 0 such that T(N) = n 0. T(N) = Ω (g(n)) if there are positive constants c and n 0 such that T(N) >= c*g(n) when N >= n 0. T(N) = (h(n)) iff T(N) = O(h(n)) and T(N) = Ω (h(n))
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The Goal??? 12 To place a relative ordering on functions To examine the relative rates of growth. Example:
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Big - Oh 13 T(N) = O(f(n)) What does this really mean? Means: T is big-O of f if there is a positive number c such that T is not larger than c*f for sufficiently large ns (for all ns larger than some number N) In other words: The relationship between T and f can be expressed by stating either that f(n) is an upper bound on the value of T(n) or that, in the long run, T grows at most as fast as f.
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Asymptotic Notation: Big-O 14 Graphic Example
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Asymptotic Notation: Big-Oh 15 Example: Show that 2n 2 + 3n + 1 is O(n 2 ). By the definition of Big-O 2n 2 + 3n + 1 = N. So we must find a c and N such that the inequality holds for all n > N. How?
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Asymptotic Notation: Big-O 16 Reality Check: We’re interested in what happens to the number of ops needed to solve a problem as the size of the input increases toward infinity. Not too interested in what happens with small data sets.
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Notes on Notation 17 Very common to see T(n) = O(f(n)) Not completely accurate not symmetric about = Technically, O(f(n)) is a set of functions. Set definition O(g(n)) = { f(n): there are constants c > 0, N>0 such that 0 N.} When we say f(n) = O(g(n)), we really mean that f(n) ∈ O(g(n)).
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Asymptotic Notation: Big-O 18 Show that n 2 = O(n 3 ).
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Three Cases for Analysis 19 Best Case Analysis: when the number of steps needed to complete an algorithm with a data set is minimized e.g. Sorting a sorted list Worst Case Analysis: when the maximum number of steps possible with an algorithm is needed to solve a problem for a particular data set Average Case Analysis:
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Example 20 The problem is SORTING (ascending) Best Case: Worst Case: Average Case: 5 9 3 8 Data Set: n = _______
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T(N)? 21 For a particular algorithm, how do we determine T(N)? Use a basic model of computation. Instructions are executed sequentially Standard simple instructions Add, subtract, multiply, divide Comparison, store, retrieve Assumptions: Takes one time unit, T(1) to do anything simple
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Determining Complexity How can we determine the complexity of a particular algorithm? int sum(int* arr, int size) { int sum = 0; for (int i = 0; i < size; i++) sum += arr[i]; return sum; }
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