1. Complementary Angles = 90◦ Supplementary Angles = 180◦

2.  m ∟ A is 26.3◦ Determine the measure of supplementary ∟A 180 – 26.3 = 153.7◦

3.  If are supplementary and the measure of ABC is 6 times larger than CBD, determine the measure of each angle. A B C D

4. Angles are complementary angles. Determine Measurements of angle 1 and 2. 1 12x - 1 2 x 12 x – 1 + x = 90 13x -1 = 90 13x = 90 + 1 13 x = 91 X = 7◦ 12(7) – 1 = 83

5. 5 6 12 4 87 3 One interior and one exterior angle on the same side of the transversal–have the same measure Correspondin g angles Exterior angles on the opposite sides of the transversal–have the same measure Alternate exterior angles Interior angles on the opposite side of the transversal–have the same measure Alternate interior angles 5 6 12 4 87 3 5 6 12 4 87 3

6.  Polygons are named according to their number of sides. Icosagon20Heptagon7 Dodecagon 12Hexagon6 Decagon10Pentagon5 Nonagon9 Quadrilatera l4 Octagon8Triangle3 NameNumber of Sides NameNumber of Sides

7.  ∟1 = 130◦∟5 = 130◦  ∟2 = 50◦∟6 = 50◦  L3 = 50◦∟7 = 50◦  L4 = 130◦ 130◦ 180 – 130 = 50◦

8.  Catherine Johnson wants to measure the height of a lighthouse. Catherine is 5 feet tall and determines that when her shadow is 12 feet long, the shadow of the lighthouse is 75 feet long. How tall is the lighthouse? x 75 12 5

9. x 75 12 5 Therefore, the lighthouse is 31.25 feet tall.

10. P = s 1 + s 2 + b 1 + b 2 P = s 1 + s 2 + s 3 P = 2b + 2w P = 4s P = 2l + 2w Perimeter Trapezoid Triangle A = bhParallelogram A = s 2 Square A = lwRectangle AreaFigure

11.  Marcus Sanderson needs to put a new roof on his barn. One square of roofing covers 100 ft 2 and costs $32.00 per square. If one side of the barn roof measures 50 feet by 30 feet, determine a) the area of the entire roof. b) how many squares of roofing he needs. c) the cost of putting on the roof.

12.  a) The area of the roof is A = lw A = 30(50) A = 1500 ft 2 1500  2 (both sides of the roof) = 3000 ft 2  b) Determine the number of squares

13.  c) Determine the cost 30 squares  $32 per square $960 It will cost a total of $960 to roof the barn.

14.  Terri is installing a new circular swimming pool in her backyard. The pool has a diameter of 27 feet. How much area will the pool take up in her yard? (Use π = 3.14.) The radius of the pool is 13.5 ft. The pool will take up about 572 square feet.

15. Sphere Cone V =  r 2 hCylinder V = s 3 Cube V = lwhRectangular Solid DiagramFormulaFigure

16. Sphere Cone SA = 2  rh + 2  r 2 Cylinder SA= 6s 2 Cube SA = 2lw + 2wh +2lhRectangular Solid DiagramFormulaFigure

17.  Mr. Stoller needs to order potting soil for his horticulture class. The class is going to plant seeds in rectangular planters that are 12 inches long, 8 inches wide and 3 inches deep. If the class is going to fill 500 planters, how many cubic inches of soil are needed? How many cubic feet is this?

18.  We need to find the volume of one planter.  Soil for 500 planters would be 500(288) = 144,000 cubic inches

19.  V = Bh, where B is the area of the base and h is the height.  Example: Find the volume of the figure. Area of one triangle. Find the volume. 8 m 6 m 4 m

20.  where B is the area of the base and h is the height.  Example: Find the volume of the pyramid. Base area = 12 2 = 144 12 m 18 m

21. 26 m A = s² A = (26)² A = 676 m² 6 m SA = 4∏r² 26 m SA = 4∏ (6) ² ∏=3.14 SA = 4(3.14)(36) SA = 452.16 m² 676 – 452.16 = 223.84 m² area of shaded region