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GAS LAWS Boyle’s Charles’ Gay-Lussac’s Combined Gas Ideal Gas Dalton’s Partial Pressure
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Boyle’s Law The pressure and volume of a sample of gas at CONSTANT temperature are inversely proportional to each other.
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Graphing Boyle’s Law (V ↑ as P ↓) and (P ↑as V ↓)
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Boyle’s Law Equation: P 1 V 1 = P 2 V 2 P 1 V 1 = initial pressure/volume P 2 V 2 = final pressure/volume Must Have Unit Agreement
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A gas occupies 20.0 L at a pressure of 50.0 mm Hg. What is the volume when the pressure is increased to 80.0 mm Hg? (50.0 mm Hg)(20.0 L) = (80.0 mm Hg) V 2 (80.0 mm Hg) (80.0 mm Hg) V 2 = 12.5 L
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Charles’ Law At constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature.
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Graphing Charles’ Law (V ↑ as T ↑) and (V ↓ as T ↓)
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Charles’ Law Equation: V 1 T 2 = V 2 T 1 T is measured in K temperature Must Have Unit Agreement
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A 250. mL sample of neon is collected at 44 o C. Assuming the pressure remains constant, what would be the volume of the neon at standard temperature? (250. mL)(273 K) = V 2 (317K) (317K) (317K) V 2 = 215 mL
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Gay-Lussac’s Law At constant volume, the pressure of a gas is directly proportional to the temperature (Kelvin).
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Graphing Gay-Lussac’s Law (P ↑as T ↑ and P ↓ as T ↓)
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Gay-Lussac’s Equation: P 1 T 2 = P 2 T 1 Must Have Unit Agreement T is measured in K temperature
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If a gas is cooled from 355 K to 293 K and the volume is kept constant, what final pressure would result if the original pressure were 780.0 mm Hg? (780.0 mm Hg)(293 K) = P 2 (355 K) (355 K) (355 K) P 2 = 644 mm Hg
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Combined Gas Law The law combines Boyle’s, Charles’s, and Gay- Lussac’s relationship into one equation.
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Combined Gas Law Equation: P 1 V 1 T 2 = P 2 V 2 T 1 Must Have Unit Agreement T is measured in K temperature
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A sample of gas occupies a volume of 450.0 mL at 740 mm Hg and 16 o C. Determine the volume of this sample at 760 mm Hg and 37 o C. (740 mm Hg)(450.0 mL)(310K) = (760 mm Hg)(V 2 )(289K) (760 mm Hg) (289K) (760 mm Hg) (289K) V 2 = 470 mL
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Dalton’s Partial Pressure The total pressure of a mixture of gases is the sum of the partial pressures of the gases
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Dalton’s Partial Pressure Equation: P total = P A + P B + P C …
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A mixture of neon and argon gases exerts a total pressure of 2.39 atm. The partial pressure of the neon alone is 1.84 atm, what is the partial pressure of the argon? P total = P A + P B 2.39 atm = 1.84 atm of Ne + ? atm of Ar *Rearrange the equation and subtract to solve for Argon partial pressure 0.55 atm of Ar
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Ideal Gas Law Relates the pressure, temperature, volume, and moles of gas through the gas constant “R” The value for “R” depends on the pressure and volume R = 0.0821 L atm mol K R = 8.314 L kPa mol K R = 62.4 L mm Hg mol K R = 62.4 L torr mol K
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Ideal Gas Law Equation: PV = nRT where P = (kPa, atm, mm Hg, torr) V = (Liters) n = # of moles R = Universal Gas Constant T = (Kelvin) Must have unit agreement!
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How many moles of argon are there in a 725 mL sample of gas at 1875 torr and at standard temperature? P= 1875 torr V= 725 mL* n= ? mol Ar R= 62.4 T= 0 o C* PV=nRT Must convert mL to L Must convert o C to K n = 0.0798 mol Ar (1875 torr)(0.725 L)=n(62.4)(273 K)
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How many grams of argon are present? Convert moles to grams by using molar mass 0.0798 mol ArX 39.95 g Ar 1 mol Ar = 3.19 g Ar
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