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V  1/P (Boyle’s law) V  T (Charles’s law) P  T (Gay-Lussac’s law) V  n (Avogadro’s law) So far we’ve seen… PV nT = R ideal gas constant: R = 0.08206.

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Presentation on theme: "V  1/P (Boyle’s law) V  T (Charles’s law) P  T (Gay-Lussac’s law) V  n (Avogadro’s law) So far we’ve seen… PV nT = R ideal gas constant: R = 0.08206."— Presentation transcript:

1 V  1/P (Boyle’s law) V  T (Charles’s law) P  T (Gay-Lussac’s law) V  n (Avogadro’s law) So far we’ve seen… PV nT = R ideal gas constant: R = 0.08206 L∙atm / mol ∙ K constant PV = nRT Ideal Gas Law (same ratio for every gas) NO Units of : mL, mmHg, kPa, grams, °C

2 1.A 5.00 L balloon is at 0.855 atm and 25 o C. How many moles of gas are in the balloon? Ideal Gas Law Calculations (0.855 atm)(5.00 L) = n (0.08206)(298 K) (0.855)(5.00) (0.08206)(298) = n n = 0.175 mol PV = nRT R = 0.08206

3 2.What is the pressure of 0.435 mol He gas in a volume of 8.12 L at 0.00 o C? Ideal Gas Law Calculations P (8.12 L) = (0.435mol )(0.08206)(273 K) (0.435)(0.08206)(273) (8.12) = P P = 1.20 atm PV = nRT R = 0.08206

4 Molar Mass 3.A sample of aluminum chloride gas weighing 0.0500 g at 350. o C and 760 mmHg of pressure occupies a volume of 19.2 mL. Calculate the Molar Mass of the gas. 133 g/mol Ideal Gas Law Calculations (1.00 atm)(0.0192 L) = n (0.08206)(623 K) n = 0.000376 mol PV = nRT R = 0.08206 grams mole M = __0.0500 g_ 0.000376 mol = AlCl 3 =


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