1. 5-8 Quadratic Formula Hubarth Algebra II

2. Ex 1 Using the Quadratic Formula Solve x 2 + 2 = –3x. x 2 + 3x + 2 = 0 x = –b ± b 2 – 4ac 2a x = –3 ± (3) 2 – 4(1)(2) 2(1) x = –3 ± 1 2 x = –3 + 1 2 x = –3 – 1 2 or x = –1orx = –2 a = 1, b = 3, c = 2

3. Solve 3x 2 + 4x – 8 = 0. x = –b ± b 2 – 4ac 2a x = –4± 4 2 – 4(3)(–8) 2(3) –4 ± 112 6 x = Ex 2 Finding Approximate Solutions a = 3, b = 4, c = -8

4. Ex. 3 Finding Complex Solutions

5. Value of the Discriminant Two real solutions two x-intercepts One real solution one x-intercept No real Solutions; Two imaginary solutions no x-intercept

6. Ex. 4 Using the Discriminant There are two real solutions

7. Practice One real solutionTwo imaginary solutions