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IDEAL GAS LAW PV=nRT. IDEAL GAS LAW P=pressure (in kPa or atm only!) V= volume in Liters n = number of moles R= Ideal Gas Law Constant T= Temperature.

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Presentation on theme: "IDEAL GAS LAW PV=nRT. IDEAL GAS LAW P=pressure (in kPa or atm only!) V= volume in Liters n = number of moles R= Ideal Gas Law Constant T= Temperature."— Presentation transcript:

1 IDEAL GAS LAW PV=nRT

2 IDEAL GAS LAW P=pressure (in kPa or atm only!) V= volume in Liters n = number of moles R= Ideal Gas Law Constant T= Temperature in KELVIN

3 IDEAL GAS LAW R= 8.31 kPa*L Mole*K Or R=.0821 atm*L mole * k **Units must cancel in what you plug into the equation!!!

4 IDEAL GAS LAW Ideal gases are those that are: Not affected by intermolecular forces Behave according to the Kinetic molecular theory

5 IDEAL GAS LAW Avagadro’s Principle: Equal volumes of gases at the same temperature and pressure contain the same numbers of particles 1 mole= 22.4 L of gas= 6.023 x 10 23 atoms/molecules

6 IDEAL GAS LAW In reality, no gas is ideal. Under the right conditions, calculations with the ideal gas law will be very close to real gases.

7 IDEAL GAS LAW GRAPH Shows how accurately the ideal gas law can be used to estimate the characteristics of a real gas.

8 IDEAL GAS LAW GRAPH

9 The closer the real gas is to the ideal gas line (constant), the better the estimation will be.

10 IDEAL GAS LAW GRAPH

11 Examples 1. 3.25 g of XeF4 gas is placed into an evacuated 5.00 liter container at 80.0 °C. What is the pressure in the container?

12 Examples 2. What is the temperature if 1 mole of O 2 occupying 100 L of volume has a pressure of 20 Pa (1000 Pa=1 KPa)?

13 Examples 3. A 334 mL cylinder for use in chemistry lectures contains 8.470 g of helium at 23oC. How many grams of helium must be release to reduce the pressure to 145 atm assuming ideal gas behavior? (Atomic weight: He = 4.00).


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