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Chapter 10 - 1 ISSUES TO ADDRESS... When we combine two __________... what is the resulting _____________state? In particular, if we specify... -- the ____________ (e.g., wt% Cu - wt% Ni), and -- the temperature (T ) then... How many __________ form? What is the composition of each __________? What is the _________ of each phase? Chapter 10: _______ Diagrams Phase B Phase A Nickel atom Copper atom
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Chapter 10 - 2 Phase Equilibria: Solubility Limit Question: What is the __________ limit for sugar in water at 20ºC? Answer: ___ wt% sugar. At 20ºC, if C < 65 wt% sugar: syrup At 20ºC, if C > 65 wt% sugar: syrup + sugar 65 Solubility Limit: Maximum ____________ for which only a _____________ _________ exists. Sugar/Water Phase Diagram Sugar Temperature (ºC) 0 20 4060 80100 C= Composition (wt% sugar) L (liquid solution i.e., syrup) Solubility Limit L (liquid) + S (solid sugar) 20 40 60 80 100 Water Adapted from Fig. 10.1, Callister & Rethwisch 4e. Solution – solid, liquid, or gas solutions, single phase Mixture – ________________________
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Chapter 10 - 3 Components: ________________________________________________ (e.g., Al and Cu) Phases: The physically and chemically distinct material regions that form (e.g., and ). Aluminum- Copper _______ Components and Phases (darker _______) (lighter _______) Adapted from chapter- opening photograph, Chapter 9, Callister, Materials Science & Engineering: An Introduction, 3e.
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Chapter 10 - 4 70801006040200 Temperature (ºC) C= Composition (wt% sugar) L ( liquid solution i.e., syrup) 20 100 40 60 80 0 L (liquid) + S (solid sugar) Effect of Temperature & Composition Altering ______________________: path A to B. Altering ______________________: path B to D. water- sugar system Adapted from Fig. 10.1, Callister & Rethwisch 4e. D (100ºC,C = 90) __ phases B (100ºC,C = 70) __ phase A (20ºC,C = 70) __ phases
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Chapter 10 - 5 Criteria for Solid Solubility Crystal Structure electroneg r (nm) NiFCC1.90.1246 CuFCC1.80.1278 Both have the same _______________________ and have similar __________________ and atomic radii (W. Hume – Rothery rules) suggesting high mutual solubility. _____________ (e.g., Ni-Cu solution) ________________________ in one another for all proportions.
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Chapter 10 - 6 Phase Diagrams Indicate phases as a function of T, C, and P. For this course: - binary systems: ___________________. - independent variables: _________ (P = 1 atm is almost always used). Phase Diagram for Cu-Ni system 2 phases: ____________ 3 different phase fields: _______ wt% Ni 204060801000 1000 1100 1200 1300 1400 1500 1600 T(ºC) L (liquid) (FCC solid solution) L + liquidus solidus Adapted from Fig. 10.3(a), Callister & Rethwisch 4e. (Fig. 10.3(a) is adapted from Phase Diagrams of Binary Nickel Alloys, P. Nash (Ed.), ASM International, Materials Park, OH (1991).
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Chapter 10 - 7 Cu-Ni phase diagram Isomorphous Binary Phase Diagram Phase diagram: Cu-Ni system. System is: -- ___________ i.e., 2 components: Cu and Ni. -- ___________ i.e., complete _________ of one component in another; phase field extends from 0 to 100 wt% Ni. wt% Ni 204060801000 1000 1100 1200 1300 1400 1500 1600 T(ºC) L (liquid) (FCC solid solution) L + liquidus solidus Adapted from Fig. 10.3(a), Callister & Rethwisch 4e. (Fig. 10.3(a) is adapted from Phase Diagrams of Binary Nickel Alloys, P. Nash (Ed.), ASM International, Materials Park, OH (1991).
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Chapter 10 - wt% Ni 204060801000 1000 1100 1200 1300 1400 1500 1600 T(ºC) L (liquid) (FCC solid solution) L + liquidus solidus Cu-Ni phase diagram 8 Phase Diagrams : Determination of phase(s) present Rule 1: If we know ____________, then we know: -- which phase(s) is (are) present. Examples: A(1100ºC, 60 wt% Ni): ________________ B(1250ºC, 35 wt% Ni): ________________ B (1250ºC,35) A(1100ºC,60) Adapted from Fig. 10.3(a), Callister & Rethwisch 4e. (Fig. 10.3(a) is adapted from Phase Diagrams of Binary Nickel Alloys, P. Nash (Ed.), ASM International, Materials Park, OH (1991).
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Chapter 10 - 9 wt% Ni 20 1200 1300 T(ºC) L (liquid) (solid) L + liquidus solidus 304050 L + Cu-Ni system Phase Diagrams : Determination of phase compositions Rule 2: If we know T and C 0, then we can determine: -- the composition of each phase. Examples: TATA A 35 C0C0 32 CLCL At T A = 1320ºC: _______________________ C L _____________________ At T B = 1250ºC: _______________________ CLCL = C liquidus ( = ___ wt% Ni) CC = C solidus ( = ___ wt% Ni) At T D = 1190ºC: _______________________ C _____________________ Consider C 0 = 35 wt% Ni D TDTD tie line 4 CC 3 Adapted from Fig. 10.3(a), Callister & Rethwisch 4e. (Fig. 10.3(a) is adapted from Phase Diagrams of Binary Nickel Alloys, P. Nash (Ed.), ASM International, Materials Park, OH (1991). B TBTB
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Chapter 10 - 10 Rule 3: If we know T and C 0, then can determine: -- the _________________ of each phase. Examples: At T A : Only Liquid (L) present W L = _____, W = _____ At T D : Only Solid ( ) present _____________________ Phase Diagrams : Determination of phase weight fractions wt% Ni 20 1200 1300 T(ºC) L (liquid) (solid) L + liquidus solidus 304050 L + Cu-Ni system TATA A 35 C0C0 32 CLCL B TBTB D TDTD tie line 4 CC 3 R S At T B : _____________________ = 0.27 WLWL S R+S WW R R+S Consider C 0 = 35 wt% Ni Adapted from Fig. 10.3(a), Callister & Rethwisch 4e. (Fig. 10.3(a) is adapted from Phase Diagrams of Binary Nickel Alloys, P. Nash (Ed.), ASM International, Materials Park, OH (1991).
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Chapter 10 - 11 _________ – connects the phases in equilibrium with each other – also sometimes called an ___________ The Lever Rule What fraction of each phase? Think of the tie line as a lever (teeter-totter) MLML MM RS wt% Ni 20 1200 1300 T(ºC) L (liquid) (solid) L + liquidus solidus 304050 L + B T B tie line C0C0 CLCL CC S R Adapted from Fig. 10.3(b), Callister & Rethwisch 4e.
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Chapter 10 - 12 wt% Ni 20 1200 1300 304050 1100 L (liquid) (solid) L + L + T(ºC) A 35 C0C0 L: 35wt%Ni Cu-Ni system Phase ________: Cu-Ni system. Adapted from Fig. 10.4, Callister & Rethwisch 4e. Consider ____________ changes that accompany the __________ of a C 0 = 35 wt% Ni alloy Ex: Cooling of a Cu-Ni Alloy 46 35 43 32 : 43 wt% Ni L: 32 wt% Ni B : 46 wt% Ni L: 35 wt% Ni C E L: 24 wt% Ni : 36 wt% Ni 24 36 D
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Chapter 10 - ______rate of cooling: Equilibrium structure _____ rate of cooling: Cored structure First to solidify: 46 wt% Ni Last to solidify: < 35 wt% Ni 13 _______________________ Cu-Ni _____: First to solidify has C = ____ wt% Ni. Last to solidify has C = ____ wt% Ni. Cored vs Equilibrium Structures Uniform C : 35 wt% Ni
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Chapter 10 - 14 Mechanical Properties: Cu-Ni System Effect of ________________________ on: -- Tensile __________ (TS)-- Ductility (%EL) Adapted from Fig. 10.6(a), Callister & Rethwisch 4e. Tensile Strength (MPa) Composition, wt% Ni Cu Ni 020406080100 200 300 400 TS for pure Ni TS for pure Cu Elongation (%EL) Composition, wt% Ni Cu Ni 020406080100 20 30 40 50 60 %EL for pure Ni %EL for pure Cu Adapted from Fig. 10.6(b), Callister & Rethwisch 4e.
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Chapter 10 - 15 _________________ has a special composition with a min. melting T. Adapted from Fig. 10.7, Callister & Rethwisch 4e. Binary-Eutectic Systems 3 single phase regions (L, , ) Limited solubility: __________________ T E : No _______ below T E : Composition at temperature T E C E Ex.: Cu-Ag system Cu-Ag system L (liquid) L + L+ C,wt% Ag 204060 80100 0 200 1200 T(ºC) 400 600 800 1000 CECE TETE 8.0 71.9 91.2 779ºC cooling heating ____________ reaction L(C E ) (C E ) + (C E )
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Chapter 10 - 16 L+ L+ + 200 T(ºC) 18.3 C, wt% Sn 206080 100 0 300 100 L (liquid) 183ºC 61.997.8 For a 40 wt% Sn-60 wt% Pb alloy at 150ºC, determine: -- the phases present Pb-Sn system EX 1: Pb-Sn Eutectic System Answer: + -- the phase compositions -- the relative amount of each phase 150 40 C0C0 11 CC 99 CC S R Answer: C = __ wt% Sn C = __ wt% Sn W = C - C 0 C - C = 99 - 40 99 - 11 = 59 __ = _____ S ____ = W = C 0 - C C - C = R R+SR+S = 29 __ = _____ = 40 - 11 99 - 11 Answer: Adapted from Fig. 10.8, Callister & Rethwisch 4e.
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Chapter 10 - 17 Answer: C = __ wt% Sn -- the phase compositions L+ + 200 T(ºC) C, wt% Sn 206080 100 0 300 100 L (liquid) L+ 183ºC For a 40 wt% Sn-60 wt% Pb alloy at 220ºC, determine: -- the phases present: Pb-Sn system EX 2: Pb-Sn Eutectic System -- the relative amount of each phase W = C L - C 0 C L - C = 46 - 40 46 - 17 = 6 __ = _____ WLWL = C 0 - C C L - C = 23 __ = _____ 40 C0C0 46 CLCL 17 CC 220 S R Answer: + L C L = __ wt% Sn Answer: Adapted from Fig. 10.8, Callister & Rethwisch 4e.
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Chapter 10 - 18 Microstructural Developments in Eutectic Systems I 0 L + 200 T(ºC) C,wt% Sn 10 2 20 C0C0 300 100 L 30 + 400 (room T solubility limit) TETE (Pb-Sn System) L L: C 0 wt% Sn : C 0 wt% Sn Adapted from Fig. 10.11, Callister & Rethwisch 4e. For alloys for which C o < 2 wt% Sn Result: at room temperature --____________ with grains of __________ having __________ C o
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Chapter 10 - 19 Adapted from Fig. 10.12, Callister & Rethwisch 4e. Microstructural Developments in Eutectic Systems II Pb-Sn system L + 200 T(ºC) C,wt% Sn 10 18.3 200 C0C0 300 100 L 30 + 400 (sol. limit at T E ) TETE 2 (sol. limit at T room ) L L: C 0 wt% Sn : C 0 wt% Sn For alloys for which 2 wt% Sn < C o < 18.3 wt% Sn Result: at ___________ in + range --polycrystalline with __ grains and small __-phase _______
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Chapter 10 - 20 Adapted from Fig. 10.13, Callister & Rethwisch 4e. Microstructural Developments in Eutectic Systems III Adapted from Fig. 10.14, Callister & Rethwisch 4e. 160 m Micrograph of Pb-Sn eutectic microstructure Pb-Sn system LL 200 T(ºC) C, wt% Sn 2060801000 300 100 L L+ 183ºC 40 TETE 18.3 : 18.3 wt%Sn 97.8 : 97.8 wt% Sn CECE 61.9 L: C 0 wt% Sn For alloy of composition C o = C E Result: Eutectic microstructure (________ structure) --alternating layers (__________) of and phases.
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Chapter 10 - 21 Lamellar Eutectic Structure Adapted from Figs. 10.14 & 10.15, Callister & Rethwisch 4e.
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Chapter 10 - 22 For ______ for which 18.3 wt% Sn < C 0 < 61.9 wt% Sn Result: phase particles and a ________ microconstituent Microstructural Developments in Eutectic Systems IV 18.361.9 SR 97.8 S R primary eutectic Adapted from Fig. 10.16, Callister & Rethwisch 4e. Pb-Sn system L+ 200 T(ºC) C, wt% Sn 2060801000 300 100 L L+ 40 + TETE L: C 0 wt% Sn L L WLWL = (1-W ) = 0.50 C = ____ wt% Sn CLCL S R +S W = = 0.50 Just above T E : Just below T E : C = _____ wt% Sn C S R +S W = = 0.73 W = 0.27
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Chapter 10 - 23 L+ L+ + 200 C, wt% Sn 2060801000 300 100 L TETE 40 (Pb-Sn System) Hypoeutectic & Hypereutectic Adapted from Fig. 10.8, Callister & Rethwisch 4e. (Fig. 10.8 adapted from Binary Phase Diagrams, 2nd ed., Vol. 3, T.B. Massalski (Editor-in-Chief), ASM International, Materials Park, OH, 1990.) 160 m eutectic micro-constituent Adapted from Fig. 10.14, Callister & Rethwisch 4e. hypereutectic: (illustration only) Adapted from Fig. 10.17, Callister & Rethwisch 4e. (Illustration only) (Figs. 10.14 and 10.17 from Metals Handbook, 9th ed., Vol. 9, Metallography and Microstructures, American Society for Metals, Materials Park, OH, 1985.) 175 m hypoeutectic: C 0 = 50 wt% Sn Adapted from Fig. 10.17, Callister & Rethwisch 4e. T(°C) 61.9 eutectic eutectic: C 0 = 61.9 wt% Sn
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Chapter 10 - 24 Intermetallic Compounds Mg 2 Pb Adapted from Fig. 10.20, Callister & Rethwisch 4e. Note: intermetallic compound exists as a ____ on the diagram - not an ______ - because of stoichiometry (i.e. composition of a ___________ is a fixed value).
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Chapter 10 - 25 Eutectic, Eutectoid, & Peritectic Eutectic - liquid transforms to two solid phases L + (For Pb-Sn, 183ºC, 61.9 wt% Sn) cool heat _______ – one solid phase __________ to two other solid phases S 2 S 1 +S 3 + Fe 3 C (For Fe-C, 727 C, 0.76 wt% C) __________ compound - cementite cool heat cool heat ________ - liquid and one solid phase transform to a second solid phase S 1 + L S 2 + L (For Fe-C, 1493°C, 0.16 wt% C)
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Chapter 10 - 26 Eutectoid & Peritectic Cu-Zn Phase diagram Adapted from Fig. 10.21, Callister & Rethwisch 4e. ________transformation + ________transformation + L
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Chapter 10 - 27 Ceramic Phase Diagrams MgO-Al 2 O 3 diagram: Adapted from Fig. 10.24, Callister & Rethwisch 4e.
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Chapter 10 - 28 Iron-Carbon (Fe-C) Phase Diagram 2 important points - _________ (B): + Fe 3 C - ________ (A): L + Fe 3 C Adapted from Fig. 10.28, Callister & Rethwisch 4e. Fe 3 C (cementite) 1600 1400 1200 1000 800 600 400 0 1234566.7 L (austenite) +L+L +Fe 3 C + (Fe) C, wt% C 1148ºC T(ºC) 727ºC = T eutectoid 4.30 Result: _______ = alternating layers of and Fe 3 C phases 120 m (Adapted from Fig. 10.31, Callister & Rethwisch 4e.) 0.76 B A L+Fe 3 C Fe 3 C (cementite-hard) (ferrite-soft)
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Chapter 10 - 29 Fe 3 C (cementite) 1600 1400 1200 1000 800 600 400 0 1234566.7 L (austenite) +L+L + Fe 3 C L+Fe 3 C (Fe) C, wt% C 1148ºC T(ºC) 727ºC (Fe-C System) C0C0 0.76 Hypoeutectoid Steel Adapted from Fig. 10.34, Callister & Rethwisch 4e. __________ ferrite pearlite 100 m ______________ _____ pearlite Adapted from Figs. 10.28 and 10.33,Callister & Rethwisch 4e. (Fig. 10.28 adapted from Binary Alloy Phase Diagrams, 2nd ed., Vol. 1, T.B. Massalski (Ed.-in- Chief), ASM International, Materials Park, OH, 1990.)
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Chapter 10 - 30 Fe 3 C (cementite) 1600 1400 1200 1000 800 600 400 0 1234566.7 L (austenite) +L+L + Fe 3 C L+Fe 3 C (Fe) C, wt% C 1148ºC T(ºC) 727ºC (Fe-C System) C0C0 0.76 Hypoeutectoid Steel sr W = s/(r + s) W =(1 - W ) R S pearlite W pearlite = W W ’ = S/(R + S) W =(1 – W ’ ) Fe 3 C Adapted from Fig. 10.34, Callister & Rethwisch 4e. __________ ferrite pearlite 100 m _______________ ______ Adapted from Figs. 10.28 and 10.33,Callister & Rethwisch 4e. (Fig. 10.28 adapted from Binary Alloy Phase Diagrams, 2nd ed., Vol. 1, T.B. Massalski (Ed.-in- Chief), ASM International, Materials Park, OH, 1990.)
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Chapter 10 - 31 Hypereutectoid Steel Fe 3 C (cementite) 1600 1400 1200 1000 800 600 400 0 1234566.7 L (austenite) +L+L +Fe 3 C L+Fe 3 C (Fe) C, wt%C 1148ºC T(ºC) (Fe-C System) 0.76 C0C0 Fe 3 C Adapted from Fig. 10.37, Callister & Rethwisch 4e. _____________ Fe 3 C 60 m ________________ steel pearlite Adapted from Figs. 10.28 and 10.36,Callister & Rethwisch 4e. (Fig. 10.28 adapted from Binary Alloy Phase Diagrams, 2nd ed., Vol. 1, T.B. Massalski (Ed.-in- Chief), ASM International, Materials Park, OH, 1990.)
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Chapter 10 - 32 Fe 3 C (cementite) 1600 1400 1200 1000 800 600 400 0 1234566.7 L (austenite) +L+L +Fe 3 C L+Fe 3 C (Fe) C, wt%C 1148ºC T(ºC) Hypereutectoid Steel (Fe-C System) 0.76 C0C0 pearlite Fe 3 C x v VX W pearlite = W ______________ W =(1-W ) W =x/(v + x) Fe 3 C Adapted from Fig. 10.37, Callister & Rethwisch 4e. proeutectoid Fe 3 C 60 m Hypereutectoid steel pearlite Adapted from Figs. 10.28 and 10.36,Callister & Rethwisch 4e. (Fig. 10.28 adapted from Binary Alloy Phase Diagrams, 2nd ed., Vol. 1, T.B. Massalski (Ed.-in- Chief), ASM International, Materials Park, OH, 1990.)
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Chapter 10 - 33 Example Problem For a 99.6 wt% Fe-0.40 wt% C steel at a temperature just below the eutectoid, determine the following: a)The compositions of Fe 3 C and ferrite ( ). b)The amount of cementite (in grams) that forms in 100 g of steel. c)The amounts of pearlite and proeutectoid ferrite ( ) in the 100 g.
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Chapter 10 - 34 Solution to Example Problem a) Using the RS tie line just below the _____________ Fe 3 C (cementite) 1600 1400 1200 1000 800 600 400 0 1234566.7 L (austenite) +L+L + Fe 3 C L+Fe 3 C C, wt% C 1148ºC T(ºC) 727ºC C0C0 R S C Fe C 3 CC b)Using the ______ rule with the tie line shown C = ______ wt% C C Fe C = ____ wt% C 3 Amount of Fe 3 C in ______ g = (100 g)W Fe 3 C = (100 g)(0.057) = ____ ______
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Chapter 10 - 35 Solution to Example Problem (cont.) c) Using the VX tie line just above the eutectoid and realizing that C 0 = 0.40 wt% C C = 0.022 wt% C C pearlite = C = _______ wt% C Fe 3 C (cementite) 1600 1400 1200 1000 800 600 400 0 1234566.7 L (austenite) +L+L + Fe 3 C L+Fe 3 C C, wt% C 1148ºC T(ºC) 727ºC C0C0 V X CC CC Amount of pearlite in 100 g = (100 g)W pearlite = (100 g)(0.512) = _____
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Chapter 10 - VMSE: Interactive Phase Diagrams 36 Change alloy composition Microstructure, phase compositions, and phase fractions respond interactively
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Chapter 10 - 37 Alloying with Other Elements T eutectoid changes: Adapted from Fig. 10.38,Callister & Rethwisch 4e. (Fig. 10.38 from Edgar C. Bain, Functions of the Alloying Elements in Steel, American Society for Metals, 1939, p. 127.) T Eutectoid (°C) wt. % of alloying elements Ti Ni Mo Si W Cr Mn C eutectoid changes: Adapted from Fig. 10.39,Callister & Rethwisch 4e. (Fig. 10.39 from Edgar C. Bain, Functions of the Alloying Elements in Steel, American Society for Metals, 1939, p. 127.) wt. % of alloying elements C eutectoid (wt% C) Ni Ti Cr Si Mn W Mo
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Chapter 10 - 38 Phase diagrams are useful tools to determine: -- the number and types of phases present, -- the composition of each phase, -- and the weight fraction of each phase given the temperature and composition of the system. The microstructure of an alloy depends on -- its composition, and -- whether or not cooling rate allows for maintenance of equilibrium. Important phase diagram phase transformations include eutectic, eutectoid, and peritectic. Summary
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