1. Examen. Yolanda Elizabeth Zavala Ortega. Matemáticas III. C.E.A. III «A»

2. 1 2 3 4 5 6 7 8 9 10 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 43214321 -2 -3 -4 X Y A B C

4. d AB = √(2+7)² + (1-3)² d AB = √81 + 4 d AB = √85 d AB = 9.2 u d BC = √(4-2)² + (2-1)² d BC = √4 + 1 d BC = √5 d BC = 2.2 u d CA = √(-7-4)² + (3-2)² d CA = √121 + 1 d CA = √122 d CA = 11 u 1 2 3 4 5 6 7 8 9 10 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 43214321 -2 -3 -4 X Y A B C

5. Perímetro= 9.2 + 2.2 + 11 Perímetro= 22.4 u

6. 1 2 3 4 5 6 7 8 9 10 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 43214321 -2 -3 -4 X Y A B C ---------------------- -------- ---------------------- -------- D E F I II III

7. RECTÁNGULO d AE = √(-7+7)² + (1-3)² d AE = √4 d AE = 2 u d EF = √(4+7)² + (1-1)² d EF = √121 d EF = 11 u A= 11 x 2 A= 22 u² TRIÁNGULO I d AE = 2 U d EB = √(2+7)² + (1-1)² d EB = √81 d EB = 9 u A= (9x2)/2 A=9 u²

8. TRIÁNGULO II d BF = √(4-2)² + ](1-1)² d BF = √4 d BF = 2 u d FC = √(4-4)² + (2-1)² d FC = √1 d FC = 1 u A= (1x2)/2 A= 1 u² TRIÁNGULO III d DC = √(4-4)² + (2-3)² d DC = √1 d DC = 1 u d AD = 11 u A= (11x1)/2 A= 5.5 u²

9. 1 2 3 4 5 6 7 8 9 10 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 43214321 -2 -3 -4 X Y A B C 9 + 5.5 1 15.5 u²

11. 1-3 2+7 -2 9 2-1 4-2 1 2 3-2 -7-4 1 -11

12. < AB = 167.4° ) < BC = 26.5° ) < CA = 174.8° ) 1 2 3 4 5 6 7 8 9 10 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 43214321 -2 -3 -4 X Y A B C

14. (Y-3) = -2/9(X+7) (9) (Y-3)= -2X-14 9Y-27 = -2X-14 2X+9Y-10 = 0 (Y-1) = 1/2(X-2) (2) (Y-1)= X-2 2Y-2 = X-2 X-2Y = 0 (Y-2) = 1/-11 (X-4) (-11) (Y-2)= X-4 -11Y+22 = X-4 (-1)–X-11Y+26 = 0 X+11Y-26 = 0

15. 2X+9Y-10 = 0 9Y = -2+10 Y= -2X + 10 9 9 2X+9Y-10 = 0 2X+9Y=10 (/10) 2X + 9Y = 1 10 10 X-2Y = 0 -2Y = X Y= X -2 X-2Y = 0 X+11Y-26 = 0 11= -X+26 Y= -X + 26 11 11 X+11Y-26 = 0 X+11Y=26 (/26) X + 11Y = 1 26 26 Ecuación canónica Ecuación simétrica