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Ideal Gas Law & Gas Stoichiometry Work out each problem in the 3-step format. Gases notes #4 - Ideal Gas Law & Gas Stoichiometry.pptx
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After this lesson you will be able to: Solve problems involving the gas laws involving chemical reactions Apply stoichiometry principles in addition to gas laws Recognize which equations to apply in different types of problems involving gases
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QUESTION #1 How many grams of CO 2 are produced from 75 L of CO at 35°C and 96.2 kPa? 2CO + 1O 2 2CO 2
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Find the moles of CO: n = ? mol V = 75 L P = 96.2 kPa T = 35°C R = 0.08206 L atm/mol K Use: PV = nRT n = 2.818023828 mol CO 2CO + 1O 2 2CO 2 ? g 75 L, 35 °C, 96.2 kPa ANSWER #1, part 1 = 0.949654491 atm = 308 K
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ANSWER #1, part 2 Use stoichiometry: 2CO + 1O 2 2CO 2 2.818023828 mol ? g 2.818023828 mol CO 2 mol CO 2 2 mol CO 44.01 g CO 2 1 mol CO 2 = 120 g CO 2
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QUESTION #2 How many moles of oxygen will occupy a volume of 2.5 L at 1.2 atm and 25°C?
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ANSWER #2 n = ? V = 2.5 L P = 1.2 atm T = 25°C R = 0.08206 L atm/mol K Use: PV = nRT n = 0.12 mol = 298 K
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QUESTION #3 What volume will 56.0 grams of nitrogen gas occupy at 96.0 kPa and 21°C?
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ANSWER #3 V = ? n = 56.0 g P = 96.0 kPa T = 21°C R = 0.08206 L atm/mol K Use:PV = nRT V = 50.9 L = 1.998572448 mol = 0.947680157 atm = 294 K
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QUESTION #4 What volume of NH 3 at STP is produced if 25.0 g of N 2 is reacted with excess H 2 ? 1N 2 + 3H 2 2NH 3
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ANSWER #4 25.0 g N 2 1 mol N 2 28.02 g N 2 = 40.0 L NH 3 1 N 2 + 3 H 2 2 NH 3 2 mol NH 3 1 mol N 2 22.4 L NH 3 1 mol NH 3 25.0 g? L, STP Use stoichiometry: excess limiter
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QUESTION #5 What volume of hydrogen is produced from 25.0 g of water at 27°C and 1.16 atm? 2H 2 O 2H 2 + 1O 2
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ANSWER #5, part 1 25.0 g H 2 O 1 mol H 2 O 18.02 g H 2 O = 1.387347392 mol H 2 2 mol H 2 2 mol H 2 O 2H 2 O 2H 2 + 1O 2 25.0 g ? L, 27 C, 1.16 atm Use stoichiometry:
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ANSWER #5, part 2 Find the product volume: n = 1.387347392 mol V = ? P = 1.16 atm T = 27°C R = 0.08206 L atm/mol K Use: PV = nRT V = 29.4 L 2H 2 O 2H 2 + 1O 2 ? L, 27 C, 1.16 atm (= 1.387347392 mol) 25.0 g = 300 K
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QUESTION #6 How many atmospheres of pressure will be exerted by 25 g of CO 2 at 25°C and 0.500 L?
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ANSWER #6 P = ? n = 25 g T = 25°C V = 0.500 L R = 0.08206 L atm/mol K Use: PV = nRT P = 28 atm = 0.568057715 mol = 298 K
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QUESTION #7 How many grams of CaCO 3 are required to produce 45.0 L of CO 2 at 25°C and 2.3 atm? 1CaCO 3 + 2HCl 1CO 2 + 1H 2 O + 1CaCl 2
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ANSWER #7, part 1 Find the moles of product: n = ? V = 45.0 L P = 2.3 atm T = 25°C R = 0.08206 L atm/mol K Use: PV = nRT n = 4.232457181 mol ? g 45.0 L, 25 C, 2.3 atm 1 CaCO 3 + 2 HCl 1 CO 2 + 1 H 2 O + 1 CaCl 2 = 298 K
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ANSWER #7, part 2 4.232457181 mol CO 2 = 4.2 x 10 2 g CaCO 3 1 CaCO 3 + 2 HCl 1 CO 2 + 1 H 2 O + 1 CaCl 2 1 mol CaCO 3 1 mol CO 2 ? g 45.0 L, 25 C, 1 atm, 4.232457181 mol 100.09 g CaCO 3 1 mol CaCO 3 Use stoichiometry:
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QUESTION #8 Find the number of grams of CO 2 that exert a pressure of 785 torr at 32.5 L and 32°C.
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ANSWER #8 n = ? P = 785 torr V = 32.5 L T = 32°C R = 0.08206 L ⋅ atm / mol ⋅ K Use: PV = nRT n = 1.341244869 mol Convert using molar mass: = 59.0 g CO 2 = 1.032894737 atm = 305 K
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Tips for solving problems with gases: 1.Is there a chemical reaction happening? If yes, then write the balanced equation and use stoichiometry. 2.Are there changing conditions? If yes, then use the Everything Law (convert T to Kelvins). 3.No changing conditions? Use the Ideal Gas Law (convert all units to match R).
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