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Published byRuth Lane Modified over 8 years ago
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Distributive Property
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Mix Problems Homework
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Distributive Property
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A (B + C) = AB + AC 5 (x + 3) Multiple each value inside the parenthesis by 5 5 (X) + 5 (3) Add or subtract all like term 5x + 15 Because it is simplified this is your final answer
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Distributive Property A (B + C) = AB + AC -6 (y – 4) -6(y) + -6(-4) -6y + 24
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Distributive Property A (B + C) = AB + AC 7 (x – 3) 7(x) + 7(-3) 7x - 21
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Distributive Property A (B + C) = AB + AC 4 (7 + 3) 4(7) + 4(3) 28 + 12 40 OR 4 (7 + 3) Since same terms add what is in ( ) first 4 (10) 40
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Distributive Property A (B + C) = AB + AC (x – 3) 5 This is a Distributive Problem but number is on backside 5(x-3) Problem can be rewritten like this 5(x) + 5(-3) 5x - 15
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Distributive Property A (B + C) = AB + AC -(x – 7) -1(x – 7) Rewrite equation with a -1 -1(x) + -1(-7) -1x + 7
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Distributive Property Practice Problems 1. 8 (c + 4) 2. -5 (X + 2) 3. 3 (V – 3) 4. -2 (x – 7) 5. 4(3x + 7) 6. (x – 9) 3 7. -6 (-2x + 6) 8. 2 (-x + -1) 9 (7x + 4) (-3) 10. (x + 5) (x – 3)
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Distributive Property Practice Problems Answers
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