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ALGEBRAIC EXPRESSIONS AND PROPERTIES REVIEW. IDENTIFY THE PROPERTY 6 x 3 = 3 x 6 1.Associative 2.Commutative 3.Distributive 4.Algebra.

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Presentation on theme: "ALGEBRAIC EXPRESSIONS AND PROPERTIES REVIEW. IDENTIFY THE PROPERTY 6 x 3 = 3 x 6 1.Associative 2.Commutative 3.Distributive 4.Algebra."— Presentation transcript:

1 ALGEBRAIC EXPRESSIONS AND PROPERTIES REVIEW

2 IDENTIFY THE PROPERTY 6 x 3 = 3 x 6 1.Associative 2.Commutative 3.Distributive 4.Algebra

3 WRITE AN ALGEBRAIC EXPRESSION FOR “THE QUOTIENT OF w AND 4.

4 WHAT IS THE PERIMETER OF THE TRIANGLE SHOWN IN TERMS OF s. 1. 20s 2. 2s + 10 3. s 2 + 10 4. 12s

5 THE COMMUTATIVE PROPERTY STATES x + y = 1.xy 2.(x + y) 3.2 4.y + x

6 A TICKET TO THE BASKETBALL GAME COSTS s DOLLARS FOR A STUDENT. AN ADULT TICKET COSTS $5.00 MORE. FIND THE COST OF AN ADULT TICKET IN TERMS OF s. 1. s – 5 2. 5s 3. s + 5 4. 2s + 5

7 EVALUATE THE EXPRESSION 2s + 10 WHEN s = 7. 1. 37 2. 72 3. 24 4. 14

8 USE THE DISTRIBUTIVE PROPERTY TO EXPAND THE FOLLOWING EXPRESSION 7(t – 3) 1.7t – 3 2.7t – 21 3.t – 21 4.21

9 WRITE AN ALGEBRAIC EXPRESSION FOR: A NUMBER THAT IS 5 LESS THAN TWICE x 1. 2x - 5 2. x - 10 3. 5 – 2x 4. 10 - x

10 SIMPLIFY THE EXPRESSION 7k + 12 – 5k – 4 1. 12k + 8 2. 12k – 8 3. 2k + 16 4. 2k + 8

11 A LADY NEVER REVEALS HER AGE! MRS. O’DELL IS y YEARS OLD. MRS. WOJTOWICZ IS TWICE AS OLD AS MRS. O’DELL. HOW OLD IS MRS. WOJTOWICZ IN TERMS OF y?

12 SIMPLIFY THE EXPRESSION a + a + a + 25 - 12 1. 3a + 25 – 12 2. a + 16 3. 3a + 37 4. 3a + 13

13 IDENTIFY THE COEFFICIENT OF THE VARIABLE. 3a + 13 1. 13 2. a 3. 3 4. 16

14 1. 18 2. 16 3. 17 4. 11

15 USE THE DISTRIBUTIVE PROPERTY TO EXPAND THE FOLLOWING EXPRESSION. 8(2w – 9) 1.82w – 9 2.16w – 9 3.10w – 72 4.16w – 72

16 STATE WHETHER EACH PAIR OF EXPRESSIONS ARE EQUIVALENT. 3(x + 5) and 5(x + 3) 1. Equivalent 2. Not equivalent

17 WHICH OF THE FOLLOWING IS AN EXAMPLE OF THE ASSOCIATIVE PROPERTY? 1.4 + 3 = 3 + 4 2.(3 + 4) + 5 = 3 + (4 + 5) 3.3 x 45 = (3 x 40) + ( 3 x 5) 4.(3 + 5) + 4 = (3 x 4) + 5

18 1. 16 2. 10 3. 14 4. 3

19 THE PERIMETER OF THIS FIGURE CAN BE FOUND BY ADDING 4 + 7 + 4 + 7. WHICH IS ANOTHER WAY TO FIND THE PERIMETER USING THE DISTRIBUTIVE PROPERTY ? 4 7 1.4 x 7 2.2(4 + 7) 3.2 x 4 + 7 4.2 x 4 x 7

20 WHICH SHOWS HOW TO USE THE DISTRIBUTIVE PROPERTY TO MULTIPLY 8 X 64 1.8 + (60 + 4) 2.8 + (60 X 4) 3.8 X 60 + 4 4.8 X (60 + 4)


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