1. Algebra 1 Suppose you roll two number cubes. What is the probability that you will roll an odd number on the first cube and a multiple of 3 on the second cube? P(odd and multiple of 3) = P(odd) P(multiple of 3) The probability that you will roll an odd number on the first cube and a multiple of 3 on the second cube is. 1616 P(odd) = = 3636 1212 There are 3 odd numbers out of six numbers. P(multiple of 3) = = 2626 1313 There are 2 multiples of 3 out of 6 numbers. = 1212 1313 Substitute. = 1616 Simplify. Probability of Compound Events Lesson 2-7 Additional Examples

2. Algebra 1 Suppose you have 3 quarters and 5 dimes in your pocket. You take out one coin, and then put it back. Then you take out another coin. What is the probability that you take out a dime and then a quarter? Since you replace the first coin, the events are independent. The probability that you take out a dime and then a quarter is. 15 64 P(dime) =There are 5 out of 8 coins that are dimes. 5858 P(quarter) =There are 3 out of 8 coins that are quarters. 3838 P(dime and quarter) = P(dime) P(quarter) 15 64 = Multiply.= 5858 3838 Probability of Compound Events Lesson 2-7 Additional Examples

3. Algebra 1 Suppose you have 3 quarters and 5 dimes in your pocket. You take out one coin, but you do not put it back. Then you take out another coin. What is the probability of first taking out a dime and then a quarter? P(dime then quarter) = P(dime) P(quarter after dime) = 15 56 = 5858 3737 Multiply. The probability that you take out a dime and then a quarter is. 15 56 P(dime) =There are 5 out of 8 coins that are dimes. 5858 P(quarter after dime) =There are 3 out of 7 coins that are quarters. 3737 Probability of Compound Events Lesson 2-7 Additional Examples

4. Algebra 1 A teacher must select 2 students for a conference. The teacher randomly picks names from among 3 freshmen, 2 sophomores, 4 juniors, and 4 seniors. What is the probability that a junior and then a senior are chosen? P(junior then senior) = P(junior) P(senior after junior) The probability that the teacher will choose a junior then a senior is. 4 39 P(junior) =There are 4 juniors among 13 students. 4 13 P(senior after junior) = There are 4 seniors among 12 remaining students. 4 12 = 4 13 4 12 Substitute. = 16 156 4 39 Simplify. Probability of Compound Events Lesson 2-7 Additional Examples