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FTCE 5-9 Test Prep Center for Teaching and Learning.

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Presentation on theme: "FTCE 5-9 Test Prep Center for Teaching and Learning."— Presentation transcript:

1 FTCE 5-9 Test Prep Center for Teaching and Learning

2 Competency 1 Which item cost the least? $1.79 for 10 ounces $189 for 12 ounces $5.49 for 32 ounces

3 Competency 1 Which item cost the least? $1.79 for 10 ounces  $0.179 oz $1.89 for 12 ounces  $0.1575 oz $5.49 for 32 ounces  $0.172 oz Best buy is 12 ounces for $1.89

4 Competency 1 How much does an item cost that sells for $120 with a sales tax of 7%? How much is the tax?

5 Competency 1 How much does an item cost that sells for $120 with a sales tax of 7%? Cost of item with tax is $120 x 1.07 or $128.40 How much is the tax? Tax can be found by subtracting total cost from price of item. $128.40 - $120 = $8.40

6 Competency 1 Find the time from 11:34:22 AM until 2:28:40 pm

7 Competency 1 03:28:40 pm -11:34:22 am you see that you cannot subtract 34 minutes from 28 minutes Convert pm time to military time by adding 12 hours. Take one hour from 15 hours, change to 60 minutes and add to 28 minutes 15:28:40 pm -11:34:22 am 14:88:40 pm - 11:34:22 am 03:54:18 which is 3 hours, 54 minutes and 18 seconds

8 Competency 1 There are 100 coins in a jar. Ten are dimes, The rest are pennies and nickels. There are twice as many pennies as nickels. How many pennies and nickels are in the jar?

9 Competency 1 There are 100 coins in a jar. Ten are dimes, The rest are pennies and nickels. There are twice as many pennies as nickels. How many pennies and nickels are in the jar? What do you know? 100 coins Nickels, dimes, pennies 10 are dimes 90 are nickels and pennies Twice pennies than nickels

10 Competency 1 100 coins Nickels, dimes, pennies 10 are dimes 90 are nickels and pennies Twice pennies than nickels We can write this equation P + N = 90 We can also write P = 2N (twice pennies than nickels) Substitute: 2N + N = 90  3N = 90  N = 30 This means there are 30 nickels and 60 pennies

11 Competency 1 John subtracted 7 from his age and divided the difference by 3. The result was 4. What is John’s age?

12 Competency 1 John subtracted 7 from his age and divided the difference by 3. The result was 4. What is John’s age? What do we know?

13 Competency 1 Let John be X. X – 7  (he subtracted 7 from his age) (X – 7)/3  he divided by 3 (x – 7)/ 3 = 4  result was 4 Now solve the equation x – 7 = 12 x = 19 John is 19


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